How many tons of cement do you need to tow a pile of cement to B pile every time

How many tons of cement do you need to tow a pile of cement to B pile every time

Since the total amount is 120 tons, if pile B is twice as much as pile a, pile B is 80 tons, and pile a is 40 tons, then pile a needs to transport 60 tons. If it comes out five tons at a time, it will be 12 times
A batch of goods was transported 35% in the first time and 78 tons in the second time, which accounted for 65% of the total amount?
The total quantity of the goods is x tons
35%x+78=65%x
30%x=78
x=260
260 tons
78/(65%-35%)
Three cars of a, B and C carry a pile of coal. Car a carries 40% of the total, while car B carries 60% of car C,
It is known that car a carries 28 tons more than car B. how many tons of coal is this pile?
To detailed steps Oh, online and so on
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0.4x-28=0.6x*(60/160)
How did this 60 / 160 come about? What do you mean?
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The total quantity of coal is x tons
0.4x-28=0.6x*(60/160)
By solving the equation, we can get x = 160
Because the ratio of B to C is 60%: 1 = 6:10, B accounts for 6 / 16 of the total number of B and C
Let the total coal be a
40% by car a, 40% by car B, 40% by car A-28, 40% by car C (40% by car A-28) / 60%
The sum of three trucks is a pile of coal a
40%a+(40%a-28)+(40%a-28)/60%=a
(2+5/3)40%a-28(1+5/3)=a
[(2+5/3)40%-1]a=28(1+5/3)
a=160
This pile of coal amounts to 160 tons
Two cars are driving from a to B at the same time. The speed of a is 80 km / h, and that of B is 120 km / h. how many hours later are the two cars 100 km apart? At this time, car B is just half of the whole journey. What is the distance between a and B?
100÷(120-80)
=100÷40
=2.5 hours
120 × 2.5 × 2 = 600 km
One
100 ÷ (120-80) = 2.5 hours
Two
120 × 2.5 × 2 = 600 km
For a batch of goods, 143 tons were transported in the first time, 5 / 12 of the total in the second time, and 7 / 8 of the total in the two times. How many tons are there?
This batch of goods: 143 (7 / 8-5 / 12) = 312 tons
Car a, car B and car C transport a pile of coal. Car a transports 2 / 5 of the total tons, and car B transports 3 / 5 of car C. It is known that car a transports 28 tons more than car B,
How many tons of coal is this pile
Car C = (1-2 / 5) / (1 + 3 / 5) = 3 / 8
Car B = 1-2 / 5-3 / 8 = 9 / 40
Total = 28 (2 / 5-9 / 40) = 160 tons
(1-2 / 5) / (3 / 5 + 1) × 3 / 5 = 9 / 40
Total: 28 (2 / 5-9 / 40) = 160 tons
Total x tons
A: (2 / 5) * x
Car B: (2 / 5) * x-28
Car C: [(2 / 5) * x-28] / (3 / 5)
A + B + C = x
x=160
From city a to city B, a car can arrive at the speed of 120 km / h for 2 hours. After the whole race, the time ratio of a bus to a car is 5:4,
What's the speed of the car
It takes 35 minutes to saw a 4-meter-long piece of wood into 0.5-meter-long sections. According to this calculation, how many minutes does it take to saw it into 0.4-meter-long sections?
First: the distance from city a to city B: 120kmx2h = 240km
Bus time: 2x5 / 4 = 2.5h
The speed of the bus is 240km except 2.5h = 96km / h
The second method is that if the speed of the bus is x, the following results can be obtained
120×2=5/4×2X
The solution is: x = 96 km / h
The second question: each segment is 0.5m long, there are 8 segments need to be sawed 7 times. The time of each sawing is 5 minutes
Each segment is 0.4 m long, 10 segments need to be sawed 9 times, 5 minutes each time, 45 minutes
The rest of the goods will be transported in the second day. The first batch will be transported in the second day___ .
(1-37) × 58 + 37 = 47 × 58 + 37 = 514 + 37 = 1114 answer: 1114 of this batch of goods were transported twice
A, B, C two cars transported a batch of coal, a transported 40% of the total, B car transported 60% of C car, known as a
Car a, car B and car C carry a batch of coal. Car a carries 40% of the total amount, while car B carries 60% of car C. It is known that car a carries 28 tons more than car B. how many tons of coal are there in total?
160 tons
Let the total yield be x tons
A: 40% X
B: 40% x-28
C: x-40x - (40% x-28)
The equation is: 40% x-28 = (x-40% X - (40% x-28)) X60%
The distance between city a and city B is 120 km. If the speed of a car from city a to city B is increased to 1.2 times of the original speed, it will arrive 20 minutes ahead of time: how many kilometers per hour is the original speed of the car?
Suppose the original speed of the car is x kilometers per hour
120/X-120/1.2X=20/60
144-120 =1/3*1.2X
0.4X =24
X =60
The test shows that x = 60 is the solution of the original equation
A: the original speed of the car is 60 kilometers per hour
The following is the standard answer format.
20 minutes is a third of an hour.
Let the speed of the original car be x (km / h)
120÷x=120÷1.2x+1/3
120/x=100/x+1/3
120=100+x/3
x/3=20
x=60
It is proved that x = 60 is the solution of the original equation.
A: the original speed of the car was 60km / h.
1/1.2=5/6
5/6-1=1/6
20/1/6=120
120/120=1m
1*60=60m