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The transport team went to the warehouse to transport cement. On the first day, 15% of the total cement was transported out, and on the second day, 36 tons of cement was transported in. At this time, the cement in the warehouse was 87.5% of the original. How many tons of the original cement in the warehouse?
36 (15 + 87.5% - 1) = 36 (20% + 87.5% - 1) = 36 (7.5%) = 36 (0.075) = 480 (tons); answer: 480 tons of original cement in the warehouse
There are two piles of coal, pile a and pile B. the mass of pile a is 1.5 times that of pile B. If 125 kg is added to pile B, the mass of the two piles of coal will be equal. How many kg are there in each pile?
125 ÷ (1.5-1) = 125 ÷ 0.5 = 250 (kg) 250 × 1.5 = 375 (kg) a: there were 375 kg of coal in pile a and 250 kg of coal in pile B
B car to catch up with the speed of 1249 kilometers per hour
100×9-60×9
A speed: 60km / h = 50 / 3m / S
B speed: 100km / h = 250 / 9m / S
9 seconds before two cars meet: 9x (250 / 9-50 / 3) = 100m
A: nine seconds before car B overtakes car a, the two cars are 100 meters apart
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A speed: 60km / h = 50 / 3m / S
B speed: 100km / h = 250 / 9m / S
9 seconds before two cars meet: 9x (250 / 9-50 / 3) = 100m
A: nine seconds before car B overtakes car a, the two cars are 100 meters apart
If you don't understand, please continue to ask.
If you agree with my answer, please click the "adopt as satisfactory answer" button in time
Friends who ask questions from mobile phones can click "satisfied" in the upper right corner of the client. Ask: can we not use scores
The transport team went to the warehouse to transport cement. On the first day, 15% of the total cement was transported out, and on the second day, 36 tons of cement was transported in. At this time, the cement in the warehouse was 87.5% of the original. How many tons of the original cement in the warehouse?
36 (15 + 87.5% - 1) = 36 (20% + 87.5% - 1) = 36 (7.5%) = 36 (0.075) = 480 (tons); answer: 480 tons of original cement in the warehouse
If the mass of coal in pile a is one sixth less than that in pile B, the following statements are incorrect: (a) the mass of coal in pile B is 20% more than that in pile a
B. The mass ratio of pile a and pile B is 6:7
C. If 1 / 12 of pile B is taken out to pile a, the quality of the two piles of coal will be the same
D. Pile a accounts for 5 / 11 of the total coal mass of the two piles
Because the mass of coal in pile a is one sixth less than that in pile B, so a = (1-1 / 6) × B, that is, a = 5 / 6 B
A: B = 5:6
A = 5 ÷ (5 + 6) = 5 / 11
Choose D
B
If the mass of coal in pile a is one sixth less than that in pile B, the following statements are incorrect: (b)
Start from a and drive at a speed of 60 km / h. After half an hour, B will start from a and drive at a speed of 80 km / h. set B as X hours
1. The algebraic expression of X is used to represent the distance between vehicle a and vehicle B when vehicle B runs for X hours
Distance between vehicle a and ground a = 60 * (x + 0.5) = 60 * x + 30
Distance between vehicle B and ground a = 80 * x
The transport team went to the warehouse to transport cement. One fifth of the total cement was transported out on the first day, and 30 tons of cement was transported in on the second day. The total cement transported out on the two days was 45% of the total
How many tons of cement are shipped out
The next day: 45% - 1 / 5 = 0.45-0.2 = 0.25 = 1 / 4
That is to say, 30 tons is 1 / 4 of the total, so there is a total of cement 30 △ 1 / 4 = = 120 tons
On the first day, 120 × 1 / 5 = 24 tons were transported
Hello!
From the meaning of the question, we can see that 45% - 1 / 5 = 1 / 4 of the total was transported the next day
So the total is 30 △ 1 / 4 = 120 (tons)
So the first day is 120 × 1 / 5 = 24 (tons)
A: 24 tons of cement were transported out on the first day.
Thank you
If the mass of coal in pile a is 1 / 6 less than that in pile B, then the following statement is correct
1. The mass of pile B is 1 / 5 more than that of pile A. 2. The mass ratio of pile a and pile B is 6:7. 3. If 1 / 12 is taken from pile B to pile a, the mass of the two piles of coal will be the same. 4. Pile a accounts for 5 / 11 of the total mass of the two piles of coal
1,3,4
A. B is 100 km apart, a's speed is 20 km / h in a, B's speed is 30 km / h in B
1. A starts an hour before B starts. They start from each other. How many hours after a starts, they meet?
2. They set out at the same time and go in the same direction. A is in the front and B is in the back. How many hours does B catch up with a?
3. One hour after a's departure, B's departure. The two people walk in opposite directions. A few hours after a's departure, they are 200 kilometers apart?
4. Party A and Party B set out at the same time and walked towards each other. After a few hours, they were 20 kilometers apart?
5. Party A and Party B set out at the same time, facing each other, returning to places B and a respectively. When they meet again, how far is it from place a?
Today, please
1: 20x 30x = 100.2: 20x 100 = 30x.3: 20 100 20x 30x = 200.4: 20x 20 30 × = 100.5: 20x 30 × = 300
1, t = (100-20 * 1) / (20 + 30) = 1.6 hours
2 30 * t = 20 * t + 100, t = 10 hours
3 (200-100-20 * 1) / 50 = 1.6 hours
4 （ 100-20）/50=1.6
When they met again, they walked a total of 300 km, 300 / 50 = 6 hours, 100 - (6-5) * 20 = 80 km. Thank you, but I want the one yuan equation method, 1 100-20 × 1 = 80... To expand
1, t = (100-20 * 1) / (20 + 30) = 1.6 hours
2 30 * t = 20 * t + 100, t = 10 hours
3 (200-100-20 * 1) / 50 = 1.6 hours
4 （ 100-20）/50=1.6
When they met again, they walked 300 km, 300 / 50 = 6 hours, 100 - (6-5) * 20 = 80 km
There are 360 tons of cement in a batch, 1 / 4 of the total transported in the first time and 1 / 6 of the total transported in the second time. How many tons are there in two times? How many tons are left?
360×（1/4+1/6）
=360×1/4+360×1/6
=90+60
=150
360-150=210
A: two times, 150 tons in total, 210 tons left
360x1/4=90 360x1/6=60 90+60=150
360-150=210
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