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A and B leave each other from a and B, and meet 2.5 hours later. When they meet, B travels 105 kilometers, and then continues to drive to B and a respectively Drive back at once. When you meet for the second time, car B is 90 kilometers away from A. find the distance between a and B
Is it true that Party A and Party B start from each other at the same time? If this is the case, let's set the whole journey as X. they walk three whole distances from starting to meeting. According to the drawing, if Party B walks x + 90, Party A walks 3x - (x + 90) = 2x-90
（2x-90）：（x+90）=（x-105）:105
x=225
A and B start from ab at the same time. A car runs 80 kilometers per hour, B car runs 10% of the whole journey per hour, and a car runs the whole journey again at 8 / 5 o'clock
Car a and car B start from a and B at the same time and travel in opposite directions. Car a travels 80 kilometers per hour, and car B travels 10% of the whole journey per hour. When car B reaches 8 / 5 of the whole journey, car a will travel 1 / 6 of the whole journey to reach place B. how many kilometers are there between a and B?
5 / 8 of the whole journey of B uses:
10 * 5 / 8 = 25 / 4 hours
In the next 25 / 4 hours, a drove the whole journey:
（1-1/6）=5/6,
Driving: 80 * 25 / 4 = 500km
So the length of the whole journey:
500 / (5 / 6) = 600 km
B has 5 / 8 of the whole journey, 5 / 8 ／ 10% = 25 / 4 hours, a has 25 / 4 hours, a has 80 * 25 / 4 = 500 km, which is 5 / 6 of the whole journey. Then the whole journey is: 500 ／ [5 / 6] = 600 km 2. Suppose the distance between the East and the west is XKM, 5 / 6x divided by 80 = 5 / 8 divided by 1 / 10x, and seize the time to solve 1 / 96x = 6.25 x = 600 a: the distance between the East and the west is 600 km
1. When the distance between the two cars is 128 km, car a has already made three quarters of the whole journey, and car B has made 65% of the whole journey. How many meters is the distance between the two places
B 1-65% = 35% from a
AB distance = 128 / (3 / 4-35%) = 320 km
2. The common part of the grassland and rose garden in a park is a pool. The known grassland area accounts for 4 / 5 of the square area, the rose garden area accounts for 5 / 8 of the garden area, and the grassland area is 14 times larger than the rose garden area
1. When the distance between the two cars is 128 km, car a has already made three quarters of the whole journey, and car B has made 65% of the whole journey. How many meters is the distance between the two places
B 1-65% = 35% from a
AB distance = 128 / (3 / 4-35%) = 320 km
2. The common part of a park's Grassland and rose garden is a pool. The known grassland area accounts for 4 / 5 of the square area, and the rose garden area accounts for 5 / 8 of the garden area. Moreover, the grassland area is 140m2 larger than the rose garden area. How many square meters is the pool area?
It seems that the title is not clear
3. A and B set out at two opposite points of a circular runway (the two ends of a day's diameter) at the same time and go in opposite directions. They first meet at point C and meet for the second time at point D. It is known that C is 80 meters away from a and D is 60 meters away from B. how many meters is the perimeter of the circular runway
Party A and Party B met twice, a total of 1.5 perimeter
That's three semicircles long
The first encounter of class A is 80 meters, and the second encounter is 80 × 3 = 240 meters
Then semicircle length = 240-60 = 180 meters
Length of circular runway = 180 × 2 = 360 m
The answer is 600 km.
Time used: 5 / 8 * 10 (hours). During this time, Party A has driven 80km / h * 5 / 8 * 10h = 500km, which is 5 / 6 of the whole journey, so the whole journey is 600km
The speed ratio of car a and car B is 5:3. After 37 kilometers of the whole journey, car a runs 66 kilometers, just meeting car B. how many kilometers are there between car a and car B?
