A total of 104.5 tons of goods were transported by the two vehicles, and the goods transported by the vehicle a were 0.5 tons less than that of the vehicle B. how many tons of goods were transported by the two vehicles? It's a lesson in volume two of grade five, four exercises, 92 pages

A total of 104.5 tons of goods were transported by the two vehicles, and the goods transported by the vehicle a were 0.5 tons less than that of the vehicle B. how many tons of goods were transported by the two vehicles? It's a lesson in volume two of grade five, four exercises, 92 pages

Set to X
Then a is 2x-0,5
So x + 2x-0.5 = 104.5
x=38
So a is 75.5, it's 38
There are 80 tons of coal in two piles. Two thirds of the coal is used in the first pile and two fifths in the second pile. The remaining coal in the two piles is five times less than that in the second pile
1、 How many tons of coal was there in the second pile?
If the first pile has x tons, the second pile has 80-x tons
According to the meaning of the title:
x/3+3(80-x)/5=4(80-x)/5
The solution is x = 30
So the second pile used to be 50 tons
Assuming that the first pile of coal is x and the second pile of coal is y, then
X+Y=80
Y-(X*1/3+Y*3/5)=Y*1/5
It is concluded that x = 30 tons, y = 50 tons
The second ton of coal used to be 50 tons.
Assuming that the first pile of coal is x and the second pile of coal is y, then
X+Y=80
Y-(X*1/3+Y*3/5)=Y*1/5
It is concluded that x = 30 tons, y = 50 tons
The second ton of coal used to be 50 tons.
A passenger car and a freight car are running from both sides of Party A and Party B at the same time, and they meet after 4 hours. If the passenger car runs for 3 hours and the freight car runs for 2 hours, and the two cars are separated by 30 / 11 of the whole journey, how long does it take for the passenger car to complete the whole journey? (use the formula)
30 / 11, 11 / 30? Should be written as 11 / 30
3-2 = 1 hour, 1-2 / 4-11 / 30 = 2 / 15
Therefore, it takes 1 / 2 / 15 = 7.5 hours for the bus to complete the whole journey
It should be 11 / 30. Suppose the distance between a and B is 1, the speed of passenger car is V1, and the speed of freight car is v2
4×V1+4×V2=1
3×V1+2×V2=1-11/30=19/30
By solving the above equations, we can get V1 = 2 / 15, V2 = 7 / 60
Because time = distance / speed
Therefore, the completion time of the bus is 1 / 2 / 15 = 7.5 hours
Party A and Party B transport 108 tons of goods. If Party A transports one seventh of the task to Party B, the ratio of Party A and Party B is 5:4?
I'm dizzy. I used to be in Grade 5. Now I have to talk for 2 minutes. I need a piece of paper to compare with a pen
A has 70. B has 38
The calculation process is long in words... Send me a letter if you need to
Two fifths of a pile of coal is used, and one fifth of a ton is left
A. More B. more C. as much D. not sure
Please elaborate
The rest is of the total
2 out of 1-5 = 3 out of 5
Because 3 out of 5 > 2 out of 5
So choose B. There are more left
The distance between a and B is 476 km. A bus and a freight car leave from the two places at the same time. When the two cars meet in 3.5 hours, the bus is 16 km faster than the freight car per hour
What is the speed of the bus,
If the speed of passenger car is x km / h, the speed of freight car is x + 16 km / h
3.5(x+x+16)=476
2x+16=136
2x=120
x=60km/h
The speed of the bus is 60 km / h
Party A and Party B work together to turn 1500 screws at the same time,
Party A and Party B have 1500 screws at the same time. Because Party B has improved the operation method, the production efficiency is three times higher than that of Party A, so it takes 20 hours less than the price. How many screws do they have per hour
If a has x cars per hour, B has 3x
Column equation 1500 / x = 1500 / 3x + 20
The solution is x = 50, that is, 50 per hour for a and 150 per hour for B
Two upstairs
A pile of coal weighs seven eighths of a ton. Two fifths of it has been transported away. How many tons are left?
Write process and formula
Because two fifths have been taken away, there are three fifths left. Seven eighths of the tons are multiplied by three fifths, so there are twenty-one fourths left
7 / 8-7 / 8 times 2 / 5 = 21 / 40 tons. 21 out of 40 tons. Right
7/8*(1-2/5)=21/40
7 / 8x (1-2 / 5) = 21 / 40
7 / 8 × (1-2 / 5) = 7 / 8 × 3 / 5 = 21 / 40 tons
7 / 8 (1-2 / 5) = 21 / 40 = 0.525 tons
21 out of 40
7 / 8 × (1-2 / 5) = 7 / 8 × 3 / 5 = 21 / 40 tons
The distance between a and B is 765 meters. A bus and a truck are going to the two places at the same time. Five hours later, the two cars are still 115 meters apart
The distance between a and B is 756km. A passenger car and a freight car drive from the two places at the same time. Five hours later, the two cars drive 115km. Given that the speed ratio of passenger car and freight car is 3:2, how many kilometers does the passenger car travel per hour?
Use the determinant
115÷5=23
23 * (2 / (2 + 3)) = 23 * 2 / 5 = 9.2km/h
Pro*^__ ^* ,
Car a carries goods 10 times and has carried goods 7 times, which means that car a has carried goods 3 times more than car B. car a carries 30 tons more than car B in total, which means that car a carries 10 tons of goods each time. The title has told us that the two cars have the same weight, so the carrying capacity of each car is 10 tons
30 / (10-7) = 10 (ton)