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A total of 320 tons of coal are planted in the two piles. The weight of pile a is 60% of that of pile B. how many tons of coal are the two piles?
After the children think more about the topic, they can come up with it. I thought I was asked by Baidu in those years. Gaga, I'm in grade one now. It's so easy to do this kind of topic
Now I'll tell you the answer
320 / (1 + 0.6) = 200 (tons) a 320-200 = 120 (tons)
Want an equation?
Suppose B is x tons and a is 60% x tons
X+60%X=320
X=200
A320-200 = 120 (tons)
Three hours later, car a runs 3 / 8 of the whole journey, car B runs 60% of the whole journey, and () is close to the destination
A, B, B, C can't be sure
That's 60% versus 3 / 8
60％=3/5
3/5＞3/8
So 60% is more than 3 / 8
So car B is close to the destination
60% > 3 / 8, so car B is close to the destination
There are 120 tons of cement in the warehouse, all 3% of which were transported in the first time, 87.5% in the second time, and 87.5% in the second time
There are 120 tons of cement in the warehouse. The first time we transported all 3 tons of cement, the second time we transported 87.5% of the first time. How many tons of cement were transported in the second time?
The first time: 120 * 1 / 3 = 40 tons
The second time: 40 * 87.5% = 35 tons
Party A and Party B start from a and B at the same time by bicycle, and face each other. The meeting point is 320 meters away from the midpoint. It is known that the speed of Party A is 5 / 6 of that of Party B, and each line of Party A is 800 meters,
OK, how many minutes did a and B meet?
It is known that the speed of a is 5 / 6 of that of B, and a is 800 meters per line
So the speed of B is 800 △ 5 / 6 = 960 M / min
If the meeting point is 320 meters away from the midpoint, then B is 320 × 2 = 640 meters more than a (draw a picture)
They spend the same time, and the distance difference is proportional to the speed difference,
So time = distance difference △ speed difference = 640 ÷ (960-800) = 4 minutes
OK, four minutes later, they met
Party A and Party B are more than two fifths of each book
Let a be X
Then 2x / 5 = (300-x) / 4 + 55
2X/5=75- X/4 +55
8X/20 + 5X/20=130
13X/20=130
X=200
So the number a is 200 and the number B is 100
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20. Number a and number B are natural numbers. If 5 / 6 of number a is exactly 1 / 4 of number B, then number a and number B are 300 kilometers away from 68. A and B. There are two bookshelves of car a and B, with a total of 3000 books,
|A + B = 300
|2 / 5 * A-1 / 4 * b = 55
A = 200
B = 100
Let a be x, then B be 300-x
So, 2 / 5x-1 / 4 (300-x) = 55
So, x = 200, 300-x = 100
The number B is 200, that is 100
Car a and car B leave from a and B which are 420 kilometers apart at the same time. Five hours later, car a runs 34 times and car B runs 23 times. How many kilometers are there at this time?
420 × (34 + 23-1), = 420 × (1712-1), = 420 × 512, = 175 (km); a: the distance between the two cars is 175 km
There are 240 tons of cement in the warehouse, 30% of which were transported in the first time. The second time, as much as the first time, how many tons of cement are left in the warehouse?
240x (1-30% - 30%) = 96 (tons)
The speed of a is 56 times that of B, and a travels 800 meters per minute. Find the distance between a and B
A: the distance between a and B is 7040 meters
Urgent, a and B two piles of coal a total of 300 tons, a pile of 2 / 5 than B pile of 1 / 4 more than 55 tons, two piles of coal each how many tons?
1. Two fifths of reactor a is 55 tons more than one fourth of reactor B
55 / 25% = 220 tons
160% of reactor a is 220 tons more than 100% of reactor B
2. (220 + 300) / (1 + 160%) = 200 tons
300-200 = 100 tons
There are 200 tons in pile a and 100 tons in pile B
A and B travel from a and B, which are 420 kilometers apart. In five hours, car a takes three-quarters of the whole journey, and car B takes two-thirds of the whole journey
Car a and car B travel from a and B which are 420 kilometers apart. In 5 hours, car a takes 3 / 4 of the whole journey and car B takes 2 / 3 of the whole journey. How many kilometers are the two cars apart? We need to solve the problem, not answer it!
420 × 3 / 4 + 420 × 2 / 3 - 420
=420 × (3 / 4 + 2 / 3 - 1)
=420 × 5 / 12
=175 (km)
A: the two cars are 175 kilometers apart
At this time, a's distance is 420 * 0.75 = 335km
B's distance is 420 * 2 / 3 = 280 km
The total distance between the two vehicles is 420 km. The two vehicles meet on the way, so the distance between the two vehicles is 335 + 280-420 = 195 km
When I was 5 hours old, car a was 3 / 4 of the whole journey, which means that car a was 1 / 4 away from ground B; similarly, car B was 2 / 3 of the whole journey, which means that car B was 1 / 3 away from ground a, so there was 1-1 / 4-1 / 3 = 5 / 12 between the two cars
400 * (1-1 / 4-1 / 3) = 420 * 5 / 12 = 175 km
420 times three quarters minus 420 times (1 minus two thirds) is the answer. 420 times three fourths is the distance between a and the starting point, and 420 times (1 minus two thirds) is the distance between B and a. Subtracting two numbers is the distance between them.
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