There are 360 workers in a factory, among which the number of female workers is 40 less than 3 times of that of male workers. How many are there in this factory?

There are 360 workers in a factory, among which the number of female workers is 40 less than 3 times of that of male workers. How many are there in this factory?

Suppose there are x male workers, then the number of female workers is (3x-40). According to the meaning of the question, x + (3x-40) = 360, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 4x = 360 + 40, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 4x = 400, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; A: there are 100 male workers and 260 female workers in this factory
There are 360 workers in a workshop, including 140 men and two fifths women. How many women are there in this workshop?
I only think of a kind of assumption that female = x Male = y
x+y=360
Quarter x + two fifths y = 140
You can do it yourself
There were 400 workers in a factory, of which male workers accounted for 3 / 8 of the total number. Later, a group of female workers were transferred, and now female workers account for 3 / 5 of the total number
How many female employees are there now?
Arithmetic method:
400 × (3 / 8) × (1-3 / 5) × (3 / 5) = 225 (persons)
Now there are 225 female workers
The two of them rode bicycles from two places to each other. The whole journey took six hours. When they met, the distance was 3:2, which was 18 times more than that of B,
And then up there
How many kilometers per hour did you travel?
13: You have to work it out for me before 00
When two people meet, the distance ratio is 3:2, and the speed ratio is 3:2
The time ratio of the two trains in the whole journey is 1 / 3:1 / 2 = 2:3
B car complete the whole journey = 6 * 3 / 2 = 9 hours
Then the encounter time = 1 ÷ (1 / 6 + 1 / 9) = 3.6 hours
Then the speed difference between the two vehicles is 18 △ 3.6 = 5km / h
Speed of vehicle B = 5 △ (3-2) × 2 = 10 km / h
When two people meet, the distance ratio is 3:2, and the speed ratio is 3:2
The time ratio of the two trains in the whole journey is 1 / 3:1 / 2 = 2:3
B car complete the whole journey = 6 * 3 / 2 = 9 hours
Then the encounter time = 1 ÷ (1 / 6 + 1 / 9) = 3.6 hours
Then the speed difference between the two vehicles is 18 △ 3.6 = 5km / h
Speed of vehicle B = 5 △ (3-2) × 2 = 10 km / h
Party A and Party B jointly transport a batch of goods, and received a total freight of 1800 yuan. The carrying capacity of Party A is 8 tons, which has been transported three times. The carrying capacity of Party B is 5 tons, which has been transported three times
6 times. Reasonable distribution of freight. How much is the freight for each vehicle?
1800÷﹙8×3＋5×6﹚=100／3
The freight of car a is 100 / 3 × 24 = 800 yuan
The freight of car B is 100 / 3 × 30 = 1000 yuan
A = 1800 * (3 * 8 / (3 * 8 + 5 * 6)) = 1800 * (24 / 54) = 800 yuan;
B = 1000-1800 yuan;
Car a = 1800 / (3 * 8 + 5 * 6) * (3 * 8)
=1800/54*24
=800
Car B = 1800 / (3 * 8 + 5 * 6) * (5 * 6)
=1800/54*30
=1000
The quality of goods transported by two trucks is 8 * 3 + 5 * 6 = 54 (tons); the total freight is 1800 yuan, and the freight per ton is 1800 yuan / 54 tons = 33.33333 yuan / ton.
Car a: 8 * 3 * 1800 / (8 * 3 + 5 * 6)=
Car B: 5 * 6 * 1800 / (8 * 3 + 5 * 6)=
The ratio of a to B is 8 × 3:5 × 6 = 24:30
Jiade 1800 × 24 / (24 + 30) = 800 yuan
B: 1800 × 30 / (24 + 30) = 1000 yuan or 1800-800 = 1000 yuan
A and B leave from ab. when a runs three seventh of the whole journey, B runs 42 kilometers
When car a arrives at place B, car B runs seven tenths of the whole journey. How many kilometers is the distance between the two places?
3/7x7/10=3/10
Distance 42 △ 3 / 10 = 140 km
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Two thirds of the number a is equal to five sixths of the number B. the sum of the two numbers a and B is 162. What are the numbers a and B?
