For two piles of coal, a quarter of them are transported from pile a, and the remaining three fifths are transported from pile B. This is three fifths of the weight of pile a and pile B. the original weight of pile a is 120 tons. How many tons are there in pile B?

For two piles of coal, a quarter of them are transported from pile a, and the remaining three fifths are transported from pile B. This is three fifths of the weight of pile a and pile B. the original weight of pile a is 120 tons. How many tons are there in pile B?

120×（1-1/4）
=120×3/4
=90 tons
90 ﹣ 3 / 5 ﹣ 3 / 5 = 250 tons
The original capacity of reactor a B is 250 tons
B pile of coal to carry away part of the remaining three fifths??? Good chaos
120×（1-1/4）÷3/5
=90÷3/5
=150 tons
Let B have X tons
120-120*1/4=3/5X
90=3/5X
X=90 *5/3=150
So reactor B has 150 tons
Party A has transported 1 / 4 and 3 / 4, that is, 3 / 4 × 120 = 90 tons
Let B be x, 2 / 5 and 3 / 5x
Namely: 90 = 3 / 5 (3 / 5x) = 9 / 25X
X = 250 tons
A and B drive from a to B at the same time. When a completes 50% of the whole journey, B is 54 kilometers away from B. when a arrives at B, B runs 80% of the whole journey
Let AB be x km
When a completes 50% of the whole journey, B is 54 kilometers away from B
When car a completes the whole journey, car B runs 80% of the whole journey
So there's an equation
80%x=2(x-54)
0.8x=2x-108
1.2x=108
x=90
So the distance is 90 kilometers
For a pile of coal, 25% of the total coal was transported in the first time, and 35% of the total coal was transported in the second time. A total of 55.2 tons were transported in two times. How many tons of coal was originally transported in this pile?
Original = 55.2 ÷ (25% + 35%) = 92 tons
25% + 20% = 45% 90 * 45% = 200 tons
There are two piles of coal. Pile a accounts for 40% of the total weight of the two piles of coal. Now 26 tons of coal are transported from pile a and 48 tons from pile B. at this time, pile a is 4 tons less than pile B. how many tons of coal are there in the two piles?
Suppose the total weight of the two piles of coal is x tons, from the Title Meaning: 40% x-26 + 4 = (1-40%) x-48, & nbsp; & nbsp; 40% x-22 = 60% x-48, & nbsp; & nbsp; & nbsp; & nbsp; 20% x = 26, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 130; a: there are 130 tons of coal in the two piles
A. B is 420 kilometers away from the two places. A and B travel from a to B at the same time. A travels 80 kilometers per hour, B travels 60 kilometers per hour
Come on, let's do the math. Hurry!
What are you asking for?
The time of a use? 420 / 80 = 5.25 hours
Time used by B? 420 / 60 = 7 hours
How many hours more than a
How many minutes does B use more than a? 60 * 1.75 = 105 minutes
For a pile of coal, 25% of it is transported in the first time, 50% in the second time, and the rest in the third time
For a pile of coal, 25% was transported in the first time, 50% in the second time, and the remaining 20% in the third time. How many tons of coal are there?
40 ÷ (1-20%) / (1-25% - 50%) = 200 tons
40 times 5 equals 200, 200 times 2 equals 400, 400 times 4 equals 1600
The quality ratio of chemical fertilizer in warehouse A and warehouse B was 12:11. Later, 24 tons of chemical fertilizer were transported to warehouse B. at this time, the chemical fertilizer in warehouse A was less than that in warehouse B. 19. How many tons of chemical fertilizer were stored in warehouse B?
24 △ 1 (1-19) - 1112] × 1112 = 24 △ 89-1112] × 1112, = 24 △ 98-1112] × 1112, = 24 △ 524 × 1112, = 105.6 tons. A: the original warehouse B is 105.6 tons
A and B drive from a to B at the same time. Car a travels 60 kilometers per hour, car B travels 80 kilometers per hour, and car a goes ahead for half an hour
If car a travels 60 * 0.5 = 30 km in half an hour, if car B catches up with car a in X hours, there will be 80x = 30 + 60x, x = 1.5 (hours), so car B starts to catch up with car a in 1.5 hours
For a pile of coal, one eighth of the total amount will be used in the first time, and 75% of the total amount will be used in the second time. There are still 20 tons left. How many tons of the original pile of coal
Original = 20 (1-75% - 1 / 8) = 160 tons
The quality ratio of the two warehouses was 12:11. Later, 24 tons of chemical fertilizer were transported to warehouse B. at this time, the chemical fertilizer in warehouse A was 1 / 9 less than that in warehouse B. how much chemical fertilizer was stored in warehouse B?
How to calculate without equation?
A has not changed. Consider a as unit 1
It turns out that B belongs to a
11÷12＝11/12
Now B is a
1÷（1－1/9）＝9/8
Jiayou
24 (9 / 8-11 / 12) = 57.6 (tons)
B: Yes
57.6 × 11 / 12 = 52.8 (T)