A batch of goods were transported away for the first time and 78 tons for the second time, accounting for 65% of the total amount. How many tons of this batch of goods?

A batch of goods were transported away for the first time and 78 tons for the second time, accounting for 65% of the total amount. How many tons of this batch of goods?

A batch of goods were transported 26 tons in the first time and 78 tons in the second time, accounting for 65% of the total amount. How many tons of this batch of goods?
（26+78）÷65%
=104÷65%
=160 tons
（26+78）÷65%
=104÷65%
=160 tons
The three vehicles of a, B and C carry a pile of coal. Car a carries 40% of the total, while car B carries 60% of car C. It is known that car a carries 56 tons more than car B,
How many tons of coal is this?
1-40% = 60%
So B fainted by 60% × 60% / (1 + 60%) = 22.5%
So a total of 56 (60% - 22.5%) = 149 and one third of a ton
56/[40%-60%*(1+60%)]=1400
Suppose x tons in total, then a transports 0.4x, B transports 0.4x-56, C transports (0.4x-56) / 0.6, so a + B + C = x, and the solution is x = 320
A bus and a car drive from city a to city B at the speed of 100km and 120km per hour, respectively. The bus leaves city a one time earlier than the car, but two times later
How many kilometers is the distance between city a and city B?
If it takes x hours for a bus to go from city a to city B, it takes (x + 1) hours for a bus
According to the meaning: 120x = 100 (x + 1)
The solution is: x = 5
So: 120x = 120 * 5 = 600 (km)
A: A and B are 600 kilometers apart
Because the distance is equal to the speed times the time, and the distance of two cars is the same
100 × 1 = 100 km, 100 ÷ [120-100] = 5:00, 5 × 120 = 600 km
The original cement mass ratio of team a and team B is 4:3. After team a lent Team B 35 tons, the cement mass ratio of team a to team B is 3:4,
How many tons of cement does team a have?
Team a has x tons of cement, team B has 3 / 4x
(X-35)/(3/4X+35)=3/4
(X-35）*4=(3/4X+35）*3
X = 140 tons
There are three cars carrying a batch of coal. Car a carries 15% of the coal, car B 65% of the coal, and car C 20% of the coal. It is known that car a carries less coal than car B
Eight tons less, how many tons did car B transport?
Suppose there are x tons of coal in this batch
65%x--15%x =8
0.65x--0.15x =8
0.5x =8
X = 16 B: 16 x 65% = 10.4 (ton)
The two passenger cars run in the same direction at the same time from two places 60 kilometers apart. Car a is in the front and car B is in the back. Car B runs at a speed of 45 kilometers per hour and catches up at 8 o'clock
The two passenger cars run in the same direction at the same time from two places 60 kilometers apart. Car a is in the front and car B is in the back. Car B runs at a speed of 45 kilometers per hour and catches up at 8 o'clock
Set up a car to travel an average of X kilometers per hour
45- x = 60 ÷8
x = 37.5 km/h
Car a travels 37.5km per hour on average
Speed of car a = 45-60 △ 8
=45-7.5
=37.5 km / h
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(45X8-60)÷8=37.5
The speed of a is 37.5km/h
Let the speed of car a be x km / h
8×45-8x=60
8x=360-60
8x=300
x=37.5
So the added speed is 37.5 kilometers per hour
The original cement quality ratio of team a and team B is 4:3. After team a gives Team B 54 tons of cement, the cement quality ratio of team a and team B is 3:4. How many tons of cement does team a have
If a is the original x ton, B is 3x / 4 ton
(X-54)x4=(3X/4+54)x3
4X-216=9X/4+162
16X-864=9X+648
7X=1512
A x = 216 (T)
B = 216 △ 4 × 3 = 162 (T)
When transporting a pile of coal by car, car a needs to transport 10 times, car B needs to transport 12 times, and car C needs to transport 15 times
Now there are two piles of coal a and B. car a transports pile a and car B transports pile B. three cars start to transport coal at the same time. Car C helps car a transport coal first, then turns to help car B transport coal midway. Finally, the two piles of coal are transported at the same time. How many times has car C helped car a and car B transport coal respectively?
The quantity of coal in each pile is 1
So the total is 2
This process is equivalent to a, B and C work at the same time
The work efficiency of a and C is 1 / 15 + 1 / 12
It takes 2 / (1 / 4) = 8 hours to complete
Then a 8 hours to complete 1 / 10 × 8 = 4 / 5
A / C = 1 / 5
C help a (1 / 5) / (1 / 15) = 3 hours
C help B 8-3 = 5 hours
Car a and car B meet 8 hours after driving from the two places at the same time. Car a travels 60 kilometers per hour. The speed of car B is 1.2 times that of car A. how many kilometers are there between the two places
(60+60X1.2)X8=132X8=1056(KM)
The weight ratio of a and B is 4:3. When a transports 84 tons, the weight of a and B is 2:5. How many tons does a have?
B has 84 △ 4 / 3-2 / 5 = 84 △ 14 / 15 = 105
A: 105 * 4 / 3 = 140 tons