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Two cars a and B leave in the opposite direction at the same time. After two minutes and three hours, the distance between the two cars is 204 kilometers. The speed ratio of the two cars a and B is 8:9
(8x+9x)*1.5=204
Solve the equation, 8x is the speed of car a.
Speed sum of two vehicles: 204 △ 3 / 2 = 136 km / h
A's speed: 136 * 8 / 17 = 64 km / h
Speed of B: 136 * 9 / 17 = 72 km / h
A total of 960 tons of coal were transported twice, leaving 68 tons. It is known that one eighth of the total amount was transported in the first time, and what percentage was transported in the second time?
The second time
960-68-960*(1/8)=772
therefore
It's gone for the second time
772/960
=193/240
The coal in pile B is 2:45, and the weight of each pile is 52 tons?
The ratio of coal in pile a and pile B is 3: pile a is 15 tons less than pile B. how many tons of coal are there in pile a and pile B
The title is not clear. I can't help you. Please check it
The two vehicles of Party A and Party B drive in the opposite direction at the same time. After two minutes and three hours, the distance between the two vehicles is 204km. It is known that the speed ratio of Party A and Party B is 8:9,
Find the speed of car a
204*2/3=136(km)
136 * 8 / 17 = 64 km / h
One quarter of a ton of coal is used up, which is exactly one eighth of the coal. How many tons are left unused? How many more than the total
There are seven fourths of the tons left unused, and the rest is three-thirds more than what is used
The total weight of coal in pile a and pile B is 44 tons. When pile a uses 3-5 tons of coal and pile B uses 2-3 tons of coal, the remaining weight of the two piles of coal is equal?
No equations! It's OK to use ratio solutions
When 3-5 of coal is used in pile a and 2-3 of coal is used in pile B, the remaining weight of two piles of coal is equal
That is, (1-3 / 5) of pile a = (1-2 / 3) of pile B
A: B = 1 / 3:2 / 5 = 5:6
Original jiadui = 44 △ (6 + 5) × 5 = 20 tons
Pile B = 44-20 = 22 tons
The two cars leave from the midpoint of city a and city B in the opposite direction at the same time. Three hours later, the bus arrives at city A. the truck is 60 kilometers away from city B. the speed ratio of passenger and freight cars is 3:2. What is the distance between city a and city B?
3 + 2 + 1 = 6, 60 △ 16 = 60 × 6, = 360 km; a: the distance between city a and city B is 360 km
A pile of coal weighs two tons, one fourth of which is used, just one eighth. One and three fourths of which are left unused, leaving seven eighths of the total
correct
Quarter 2 = 1 / 8
1 and three fourths △ 2 = 7 / 4 △ 2 = 7 / 8
550Kg, that's it
1 / 4 △ 2 = 1 / 8 correct
2-1 / 4 = 1 and 3 / 4 tons
1-1/8=7/8
-----Absolutely right!
absolutely right
If you don't understand, you can ask
It's OK to change fractions into decimals. If it's a primary school problem, the answer is "correct.".
Yes!!!
The answer is right. 1 / 4T is just 1 / 8 * 2T. There are 1 and 3 / 4T left. The rest is 7 / 8 * 2T
2-1/4=7/8
There are 44 tons of coal in pile a and pile B, one fifth of which is transported from pile A. after 10 tons are transported from pile B, the two piles of coal are now the same weight. How many tons of coal was there in pile B
If the original x tons of pile B is set, then the original 44-x tons of pile a is 4 / 5 · (44-x) = x + 1035.2-0.8x = x + 1025.2 = 1.8x, and the solution is x = 14
There are two people, a and B. in the car, a finds that B walks in the opposite direction. After 40 seconds, B is twice as fast, but 0.8 times slower than the car. How long does it take for a to catch up with B
How long does it take for a to catch up with B
I think about it carefully: the solution is as follows
Let a's speed be x, B's speed be x / 2, car speed = x / 0.8 = 5x / 4
40 * (x / 2 + 5x / 4) / (x-x / 2) = 140 seconds
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