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A pile of cement was transported to a construction site. It took 15% of the total on the first day, 25% on the second day, 15 tons on the third day, and 7 tons left. How many tons of this batch of cement were used?
(15 + 7) △ 1-15-25%) = 22 △ 1120 = 40 tons a: this pile of cement is 40 tons
The weight of the two piles of coal is equal. Now 40 tons of coal are transported from a and 8 tons from B. at this time, B is three times as much as a. how many tons of coal were there in the two piles
Let the weight of coal be X
Then 3 * (x-40) = x + 8
So we have 3x-120 = x + 8
So 2x = 128
x=64
A: there used to be 64 tons of coal in each pile
If B is three times that of a, then B is two times more than A. if a carries 40 tons of coal and B carries 8 tons, then B is 40 + 8 = 48 tons more than a
Now B is 48 / 2 × 3 = 72
A is 48 △ 2 × 1 = 24
Originally, 24 + 40 = 64 or 72-8 = 64
The number of apples in box a is twice that of box B. If three apples are taken out of box a and put into Box B, the number of apples in box a and Box B is the same. How many apples are there in box a and Box B?
The number of apples in Box B is 3 + 3 = 6
The number of a apple is 6 × 2 = 12
There are 6 of 12 apples in each box
Box B, 12
The number of apples in box a is x, while that in box a is 2x
2x-3=x+3
X=6
2x =2*6=12
A: there are 6 apples in box a and 12 apples in box B.
Equations are easier to understand.
Suppose Box B has x apples, then box a has 2x apples
2X-3=X+3
2X-X=3+3
X=6
2x6 = 12
There are 12 apples in box a and 6 apples in box B.
A construction site needs 12 tons of cement. One quarter of the total cement is transported in the first day, and one fourth of the total cement is transported in the second day. How many more tons of cement are needed?
This is a math problem, ask you to answer, I believe you are smart people, please, best let me know how to do, so I can understand, hope speed, tonight! Thank you!
This is a sixth grade math problem, I do out is 6 tons, but the answer is not very sure, there may be other answers, please give enough data, let me learn the real knowledge!
A quarter of the total on the first day
Day 1: 12x1 / 4 = 3 (tons)
A quarter of a ton arrived the next day
Still need to transport: 12-3-1 / 4 = 8.75 (ton)
One quarter of the total amount transported in the first day is 3 tons, and one quarter of the total amount transported in the second day is 3 tons, so there is still 6 tons to go
On the first day, 12x1 / 4 = 3
The next day 1 / 4
3.25 tons in two days
The difference is 12-3.25 = 8.75 tons
The total cost is 12 tons. One quarter of the first day's shipment is 12 / 4. Similarly, the next day's shipment is 12 / 4
Then the cement needed is 12-12 / 4-12 / 4 = 6 (tons)
12 - 12 × & # 188; - # 188; = 8 & # 190; (eight and three fourths).
We still need to transport 8 tons.
Answer: the first time is a quarter of 12, which is 12 × a quarter of 3. The second time is a quarter of a ton. Note, it is a quarter of a ton, so it is 12-3-a quarter, which is eight and three quarters
First, what is the total? That's 12 tons in total. The first day is a quarter, that is, 12x1 / 4 = 3 (quarter). What about the next day? It's a quarter of a ton, not a quarter, so two days total 3 + 1 / 4 = 13 / 4 (three and a quarter), then the rest of the total amount minus two days of 12-13 / 4 = 33 / 4 (eight and a quarter).
Formula: 12 - (12x1 / 4) - 1 / 4 = 33 / 4 (ton)... Expansion
First, what is the total? That's 12 tons in total. The first day is a quarter, that is, 12x1 / 4 = 3 (quarter). What about the next day? It's a quarter of a ton, not a quarter, so two days total 3 + 1 / 4 = 13 / 4 (three and a quarter), then the rest of the total amount minus two days of 12-13 / 4 = 33 / 4 (eight and a quarter).
Formula: 12 - (12x1 / 4) - 1 / 4 = 33 / 4 (ton) Stow
The original tonnage ratio of a and B piles of coal is 5:3. If 900 tons are transported from a pile and put into B pile, then the tonnage of the two piles is equal. How many tons does a and B pile have? Use the proportion solution
Suppose a had x tons, B had 3 / 5x tons
x-900=3/5x+900
2/5x=1800
x=4500
3 / 5x = 4500 × 3 / 5 = 2700 tons
A used to be 4500 tons, B used to be 2700 tons
Suppose a has x tons
x：（x－900×2）＝5：3
x＝4500
B: 4500-900 × 2 = 2700 tons
A used to be 4500 tons, B used to be 2700 tons.
X / y = 5 / 3, x-900 = y + 900, x = 4500, y = 2700, 4500 tons for a and 2700 tons for B
A Y B x
y/x=5﹕3
y-900/x+900=1
y=4500
x=2700
The ratio of the number of apples in box a and Box B is 5:2. If five apples are taken out of box a and put into Box B, the ratio of apples in box a and Box B is 9:5, how many apples are there in two boxes? [idea Click: after taking 5 apples out of box a, the ratio of the total number of apples in box a to the total number of apples in two boxes also decreased accordingly
A: there are 70 apples in two boxes
The construction site needs 120 tons of cement. One quarter of the total cement is transported in the first day, and two fifths in the second day. How many more tons are transported in the second day than in the first day
120*(2/5)-120*(1/4)
=48-30
=18
A: the next day is 18 tons more than the first
.
The original tonnage ratio of a and B piles of coal is 5:3. If 90 tons are transported from a pile to B pile, then the tonnage of the two piles is equal. How many tons are there in a and B piles?
Suppose that there are x tons of coal in pile a. x-90 = 35x + 9025x = 180X = 450; coal in pile B: 450 × 35 = 270 (tons); answer: there are 450 tons of coal in pile a and 270 tons of coal in pile B
There are 100 oranges in box a and 80 oranges in box B. how many oranges are taken out of box a and put into Box B? The ratio between box a and Box B is 7:11?
100 - (100 + 80) × 77 + 11, = 100-180 × 718, = 100-70, = 30 (pieces). A: take out 30 oranges from box a and put them in box B. the ratio of box a and Box B is 7:11
There is a batch of cement on the construction site. 7200 kg is used for the first time, 3 / 4 more than the second time,
There is a batch of cement on the construction site. 7200 kg was used for the first time, 3 / 4 more tons than the second time. The remaining cement is 0.8 tons more than the sum of the previous two times. How many tons of cement are there in this pile?
Second use: 7200-3 / 4 = 7199.25 tons
The sum of the first two times: 7200 + 7199.25 = 14399.25 tons
Remaining: 14399.25 + 0.8 = 14400.05 tons
Total: 14400.05 + 14399.25 = 28799.3 tons
Suppose the original cement x tons, then: X-2 (7.2 * 2-0.75) = 0.8, the solution is x = 28.1, so the original cement is 28.1 tons
RELATED INFORMATIONS
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