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After two fifths of a pile of coal was used, 56 tons of coal was transported in. Now it's 30% more than before. How many tons of coal do you want?
The original 56 (2 / 5 + 30%) = 56 (7 / 10) = 80 tons
56 △ [30% + 2 / 5] = 80 tons, there were 80 tons.
Three seventh of the mass of coal in pile a is equal to two times that of coal in pile B. what is the mass ratio of coal in pile a and pile B
How many points is volleyball more than basketball? How many points is volleyball less than volleyball
No one will?
A: B = 2:3 / 7
=2*3/7
=14：3
A / b = 14 / 3
Car a and car B started from 396 kilometers away and ran in opposite directions. Car a ran 64 kilometers per hour. On the way, car a stopped for 0.5 hours due to fault, and then continued to drive. Results car B met car a 4 hours after starting. The speed of car B was calculated
[396-64 × (4-0.5)] / 4, = [396-64 × 3.5] / 4, = 172 △ 4, = 43 (km / h); a: the speed of car B is 43 km / h
For a pile of coal, 56 tons will be transported in the first time, and 1 / 4 of the total will be transported in the second time. This is 2:3 of the ratio of the remaining tons to the transported tons. What is the original quantity of this pile of coal
56 ÷ [3 / (2 + 3) - 1 / 4)] = 160 (tons)
Transported = 3 ÷ (2 + 3) = 3 / 5
Total = 56 (3 / 5-1 / 4) = 160 tons
If 3 / 5 of number a is equal to 5 / 4 of number B, then number a is equal to number B. if the sum of number a and number B is 7.4, how much is each of number a and number B? Why
A * 3 / 5 = b * 5 / 4
A: B = 5 / 4:3 / 5
=（5/4）*20：（3/5）*20
=25：12
The ratio of a to B is equal to (25:12),
25+12=37
A = 7.4 * (25 / 37) = 5
B = 7.4 * (12 / 37) = 2.4
Car a and car B travel from a and B at the same time. Car a travels 80 kilometers per hour, while car B travels 60 kilometers per hour. When the two cars meet, it is 40 kilometers away from the midpoint of the whole journey. How long is the whole journey?
(40 × 2) △ 80-60) × (80 + 60), = 80 △ 20 × 140, = 4 × 140, = 560 (km), a: the whole journey is 560 km long
For a pile of coal, 20% of the total amount is transported in the first time, and 2 / 5 of the total amount is transported in the second time, which is exactly 90 tons. How many tons of this pile of coal?
90/（0.2+0.4）=150
There are two double digits of a and B. two seventh of a is equal to two-thirds of B. what is the biggest difference between a and B?
The ratio of a and B is 2 / 3 ∶ 2 / 7 = 7 ∶ 3
Since the maximum value of a is 7 × 14 = 98, the maximum value of B is 42, and the maximum difference is 56
Car a and car B travel from a and B at the same time. Car a travels 80 kilometers per hour, and car B travels 60 kilometers per hour
How many meters is the distance between a and B?
Incomplete
Five hundred and fifty-six
This question is incomplete and does not indicate the problem
A pile of coal uses 25% of the total amount for the first time and 6 tons for the second time. At this time, the ratio of the coal used to the rest is 2:3. How many tons of coal is there in this pile?
2 (2 + 3) = 2 / 5
Use the next day's total of 25-2 / 20
This pile of coal has a total of 6 / 3 / 20 = 40 tons
RELATED INFORMATIONS
- 1. For two piles of coal, a quarter of them are transported from pile a, and the remaining three fifths are transported from pile B. This is three fifths of the weight of pile a and pile B. the original weight of pile a is 120 tons. How many tons are there in pile B?
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