Party A and Party B transport a pile of coal together. Party A transports more than 25% of the total amount of coal, and Party B transports 50% of the total amount of coal. How many tons of coal are there?

Party A and Party B transport a pile of coal together. Party A transports more than 25% of the total amount of coal, and Party B transports 50% of the total amount of coal. How many tons of coal are there?

Car a transported more than 25% of the total number of 9 tons
Then car B transported more than 4.5 tons of 12.5% of the total
So the total amount of coal is
(9+4.5)÷(1-25%-12.5%)
=13.5÷0.625
=21.6 tons
A: there are 6.21 tons of coal
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A and B apples are 75 kg in total, and a gives B 5 kg, but a is still 7 kg more than B. So how many kg are there in a and B apples?
It turns out that a is more than B: 5 * 2 + 7 = 17 kg
It turns out that B has: (75-17) / 2 = 29 kg, and a has: (75 + 17) / 2 = 46 kg
(75-7-10) / 2 = 29, get jiakuang Apple 46 kg, B 29 kg
Because jiakuang gave Yikuang 5 kg, but jiakuang was still 7 kg more than Yikuang, so jiakuang was 5 - (- 7) = 12 kg more than Yikuang
And because a and B have a total of 75 kg of apples, let B have x kg of apples and a have X + 12 kg of apples
Jiedejiakuang Apple 46 kg, B 29 kg
There are two bags of cement a and B. the weight of bag a is 60 kg. After one third of bag a's cement is used, the remaining mass is equal to four fifths of bag B's cement
How many kilos
60*（2/3）=40
40/（4/5）=50
B = 50kg
A batch of coal is transported by a and B trucks. When the transportation is finished, a truck transports more than 25% of the total amount of 9 tons, and the tonnage transported by B is equivalent to 50% of that transported by A. how many tons of coal is this pile? (formula)
The proportion of a in the total number: 1 ÷ (1 + 50%) = 2 / 3
Total: 9 ÷ (2 / 3-25%) = 21.6 tons
The tonnage transported by a truck is: (25% of the total + 9 tons) / 2
This pile of coal is (9 + 9 / 2) (1-25% - 25% / 2) = 21.6 (tons)
A total of X tons
0.25x+9=2(x-0.25x-9)
0.25x+9=1.5x-18
1.25x=27
x=21.6
A: Yes....
There are 338 people in fire brigade a and B, 17 of whom are transferred to fire brigade a and 13 of whom are transferred to fire brigade B. a total of 78 people are transferred. How many people are there in fire brigade a and B?
Let a fire brigade have original x persons, then B fire brigade has original 338-x persons. According to the meaning of the question, we can get the equation: 17x + 13 (338-x) = 78, 3x + 7 (338-x) = 78 × 21, & nbsp; & nbsp; 3x + 2366-7x = 1638, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 4x = 728, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 182, then the original number of fire brigade B is 338-182 = 156
A and B are two bags of cement. A weighs 96 kg. Take 25% of it out of bag A. at this time, the cement in bag B is the remaining 75% of bag A. how many kg of cement is in bag B
A now has
96 × (1-25%) = 72 (kg)
B yes
72 × 75% = 54 (kg)
96 × (1-25%) × 75% = 54 (kg)
Car a and car B transport a batch of coal together. At the end of the transport, car a transport more than 25% of the total number of 9 tons, and car B transport 50% of the total number of tons. How many tons of this batch of coal?
Suppose there are x tons in total, we can get: X - (25% x + 9) = (25% x + 9) × 50%, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 75% X-9 = 0.125x + 4.5, 0.75x-0.125x = 13.5, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.625x = 13.5, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp
There are 338 people in fire brigade a and B, 17 of whom are transferred to fire brigade a and 13 of whom are transferred to fire brigade B. a total of 78 people are transferred. How many people are there in fire brigade a and B?
Let a fire brigade have original x persons, then B fire brigade has original 338-x persons. According to the meaning of the question, we can get the equation: 17x + 13 (338-x) = 78, 3x + 7 (338-x) = 78 × 21, & nbsp; & nbsp; 3x + 2366-7x = 1638, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 4x = 728, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 182, then the original number of fire brigade B is 338-182 = 156
Party A and Party B have 180 bags of cement in each warehouse. If 20 bags are taken from Party A's warehouse and put into the warehouse, three fifths of the total amount of cement in Party A's warehouse is equal to nine tenths of that in Party A's warehouse
How many bags of cement
Now the ratio of a to B is 9 / 10:3 / 5 = 3:2
So now a 180 × 3 ^ (3 + 2) = 108 bags
So the original a 108 + 20 = 128 bags
B 180-128 = 52 bags
Car a and car B transport a batch of coal together. At the end of the transport, car a transport more than 25% of the total number of 9 tons, and car B transport 50% of the total number of tons. How many tons of this batch of coal?
Suppose there are x tons in total, we can get: X - (25% x + 9) = (25% x + 9) × 50%, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 75% X-9 = 0.125x + 4.5, 0.75x-0.125x = 13.5, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.625x = 13.5, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp