A car carries 42.5 tons of goods five times in the first day, and six times in the second day, with an average of 0.25 tons less than the first day?

A car carries 42.5 tons of goods five times in the first day, and six times in the second day, with an average of 0.25 tons less than the first day?

(42.5 △ 5-0.25) × 6 = (8.5-0.25) × 6, = 8.25 × 6, = 49.5 (tons). Answer: the next day, 49.5 tons of goods were transported
There are 30 tons of coal in pile a and pile B. 1 / 2 of pile a is equal to 1 / 4 of pile B. how many tons of coal are there in each pile?
A and B cars travel from two places at the same time. A car travels 45 kilometers per hour, B car 42 kilometers per hour. The two cars meet at the midpoint of 12 kilometers. How many hours after the two cars leave at the same time?
(it's a problem that only lists formulas but doesn't count.)
A and B cars travel from two places at the same time. A car travels 45 kilometers per hour, B car 42 kilometers per hour. The two cars meet at the midpoint of 12 kilometers. How many hours after the two cars leave at the same time?
12×2÷（45-42）
1. The unit price of apple is fixed, the quantity and total price of purchase. 2. The carrying capacity of each car is fixed, and the number of times of transportation is proportional to the total number of transportation
1. The unit price of apple is fixed. Is the quantity and total price of apple in proportion? 2. The carrying capacity of each car is fixed. Is the number of times of transportation in proportion to the total amount of transportation
1. Because total price △ quantity = unit price (certain), quantity and total price are in direct proportion
2. Because the total number of times = the carrying capacity of each vehicle (certain), the number of times of transportation is in direct proportion to the total number of transportation
1. Proportionality
2. Proportionality
Zhongxia chemical plant has two piles of coal, weighing 2268 kg in total. Two fifths of pile a and one fourth of pile B are taken out, weighing 708 kg in total. How many kg are the original coal?
Let a pile x kg, B 2268-x kg
2X/5+(2268-X)/4=708
0.4X+567-0.25X=708
0.15X=141
X=141/0.15
X=940
940 kg for pile a and 1328 kg for pile B
The total weight of 1 / 4 of pile a and 1 / 4 of pile B is 2268 × 1 / 4 = 567 (kg)
There was coal in pile a
=（708-567）÷（2/5-1/4）
=141÷（3/20）
=940 (kg)
There was coal in pile B
=2268-940
=1328 (kg)
2。 500 0。 It's impossible. It used to be 3. 4. How can l become 0 when a buys a. 22 5。 200 8。 40 6。 30 4。 27 6。 20 4。 38 and 00 5. 1400 and 8000 20. 71 and 435. 430 and 5254 65. 80 and 00 82. 630 and 600
2011-10-25 23:09:37
Let a pile x kg, B 2268-x kg
2X/5+(2268-X)/4=708
0.4X+567-0.25X=708
0.15X=141
X=141/0.15
X=940
940 kg for pile a and 1328 kg for pile B
Car a and car B travel from two places 378 kilometers away. After three hours, they meet. Car a travels 60 kilometers per hour, and car B travels how many kilometers per hour?
To solve the equation
The second car runs x kilometers per hour
3x plus 60 times 3 is 378
3x plus 180 is 378
3x equals 198
X equals 66
When the load of the car increases, to keep the speed unchanged, it should be ()
A. Make the car bigger
B. The momentum will increase
C. The car needs to be smaller
f=umg
M increases, f also increases
Therefore, it is necessary to increase the driving force, that is, to increase the engine power
According to the formula, it is obvious whether to choose B, it is convenient for you to rebuild a car or to step on the accelerator
Car is the same, you spend a lot of effort, or do a new car ah
There are two piles of cement on the construction site, weighing 2268 tons in total. Take out 25 piles of cement from pile a and 14 piles of cement from pile B, weighing 708 tons in total?
Suppose that there were x tons of cement in pile a, then there were 2268-x tons of cement in pile B. from the meaning of the question, we can get: 25X + 14 (2268-x) = 708, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 25X + 567-14x = 708, & nbsp; & nbsp; & nbsp; & nbsp; 320x + 567-567 = 708-567, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 320x × 203 = 141 × 203, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 940, cement in pile B: 2268-940 = 1328 tons. A: cement in pile a and pile B: 940 tons and 1328 tons respectively
The speed ratio of car a and car B is 5:4. When the two cars meet, they are 48 kilometers away from the midpoint
How many kilometers is the distance between them? The speed ratio of car a and car B is 5: 48 km from the midpoint when the two cars meet. How many kilometers is the distance between the two cities?
Suppose the distance between the two cities is s km, the time taken to meet is t, and the speed ratio of car a and car B is 5:4 = v1:v2
Then V1 * t-v2 * t = 48, V1 * t + V2 * t = s, V2 * t = 192, V1 * t = 240,
S = V1 * t + V2 * t = 240 + 192 = 432km
The carrying capacity of a car is fixed, the times of transporting goods and the tonnage of transporting goods. (what proportion) why
In proportion
Because the tonnage of goods transported △ the number of times of goods transported = the carrying capacity of the vehicle, it is a fixed value
It's proportional. If the carrying capacity is certain, then the tonnage of freight = Times × carrying capacity.