At the same time, the passenger car and the freight car set out from the two places of Party A and Party B, and they went opposite each other. After 7 hours, they met. The speed of the freight car was 9 / 10 of that of the passenger car. How many kilometers did the passenger car travel per hour The distance between the two places is 665 km

At the same time, the passenger car and the freight car set out from the two places of Party A and Party B, and they went opposite each other. After 7 hours, they met. The speed of the freight car was 9 / 10 of that of the passenger car. How many kilometers did the passenger car travel per hour The distance between the two places is 665 km

If the passenger car speed x is set, the freight car speed is 9 / 10x
7(1+9/10)x=665
If the bus speed is x, then the truck speed is 9 / 10x,
(x+9/10X)x7=665
x=35.
s=35x7=245
What grade are you in? Let's set the bus as X, the truck as 9 / 10x, and 7 (x + 9 / 10x) = 665
Finally, x = 50
Bus 50 km / h
Assuming that the passenger car travels x kilometers per hour, the freight car travels 9x / 10 kilometers per hour
From the meaning of the title: (x + 9x / 10) X7 = 665
Then x = 50
So the bus travels 50 kilometers per hour.
The road from a to B is 392 meters long. A car travels 168 kilometers in three hours. How many hours will it take to complete the whole journey
It will take x hours to complete the whole process
392-168:X=168:3
168X=3*224
X=4
It will take four hours to finish the whole journey
A car travels 168 km in 3 hours, with an average speed of 168 △ 3 = 56 km / h
So it takes (392-168) △ 56 = 224 △ 56 = 4 hours to complete the whole journey
I hope the answer will help you
(392-168)/X=168/3
We get x = 4
168/392=3/7
3/x=3/7,x=7
Take one eighth of the coal from pile a and give it to pile B. at this time, the weight of the two piles of coal is equal?
2 / 8 = 1 / 4 more from pile a than pile B
B is (1-1 / 4) △ 1 = 3 / 4 = 75% of A
75% (1-2 / 8)
Suppose that the weight of coal pile B is x and that of coal pile a is y, then x + Y / 8 = 7Y / 8, so x = 6y / 8, that is 75%
A-A / 8 = B + A / 8, then B = 3 / 4 * a
So: the weight of pile B coal is 75% of that of pile a coal
3/8÷5/8=60%
The speed of the freight car is 40% of that of the passenger car. The freight car and the passenger car run from a and B at the same time. After two hours, they meet,
When they meet, the distance ratio of freight cars to passenger cars is (): ()
5:2
V goods: V customers = 40% = 2:5
T is the same as 2
Then s Customer: s goods = V customer: V goods = 5:2
0.4:1
When the time is the same, the speed ratio is equal to the distance ratio
2:5
It took two days for a car to travel from a to B. on the first day, it took more than 168 kilometers. The ratio of the distance on the second day to the distance on the first day is 1:4. How many kilometers is the distance between a and B?
Two fifths of the whole journey is 168 km on the first day, and the ratio of the journey on the second day to the journey on the first day is 1:4. Then the whole journey is 2 / 5 × 1 / 4 more than 168 × 1 / 4 km on the second day, that is, 1 / 10 more than 42 km on the whole journey, and 2 / 5 + 1 / 10 more than 168 + 42 km on the two days, that is, 1 / 2 more than 210 km on the whole journey
The two piles of coal weigh 160 tons in total. If the first pile carries more than 20 tons and the second pile carries two fifths, how many tons will the two teams carry
Both Party A and Party B transport 2 / 5
Transport 160x2 / 5 = 64 tons
A total of 64 + 20 = 84 tons were transported
The distance between a and B is 560 km. A bus and a truck leave from a and B at the same time. After 3.5 hours, the two cars meet. The bus runs 90 km per hour, and the truck runs how many km per hour?
(560-3.5 × 90) △ 3.5, = (560-315) △ 3.5, = 245 △ 3.5, = 70 (km), a: the freight car travels 70 km per hour
The highway from Huzhou to Shanghai is 168 kilometers long. A and B cars leave the two cities at the same time. After 1.5 hours of intersection, a car runs 58 kilometers per hour. How many kilometers per hour does B car run?
168 △ 1.5-58 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; = 112-58 = 54 (km). A: car B runs 54 km per hour
For a pile of coal, two fifths of the coal is used first, and then four ninths of the total coal is used. This is 31 tons more than the rest. How many tons are there in this pile of coal?
It's better to say what each step means
Suppose there are x tons of coal in this pile
Then x * (2 / 5 + 4 / 9) is used successively
The rest is x-x * (2 / 5 + 4 / 9)
It can be solved by the following equation
x*(2/5+4/9)=x-x*(2/5+4/9)+31
31x/45=31
x=45
There are 45 tons of coal in this pile
A passenger car and a freight car, respectively, set out from both places at the same time, facing each other
Passenger cars travel 80 kilometers per hour, and freight cars travel 10% of the whole journey per hour. When the freight car reaches 5% of the whole journey, the passenger car can reach place B by 1 / 6 of the whole journey. How many kilometers is the distance between Party A and Party B?
When the freight car reaches 5 / 8 of the whole journey, the passenger car can reach place B by 1 / 6 of the whole journey. How many kilometers is the distance between the two places? The solution is: 10% of the whole journey of the freight car per hour, when the freight car reaches 5 / 8 of the whole journey, the time is: 5 / 8 △ 10
When the freight car reaches 5% of the whole journey, the traveling time of the freight car is as follows:
5 / 8 / (1 / 10) = 25 / 4 hours
Distance between a and B:
80*25/4/(1-1/6)
=500/(5/6)
=600 km
That is, the distance between a and B is 600 km.