The speed ratio of car a and car B is 5:3, so the distance ratio is 5:3 when they meet. Therefore, car a takes 58% of the whole journey when they meet, and car a takes 66 km after 37 km of the whole journey just to meet car B, so the proportion of 66 km in the whole journey is 58-37 = 3556-2456 = 1156, so the total distance between a and B is 66 △ 1156 = 66 × 5611 = 336 (km) The distance between the two places is 336 kilometers
Given the equation (2k + 1) x * x-4kx + (k-1) = 0 about X, ask: what is the value of K, this equation is a linear equation of one variable? Find out the root of this equation
Be in a hurry
Given the equation (2k + 1) x * x-4kx + (k-1) = 0 about X, ask: what is the value of K, this equation is one variable linear equation? When we find out the value of the root. K of this equation, it is a quadratic equation with one variable and does not contain a linear term? Find the root of the equation
The linear equation of one variable has no X & # 178;
So the coefficient is 0
So 2K + 1 = 0
k=-1/2
This is 2x-3 / 2 = 0
x=3/4
If the system of inequalities 1 ＜ x ≤ 2x ＞ K has a solution, then the value range of K is ()
A. k＜2B. k≥2C. k＜1D. 1≤k＜2
Because the system of inequalities 1 ＜ x ≤ 2x ＞ K has a solution, according to the formula, as long as K is less than 2
What is 14 minus 2 / 7
Party A and Party B set out from a and B at the same time. Party A rode bicycles and Party B rode motorcycles and drove at a constant speed along the same route. After three hours, they met
It is known that B travels 90 kilometers more than a when they meet. After meeting, B arrives at a place in an hour. Ask a, what are the speed of B? How long does it take for B to arrive at B?
It can be seen that the distance of a driving for three hours and that of B driving for one hour are three times faster than that of A
So let a speed be x km / h and B speed be 3 x km / h
There are (3 + 1) * 3x = 3x + 90 + 3x
The solution is x = 15,
So the speed of a is 15 km / h
B's speed is 15 * 3 = 45 km / h
After meeting, a is 45 * 3 = 135 km away from B, and it takes 135 △ 15 = 9 hours
It can be seen that the distance of a driving for three hours and that of B driving for one hour are three times faster than that of A
So let a speed be x km / h and B speed be 3 x km / h
There are (3 + 1) * 3x = 3x + 90 + 3x
The solution is x = 15,
So the speed of a is 15 km / h
B's speed is 15 * 3 = 45 km / h
After meeting, a is 45 * 3 = 135 km away from B, and it will take 135 △ 15 = 9 hours to expand
It can be seen that the distance of a driving for three hours and that of B driving for one hour are three times faster than that of A
So let a speed be x km / h and B speed be 3 x km / h
There are (3 + 1) * 3x = 3x + 90 + 3x
The solution is x = 15,
So the speed of a is 15 km / h
B's speed is 15 * 3 = 45 km / h
After meeting, a is 45 * 3 = 135 kilometers away from B, and it takes 135 △ 15 = 9 hours to put it away
Let the velocity of a be x and the velocity of B be y
According to the meaning of the question, we can get the equation
3y-3x=90
y=3x
The solution is as follows
x=15km/h
y=45km/h
It can be seen that a can reach B in 9 hours after meeting
A 15, B 45, a 9b hours
Suppose that the speed of a is x km / h, the formula containing x can be used to express the distance that a and B passed before they met
A-3xkm, B - (3x + 90) km.
At this point, we will go back to consider the speed of B: because B has also passed three hours, the speed of B is (3x + 90) / 3 = x + 30
It can be seen from the equation that: (x + 30) × 1 = 3x
X = 15 (km / h)
B's speed is: x + 30 = 15 + 30 = 45 (km / h)
That is, the speed of a's driving
Suppose that the speed of a is x km / h, the formula containing x can be used to express the distance that a and B passed before they met
A-3xkm, B - (3x + 90) km.
At this point, we will go back to consider the speed of B: because B has also passed three hours, the speed of B is (3x + 90) / 3 = x + 30
It can be seen from the equation that: (x + 30) × 1 = 3x
X = 15 (km / h)
B's speed is: x + 30 = 15 + 30 = 45 (km / h)
That is, the speed of a is 15 km / h, and that of B is 45 km / h.
A is 45 * 3 = 135 km away from B, and it takes 135 △ 15 = 9 hours to put it away
Let the velocity of a be x and the velocity of B be y
According to the meaning of the question, we can get the equation
3y-3x=90
y=3x
The solution is as follows
x=15km/h
y=45km/h
It can be seen that a can reach B in 9 hours after meeting
If (K + 3) x ^ 2 + 4kx-2k = 0 is a linear equation of one variable, then the solution of k = () equation?
∵ (K + 3) x & sup2; + 4kx-2k = 0 is a linear equation with one variable x
∴k+3=0
∴k=-3
Solving the system of inequalities 3 ≤ 3 (7x-6) ≤ 6
3≤3（7x-6）≤6
1≤（7x-6）≤2
1+6≤7x≤2+6
7/7≤x≤8/7
1≤x≤8/7
3≤3（7x-6）≤6
1≤7x-6≤2
7≤7x≤8
1≤x≤8/7
Seven
What is 14 out of 27 minus two out of seven?
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