For a pile of coal, one eighth of the total amount is used for the first time, and 20 tons are used for the second time. This is 75% of the total amount left. How many tons of coal was there originally?

For a pile of coal, one eighth of the total amount is used for the first time, and 20 tons are used for the second time. This is 75% of the total amount left. How many tons of coal was there originally?

Original = 20 (1-75% - 1 / 8) = 160 tons
There are 44 tons of coal in pile a and pile B. one fifth of the coal in pile a is transported and 10 tons in pile B. the two piles are the same weight. How many tons in pile B?
If there are x tons of coal in pile a, then there are (44-x) tons of coal in pile B
X-1/5X=44-X+10
4/5X+X=54
9/5X=54
X=30
A has 30, B has 14
The speed ratio of car a and car B is 6:5. They leave from a and B at the same time. When they meet, car a travels 240 kilometers, and how many kilometers does car B travel
Answer whatever you like. No bivariate linear equation
B = 240 × 5 km
B
240 △ 6X5 = 200 km
240/6*5=200
There is a pile of coal, 20 tons are used, and 75% of the total amount is left. How many tons of coal is there in this pile? (explain the process and why do you want to do this
75% left - 25% spent
That is: 20 tons, accounting for 25% of the total
So, total = 20 △ 25% = 80 (tons)
A: there used to be 80 tons of coal in this pile
Total number of media removed: 1-75% = 25%
So the total amount of coal is: 20 △ 25% = 80 tons
100/[100-75]=4
20 * 4 = 80 tons
Suppose that the pile of coal is x tons
(x-20)=x×75%
x-20=0.75x
0.25x=20
x=80
That is: this pile of coal was originally 80 tons
There is a pile of coal, 20 tons are used, and 75% of the total amount is left, so 1-75% = 25% is used
So 20 (1-75%) = 80
Two piles of coal a and B are 180t in total. Two fifths of the coal is transported from pile a and one tenth of the coal is transported from pile B. at this time, the remaining coal in the two piles is equal. How many tons of coal are left in pile a and pile B
 
A and B start from a and B at the same time, and run in opposite directions. After 5 hours of meeting, B runs 180 kilometers. If the speed ratio of a and B is 5:6, how many kilometers is the distance between a and B?
A: the distance between a and B is 330 km
There is a pile of coal, 20 tons are used, and 75% of the total amount is left. How many tons of coal is this pile?
The formula is important
20 / (1-0.75) = 80 (tons)
Set: a pile of coal x tons
X-20 = x times 75 percent
=80 tons
The total weight of pile a and pile B is 540 tons. The weight of pile a is four fifths of that of pile B. how many tons less is pile a than pile B?
To calculate the formula, steps, results
B: 540 (1 + 4 / 5) = 300 tons
A: 540-300 = 240 tons
Pile a is less than pile B: 300-240 = 60 tons
B = 540 (1 + 4 / 5) = 300 tons
Less = 300 - (540-300) = 60 tons
On the highway, cars a, B and C drive at a constant speed of 80, 70 and 50 kilometers per hour respectively. A drives from station a to station B, while B and C drive from station B to station a. a meets C two hours after meeting B, then the distance between station a and station B is shorter______ Km
Suppose the distance between station a and station B is x km. According to the meaning of the question, we get: X80 + 50-x80 + 70 = 2, the solution is x = 1950, so the answer is 1950
For a batch of cement, 30% of the total amount was transported in the first time, 8 tons more in the second time than in the first time, and 65% of the total amount was transported in the two times. How many tons of this batch of cement?
A: this batch of cement is 160 tons in total