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The speed ratio of car a and car B is 5:3, and they are facing each other. Car a runs 3 / 7 of the whole journey and 66 kilometers, just meeting car B, so as to find the full length
Suppose the total length is x km, three seventh x + 66 = five eighth x, x = 336
At the same time, the speed ratio is the distance ratio
3 / 7 and 66 km / 8 * 5
66 ÷ [5 / (5 + 3) - 3 / 7] = 210 (km)
A: the total length is 210 km
The speed ratio of car a and car B is 5:3. After two fifths of a's travel, car a runs another 18 kilometers, just meeting car B
A. B meet? Km
At the same time, the distance ratio is equal to the speed ratio
Let AB be x km apart
(5 / 2x + 18): (X-5 / 2x-18) = 5:3
The solution is: x = 80
A and B start from a and B at the same time, and run in opposite directions. After 5 hours of meeting, B runs 180 kilometers. If the speed ratio of a and B is 5:6, how many kilometers is the distance between a and B?
A: the distance between a and B is 330 km
How many hours does it take for a and B to meet each other at the same time?
It's better to solve the equation and write down every step clearly
Hello, somnus
It takes x hours for car a to complete the whole journey
1/x：（1/5－1/X）＝2：3
2/5－2/X＝3/X
0.4X－2＝3
0.4X＝5
X＝5÷0.4
X＝12.5
Let the speed of car a be 2x and that of car B be 3x
The whole course is 5 × (2x + 3x) = 25X
2 x / 12 x full travel time
If the speed of car a and car B is 2x and 3x respectively, and the total distance is y, then
(2x + 3x) * 5 = y is reduced to y = 25X
It takes y divided by the speed of a, which is 25X / 2x = 25 / 2, which is 25 / 2 hours
Let the speeds of a and B be 2x and 3x respectively
So according to s = VT
（2x+3x）×5=2xt
The solution is t = 12.5 hours
Let the velocity of a be V, then the velocity of B is 1.5V,
If the two vehicles meet each other for 5 hours, the total distance S = 5 × (V + 1.5V) = 12.5V
Therefore, it takes time for car a to complete the whole journey t = s / v = 12.5v/v = 12.5 (hours)
The speed ratio of a and B is 2:3. It is known that it takes 2 / 11 hours for car a to complete the whole journey. How many hours do the two cars meet on the way?
The speed ratio is 2:3,
Suppose that the whole course is 5 copies, when meeting a line of 2 copies
It takes 2 / 11 hours for a line of 5,
When they met, a was 2 / 11 × 2 / 5 = 4 / 55 (hours)
A: we will meet in two hours
2/11*2/5=4/55
The speed ratio is 2:3 and the distance ratio is 2:3
2 / 5 is the distance of meeting a, accounting for 2 / 5 of the total distance
Three points a (a, 0) B (0, b) C (4,1) are known to be collinear
If three points a (a, 0) B (0, b) C (4,1) are known to be collinear, where AB > 0, then the minimum value of a + B is 8, 7, 9 and 10 times of the four options
Choose 9, the line is x + 2Y = 6
Seven times and two
Root 9
If the equation [2k-1] [2K + 1] x + 3 = 0 of X is a linear equation of one variable, then the value of K is?
The equation of x [2k-1] X & # 178; - [2K + 1] x + 3 = 0 is a linear equation of one variable
therefore
2k-1=0
2k=1
k=1/2
Is there X in front?
I'm glad to answer for you. The 1900 team will answer for you
Please click the [select as satisfactory answer] button below,
Is (2k-1) x square - (2k + 1) x + 3 = 0
If it is;
Because it's one dollar a time
therefore
2k-1=0,
2K + 1 not = 0
So k = 0.5
Inequality of 3x-5 / 4 + 1 ≥ X-1 / 3 solution
It's a detailed process
Both sides of the inequality are multiplied by 12
3(3x-5) + 12 >= 4(x-1)
9x - 15 + 12 >= 4x - 4
5x >= -1
x >= -1/5
3x-5/4+1≥x-1/3
2x≥1/12
x≥1/24
14 out of 27 minus 8 out of 27 is equal to?
14/27-8/27=6/27=2/9
two-ninths
2/9
14/27-8/27=6/24=2/8
14/27-8/27=6/27=2/9
2/9
At both ends of the road 12km away, Party A and Party B face each other at the same time. The speed of Party A is 5km / h, and that of Party B is 3km / h,
There is a dog who starts from a and B again at 6 kilometers per hour. At the same time, he runs from a to B. on the way, he meets B and runs to A. when he meets a, he goes to B. He asks for the distance for the dog to run
The dog has been running, just take the time at the speed of the dog
Time is the time when Party A and Party B meet
T = 12 / (3 + 5) = 1.5 hours
So the dog ran 1.5 * 6 = 9 km
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