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A and B start from a and B at the same time, and run in opposite directions. After 5 hours of meeting, B runs 180 kilometers. If the speed ratio of a and B is 5:6, how many kilometers is the distance between a and B?
A: the distance between a and B is 330 km
A and B start from a and B at the same time, and run in opposite directions. After 5 hours of meeting, B runs 180 kilometers. If the speed ratio of a and B is 5:6, how many kilometers is the distance between a and B?
A: the distance between a and B is 330 km
A and B start from a and B at the same time, and run in opposite directions. After 5 hours of meeting, B runs 180 kilometers. If the speed ratio of a and B is 5:6, how many kilometers is the distance between a and B?
A: the distance between a and B is 330 km
At both ends of the straight road 12 kilometers away, Party A and Party B set out at the same time and walked towards each other. The speed of Party A was 5 kilometers per hour, and that of Party B was 3 kilometers per hour. A dog ran from Party A to Party B at the speed of 6 kilometers per hour, met Party B on the way, and then returned to Party A at the original speed. After meeting Party A, it turned to Party B, so it ran back and forth between Party A and Party B, Until a and B meet, find the displacement and distance of the dog in the process
Encounter time = 12 ÷ (5 + 3) = 1.5 hours
Distance of dog = 1.5 × 6 = 9 km
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It seems that I haven't touched the physics problem for ten years. This is my first impression. The distance of the dog is equal to the speed of the dog multiplied by the time it takes for Party A and Party B to meet. The displacement should be equal to the distance of Party A. first calculate the time T1 = 12 / (5 + 3) = 1.5 hours, then the distance of the dog is equal to 1.5 * 6 = 9 km, and the displacement is equal to 1.5 * 5 = 7.5 km
It shouldn't be wrong. Let's take a look at the answers later. Mm-hmm
It seems that I haven't touched the physics problem for ten years. This is my first impression. The distance of the dog is equal to the speed of the dog multiplied by the time it takes for Party A and Party B to meet. The displacement should be equal to the distance of Party A. first calculate the time T1 = 12 / (5 + 3) = 1.5 hours, then the distance of the dog is equal to 1.5 * 6 = 9 km, and the displacement is equal to 1.5 * 5 = 7.5 km
It should not be wrong. Let's have a look at our answers later
If the equation (K + 2) x2 + 4kx-5k = 0 about X is a linear equation of one variable, then K=______ The solution X of the equation=______ .
According to the characteristics of one variable linear equation, we get K + 2 = 0, and the solution is k = - 2. Therefore, the original equation can be reduced to - 8x + 10 = 0, and the solution is x = 54
The speed ratio of the bus to the truck is 5:7. The last two cars meet at a distance of 30 kilometers from the midpoint. How many kilometers is the total length of a and B?
A: the total length of a and B is 360 km
What's 15 and 3 / 1 times 14 and 3 / 2
15 and 3 / 1 by 14 and 3 / 2
=(15+1/3)(15-1/3)
=15*15-1/3*1/3
=225-1/9
=224 8 / 9
Your answer should be 15 and one-third times 14 and two-thirds. The answer is 224 and eight nines
I calculated 2024 out of 9 with a calculator
At the two ends of the road 12km apart, a starts from east to west, and from west to East, two people start at the same time and travel in opposite directions. A's speed is 5km / h,
The speed of B is 3km / h. a dog runs from a to B at the speed of 6km / h. on the way, it meets B, that is, it runs in the opposite direction to A. after meeting a, it turns to B. in this way, it runs back and forth between a and B until a and B meet. In this process, the distance and displacement of the dog are calculated
The distance is 9km and the displacement is 7.5km
(k to the power of 2-1) (x to the power of k-1) + (K-2) X-8 = 0 is a linear equation of one variable with respect to x, x =?
(k to the power of 2-1) (x to the power of k-1) + (K-2) X-8 = 0 is a linear equation of one variable with respect to X
So the k-1 power of X is linear or constant
If the k-1 power of X is a linear term, then k = 2
It's 3x-8 = 0
x=8/3
If the k-1 power of X is constant, then k = 1
That's - X-8 = 0
x=-8
It should be k = 2. What's x about?
The distance between a and B is 480 km. The bus and the freight car start from a and B at the same time and run in opposite directions. The bus runs 1 / 6 of the whole journey per hour, and the freight car runs 1 / 8 of the whole journey per hour. How many hours after the two cars start to meet?
We can meet each other after 7 / 24 hours. V passenger is equal to 1 / 6 × 480 = 80 km / h, V cargo is equal to 1 / 8 × 480 = 60 km / h, and time t = 480 / (80 + 60) = 24 / 7 hours. We can also regard the whole journey as 1, V passenger = 1 / 6, V cargo = 1 / 8, and we can also calculate time t = 1 (1 / 6 + 1 / 8) = 24 / 7 hours
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