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There are two tons of coal in pile a and pile B, 24 tons in pile A. if one eighth of the coal in pile a is put into pile B, then the weight of two tons of coal is equal. How many tons of coal in pile B? The total weight of two barrels of oil is 10.8 kg. Pour a quarter of the oil out of the first barrel and put it into the second barrel for 3.2 kg. At this time, the two barrels of oil are equal in weight. How many kg are the first and second barrels? The weight of the remaining boxes is exactly 3 kg. How much is the weight of each box? It costs 300 yuan to buy 8 big blackboards and 12 small blackboards. One big blackboard costs 2.5 yuan more than two small blackboards. How much does each big blackboard cost?
Unit price of the first container (2.7 × 10-8.8 kg) = 2.5 × 10-21 kg (2.8 kg) = 2.8 × 10-8 kg
The ratio of the number of people in workshop a and workshop B is 5:4. If 21 people are transferred from workshop a to workshop B, then the ratio of the number of people in workshop a and workshop B is 2:3
There are x and y people in workshop a and workshop B, according to the meaning of the topic
x/y=5/4
(x-21)/(y+21)=2/3
The solution of the equations is: x = 75, y = 60
A: there were 75 or 60 people in workshop a and workshop B
Let a x B y
Then the ratio of X to y is 5 to 4
Then x-21 vs y + 21 = 2 vs 3
75 and 60
A 75, B 60
Let a be 5x and B be 4x at the beginning, then a be 5x-21 and B be 4x + 21
From the ratio of the number of people in the two workshops of a and B is 5:4, we can set a as 5K and B as 4K
There are 21 people transferred from a to B, and the ratio of a to B is 2:3
(5K-21)*3=（4K+21）*2
K=15
A is 5K = 75
B is 4K = 60
If the number of a is x and the number of B is y, then:
X/Y=5/4； （X-21）/（Y+21）=2/3。
By substituting 1 for x = 5 / 4Y into 2, we can get: (5 / 4y-21) / (y-21) = 2 / 3, the solution is y = 60, substituting 1 for x = 75.
There are 75 in a and 60 in B
Let a have 5x and B have 4x
（5X-21)/(4X+21)=2/3
That is, 5x-21 = (4x + 21) * 2 / 3
5X-21=8X/3+14
7X/3=35
Then x = 15
So a has 5 * 15 = 75, B has 4 * 15 = 60
To transport a batch of goods, it takes 10 days for team a to transport the goods alone, and 15 days for team B to transport the goods alone. The two teams transport the goods together for 2 days______ (fill in the score)
(110 + 115) × 2, = 16 × 2, = 13
There are two piles of coal. Pile a has 36 tons and pile B has 24 tons. How many tons are transported from pile a to pile B, and the weight of pile B is twice that of pile a? (answer with second grade knowledge)
(36+24)÷(2+1)=20
36-20=16
After transporting 16 tons from pile a to pile B, the weight of pile B is twice that of pile a
The ratio of people in workshop a and workshop B is 5:4. If 21 people are transferred from workshop a to workshop B, the ratio of people in workshop a and workshop B is 2:3
How many people were there in workshop a and workshop B
If the number of workshop a is x, the number of workshop B is 0.8x
(x-21)/(0.8x+21)=2/3
x=75
If the number of workshop a is 75, the number of workshop B is 60
The ratio of workshop a to workshop B is 5:4, which is 5 / 9 of the total number of workshop a
If 21 people are transferred from workshop a to workshop B, the ratio of the number of people in workshop a and workshop B is 2:3, which is 2 / 5 of the total number of people in workshop a
So there are 21 / (5 / 9-2 / 5) = 135 people in the two workshops
A: 135 * 5 / 9 = 75
B: 135-75 = 60
There are x persons in a and Y persons in B;
x/y=5/4;(x-21)/(y+21)=2/3
Solving equations
Let a workshop x B workshop y X / y = 5 / 4, then y = 4 / 5x (x-21) / (y + 21) = 2 / 3, then 3x-2y = 105, so 3x-2 (4 / 5x) = 105, x = 75, y = 60
Remember to adopt it
The transport team transported a batch of rice to the disaster area. In the morning, it took 4 trucks to transport 25, with an average of 20% per truck______ What about the rest of the rice______ The car can't be finished
How many parts of this batch of rice can be transported by each truck on average: 25 △ 4, = 25 × 14, = 110; how many trucks can the rest of the rice be transported by: (1-25) △ 110, = 35 △ 110, = 6 (trucks); a: 110 of this batch of rice can be transported by each truck on average, and the rest of the rice can be transported by 6 trucks
A pile of 8 tons of coal is transported in 5 times. How many parts of the pile are transported each time? How many tons are transported each time?
A pile of 8 tons of coal is transported in 5 times. How many parts of the pile are transported each time?
1÷5=1/5
How many tons per shipment?
8 △ 5 = 1.6 tons
1 / 5,8 / 5 ton
The ratio of people in workshop a and workshop B of Limin towel factory is 5:4. According to the needs of work, 21 people are transferred from workshop a to workshop B. at this time, the ratio of people in workshop a and workshop B is 2:3. How many people are there in workshop a and workshop B? (I want a formula, not an equation.)
Total number of people = 21 (5 / 9-2 / 5) = 135
Original workshop a = 135 (5 + 4) × 5 = 75 people
Workshop B = 135-75 = 60 people
If you understand and solve your problem,
A total of 21 △ [5 / (5 + 4) - 2 / (2 + 3)]
=21÷【5/9-2/5】
=21÷7/45
=135
A: 135 × 5 / (5 + 4) = 135 × 5 / 9 = 75
B = 4 × 135 (original) = 60 × 4 / 135
If there are 5x people in workshop a, then there are 4x people in workshop B
（5X-21）/(4X+21)=2/3
It can be seen from this
(5X-21)×3=(4X+21)×2
How to solve the equation
X=15。
If workshop B = 4x, workshop a = 60, workshop B = 75
At the station, there is a batch of goods, which can be transported by car a at 10:00 and by car B at 15:00. Now, when these two cars are used to transport 4:00 at the same time, how many parts of this batch of goods are left
To calculate by formula
1-4/10-4/15=1/3
1-（1/10+1/15）*4=1/3
1-(1/10+1/15) *4
=1-1/6 *4
=1/3
1-（1/10+1/15）*4=1/3
1-4×（1/10+1/15）=1/3
1-（1/10+1/15）*4=1/3
10X=15y
4x+4y=4x+4*1.5x=10x
It's just finished
1-[(1/15+1/10)x4]=1/3
If the total quantity of goods is a, Party A transports x every hour and Party B transports y every hour, then 10x = A and 15y = a
Then 4 (x + y) = 4 (A / 10 + A / 15) = 2 / 3a, A-2 / 3A = 1 / 3a
That is to say, there is still one third of the goods left.
A pile of 15 tons of coal is transported by truck in seven times. How many parts of the coal are transported each time? How many tons?
A pile of 15 tons of coal is transported by truck in seven times. How many parts of the coal are transported each time? How many tons?
One seventh of the coal is transported at a time
It's 15 * 1 / 7 = 15 / 7 tons
Hope to help you.
1/7 15/7
A pile of 15 tons of coal is transported by truck in seven times. How many parts of the coal are transported each time?
1/7
How many tons is it?
15 / 7 tons
Please accept, thank you. I'm sorry, the first one I saw was on the top
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