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A batch of cement has to be transported by car. In the first time, one-third less than 5 tons of the total cement has been transported. In the second time, one-quarter more than 3 tons of the total cement has been transported. There are 27 tons left. How many tons of this batch of cement?
The total quantity of cement is x tons
x-27=(x/3)-5+(x/4)+3
The solution
x=60、
I hope I can help you=
60 tons
Let the total amount be x tons
Then: (x / 3-5) + (x / 4 + 3) = x-27
Calculate x = 60
1. A car has traveled 45% of the whole journey from place a to place B. It is still 110 kilometers away from place B. how many kilometers is the highway between place a and place B?
2. For a bucket of paint, 2 / 5 of the total amount is used for the first time, and 1 / 4 of the total amount is used for the second time. A total of 26 kg is used for the two times. How many kg is this bucket of paint?
3. In September last year, the fructose produced by one kind of food was 15 / 4 less than that of milk sugar. The kilogram of fructose produced by one kind of food was 4 / 5 of that of milk sugar. How many kilogram of each kind of sugar?
Here you are!
110/(1-0.45)=200km
26/(0.4+0.25)=40kg
3.75 / (1-0.8) = 18.75kg, so milk sugar is 18.75kg, fructose is 18.75 * 0.8 = 15kg
The two piles of coal a and B weigh 44 tons in total. One fifth of them are transported from pile A. after 10 tons are transported from pile B, the two piles of coal are now the same weight. How many tons of coal was there in pile a
Analysis: 10 tons from B is just equal to 4 / 5 of a, then add a is 4 / 5 + 1
A: (10 + 44) / (1-1 / 5 + 1) = 30 (tons)
A x, B y.
4/5x=y-10 ①
x+y=44 ②
For example, by substituting (1) x = 5 / 4 (Y-10) into (2), we can get y. Then you can know X
Suppose a had x tons
B has 44-x
X-1/5X=44-X+10
X=30
1-1/5=4/5
B is 10 tons less than 4 / 5 of A
A: (44 + 10) / (1 + 4 / 5) = 30 tons international trade building to carry out the spring shopping prize sales activities, with 1000 lottery tickets as a large group, the prizes are set as follows: 1 special prize, the prize value is 200 yuan; 20 second prize, the value is 100 yuan; 60 third prize, the prize value is 50 yuan. (1) What is the total amount of prizes for each group in this prize sales activity? The winning rate of this prize winning sales activity
1-1/5=4/5
B is 10 tons less than 4 / 5 of A
A: (44 + 10) / (1 + 4 / 5) = 30 tons ﹣ follow up: Guomao building carries out the spring shopping prize sales activities, with 1000 lottery tickets as a large group, the prizes are set as follows: 1 special prize, the prize value is 200 yuan; 20 second prizes, the prize value is 100 yuan; 60 third prizes, the prize value is 50 yuan. (1) What is the total amount of prizes for each group in this prize sales activity? (formula) (2) find out the winning rate of this award-winning sales activity (formula)
10. There are two trains running from 770 km away. The speed of train a is 45 km / h, and that of train B is 41 km / h
10. There are two trains running from 770 km away. The speed of car a is 45 km / h, and that of car B is 41 km / h. car B starts for 2 hours, and car a runs () hours before meeting car B.
There are two trains running from 770 km away. The speed of car a is 45 km / h, and that of car B is 41 km / h. car B starts for 2 hours, and car a runs for (8) hours before meeting car B
(770-41 × 2) / (45 + 41) = 8 hours
You are a student?
The answer to this question is that car a will meet car B after 8 hours.
The calculation is as follows:
Set the time to X
Then (45 + 41) * x + 2 * 41 = 770
The solution is x = 8
Hope to help you.
O(∩_ Thank you
(770-41*2)/(41+45)
（770-41*2）/(41+45)=8 h
One third of the cement transported by car is less than 5 tons in the first time. The second time, one fourth of the cement transported by car is more than 3 tons. There are 27 tons left. How many tons are transported in the first time
All = (27-5 + 3) / (1-1 / 3-1 / 4) = 60 tons
First time = 60 × 1 / 3-5 = 15 tons
One third of the cement transported by car is less than 5 tons in the first time. The second time, one fourth of the cement transported by car is more than 3 tons. There are 27 tons left. How many tons are transported in the first time
All = (27-5 + 3) / (1-1 / 3-1 / 4) = 60 tons
First time = 60 × 1 / 3-5 = 15 tons
A car from a to B, two hours 180 kilometers, just two-thirds of the whole line. At this speed, how many hours to complete the whole line?
After traveling 180 km in 2 hours, we can see that its speed is 90 km / h
The whole journey is 180 * 3 / 2 = 270, so it takes 270 / 90 = 3 hours to complete the whole journey
Two thirds of 180 equals 180, three thirds of two equals 270 kilometers
The total distance = 180 divided by 2 / 3 = 270 km
Speed v = s / T = 180 / 2 = 90 km / h
The speed remains the same
Driving time t = s / v = 270 / 90 = 3 hours
The weight of pile a accounts for three eleventh of the total weight. If pile a transports 4 tons of coal to pile B, the weight ratio of pile a and pile B is 2:3?
After transporting 4 tons to B, a accounts for 2 / (2 + 3) = 2 / 5 of the total
Total weight: 4 ÷ (2 / 5-3 / 10) = 40 tons
Halo is 3 / 11
Total weight: 4 ÷ (2 / 5-3 / 11) = 220 / 7 tons
The title is wrong
Class a accounted for 3 / 11
The weight ratio of a and B is 2:3
Then a battle 2 / (2 + 3) = 2 / 5
But 3 / 11
The two trains a and B leave each other from the two cities at the same time. When car a travels 36 kilometers less than car B, the two trains are 264 kilometers apart. Given that the speed ratio of car a and B is 5:6, how many kilometers are the two cities apart
Let B travel for X kilometers, then a travel for (x-36) kilometers. From the meaning of the title, we can get that: X − 36x = 56 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 6x-216 = 5x & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 216216 × 2-36 + 264 = 660 (kilometers). A: the two cities are 660 kilometers apart
One batch of cement was transported by car. The first time, one third less than 5 tons were transported. The second time, 25% more than 3 tons were transported. There are 27 tons left. How many tons of this batch of cement
Sixty
How much speed can a car drive from a to B in one hour? (answer with proportional knowledge)
If you drive for another x hours, you can get: 13:1.2 = (1-13): X, & nbsp; & nbsp; & nbsp; 13X = 1.2 × 23, & nbsp; & nbsp; 13X = 0.8, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 2.4
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