A: B
=5/6：2/3
=5：4
A = 162 △ (5 + 4) × 5 = 90
B = 162-90 = 72
Party A and Party B go from a'B to a'B at the same time. They meet on the way in four hours. At this time, Party A takes 40% of the whole journey. After meeting, they continue to move forward at the same speed. When Party B arrives at city a, how many parts of the whole journey does Party A have to take to get to city a?
A took 40% of the whole course, B took 60% of the whole course,
So their speed ratio: 3:2
So the distance ratio at the same time is 2:3
When B walked the whole journey: a walked 2 / 3
Suppose the length of the whole journey is 1, then when we meet, a walks four tenths of the way. If it takes four hours, his speed is ten one per hour, and B's speed is six tenths divided by four, which is three twentieth. Then the time for B to complete the whole journey is: 1 (distance) divided by three twentieth (speed of B) = the time for B to complete the whole journey. This time is also the time for a to reach half of the length. Multiply one tenth of a's speed by this time, and the number is two-thirds. That is to say, a still needs one-third of the whole journey to get to city A.
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Suppose the length of the whole journey is 1, then when we meet, a walks four tenths of the way. If it takes four hours, his speed is ten one per hour, and B's speed is six tenths divided by four, which is three twentieth. Then the time for B to complete the whole journey is: 1 (distance) divided by three twentieth (speed of B) = the time for B to complete the whole journey. This time is also the time for a to reach half of the length. Multiply one tenth of a's speed by this time, and the number is two-thirds. That is to say, a still needs one-third of the whole journey to get to city A.
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How many meters is the length of a 10 ton truck? How many meters is the safe distance of this truck? Urgent!
Article 43 of the road traffic safety law of the people's Republic of China stipulates that for a motor vehicle driving in the same lane, the rear vehicle shall keep a safe distance enough to take emergency braking measures from the front vehicle. The relevant person of the traffic management department explained that when the speed of the motor vehicle is 60 km / h, the driving distance should be more than 60 m; when the speed is 80 km / h, the distance between the two vehicles should be more than 60 M, In case of rain, fog, water or ice on the road, the driving distance should be extended
A car manufacturer holds different opinions on the safe distance. With the aging of the vehicle and the wear and tear of the wheels, the braking distance will be correspondingly extended. This does not include the time when the foot moves from the accelerator to the brake pedal. The manufacturer believes that when the speed is 60 km, the distance between the vehicles should be at least 80 meters; when the speed is 80 km, the distance should be at least 100 meters
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Article 80 of the regulations for the implementation of the road traffic safety law of the people's Republic of China stipulates that when a motor vehicle runs on an expressway at a speed of more than 100 kilometers per hour, it shall keep a distance of more than 100 meters from the vehicle in front of the same lane. When the speed is less than 100 kilometers per hour, the distance from the vehicle in front of the same lane can be appropriately shortened, but the minimum distance shall not be less than 50 meters
A and B depart from a and B at the same time. When a runs 5 / 7 of the whole journey, B runs 72 kilometers; when a arrives at B, B runs the whole journey
How many kilometers is the distance between AB and 7 / 10 of the distance?
When car a runs 5 / 7 of the whole journey, car B runs 5 / 7 of the whole journey
5/7x7/10=1/2
The distance between the two places is 72 △ 1 / 2 = 144 km
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The distance between the two places is x km
X：7X/10=5X/7：72
72X=7X/10*(5X/7)
72X=(X^2)*5/10
72=X/2
X=144
The distance between AB and ab is 144 km. Can the equation not be used? When car a arrives at B, car B runs 7 / 10 of the whole journey. The speed of car a is 10 / 7 times that of car B.
When a runs 5 / 7 of the whole journey, B runs (5 / 7) / (10 / 7) of the whole journey
72 △ [(5 / 7) /... Expanded
The distance between the two places is x km
X：7X/10=5X/7：72
72X=7X/10*(5X/7)
72X=(X^2)*5/10
72=X/2
X=144
The distance between AB and ab is 144 km?