There are two kinds of trucks. Car a can load 6 tons of coal each time, and car B can load 8 tons of coal each time. There are 400 tons of coal at present, which are required to be transported at one time, and each truck can be transported at the same time It's just full. How many trucks do you need? Requirements: column equation, column formula are OK, as long as the reason, the process to be listed

There are two kinds of trucks. Car a can load 6 tons of coal each time, and car B can load 8 tons of coal each time. There are 400 tons of coal at present, which are required to be transported at one time, and each truck can be transported at the same time It's just full. How many trucks do you need? Requirements: column equation, column formula are OK, as long as the reason, the process to be listed

The binary linear equation is listed: suppose x cars of a and Y cars of B are needed, then 6x + 8y = 400, and then the integer solutions of X and y are obtained. By changing the equation: y = 50 - (6x △ 8), the corresponding values of y can be obtained when x = 0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, so there are 17 groups of solutions
There are x vehicles of a and Y vehicles of B
We can get 6x + 8y = 400
The solution is x = 0, y = 50 or x = 4, y = 47 or x = 8, y = 44 or x = 12, y = 41 or x = 16, y = 38 or x = 20, y = 35 or x = 24, y = 32 or x = 28, y = 29 or x = 32, y = 26 or x = 36, y = 23 or x = 40, y = 20 or x = 44, y = 17 or x = 48, y = 14
You can make a list
A 60
B 5
The passenger car and the freight car start from the two places at the same time and travel in opposite directions. The passenger car travels 5 kilometers more per hour than the freight car. When they meet, the passenger car travels 14 / 27 of the whole journey
How many kilometers are there between a and B?
If 5 × 4 = 20 km, the passenger car will travel 20 km more than the freight car
1-14 / 27 = 13 / 27, then the truck runs 13 / 27
20 ÷ (14 / 27-13 / 27) = 540km
A: the distance between a and B is 540 km
Brother Qiushan, I don't know
5 × 4 △ 14 / 27 - (1-14 / 27)] = 20 △ 1 / 27 = 540km
How many times can b transport more goods than a? How many times can B complete the shipment?
18 × (1 + 13) = 18 × 43 = 161 △ 16 = 6 (Times) a: Vehicle B can transport 16% of the goods each time, and vehicle B can transport the goods 6 times
There are two kinds of trucks, car a can load 6 tons of coal each time, car B can load 8 tons of coal each time. There are 146 tons of coal at present, which are required to be transported at one time, and each truck is full. How many trucks do you need?
Suppose you need x cars a and Y cars B. according to the meaning of the question, you can get the equation: 6x + 8y = 64. The equation can be transformed into y = 32 − 3x4. Because X and y are integers, 32-3x must be a multiple of 4. Because 32 is a multiple of 4, 3x is also a multiple of 4. So when x = 4, y = 5, x = 8, y = 2. A: you need 4 cars a, 5 cars B, or 8 cars a and 2 cars B
The bus and the truck leave from a and B at the same time. The bus travels 60 kilometers per hour, and the truck travels 1 / 12 of the whole journey per hour. When they meet, the bus and the truck will stop
The ratio of the distance traveled by passenger cars to freight cars is 5:4. How many kilometers are there between the two places?
Because the travel ratio of two cars is 5:4 when they meet, and the time is equal, the speed ratio of passenger car and freight car is 5:4
Because the bus speed is 60, the train speed is 60 / 5 * 4 = 48
Because the hourly travel distance of freight cars is 1 / 12 of the whole journey, the distance between the whole journey is 48 * 12 = 576
So the distance between the two places is 576 meters
When we met, the truck went: 4 / 9) / (1 / 12 = 16 / 3 hours
The whole journey of the bus: 16 / 3) / (5 / 9 = 48 / 5 hours
Distance: 60x48 / 5 = 576km
60 * 4 / 5 / (1 / 12) = 576km
A: the distance between the two places is 576 km
Three cars carry a batch of goods. Car a carries two seventh of this batch of goods. Car B carries 100 pieces more than car A. car C carries 170 pieces,
If there are x pieces in total, then there is equation
Suppose: there are x pieces in total
(1-2/7-2/7)X=170+100
3/7X=270
X=630
A: there are 630 pieces in total
2/7x+100=170
2/7x=170-100
2/7x=70
x=70÷2/7
x=245
Party A and Party B transport concrete by two trucks, Party B transport concrete by eight times, party a transport concrete by five times, party a transport concrete by 1.6 tons more than Party B each time, party a transport concrete by 10 tons less than Party B at the time of settlement
How many tons can b transport each time?
A5 B8 A-B=1.6
8B-5A=10
5A-5B=8
5A+8B 5A+5B = 18
3b=18 B=6 A=7.6
7.6 5 = 38
6 8 =48
A = 7.6 B = 6
A: Vehicle B transports 6 tons each time.
Set car B to transport x tons each time. Then car a will transport x + 1.6 tons each time. 8X—10=5(X+1.6) X=6
So car B transports 6 tons each time
Passenger cars and freight cars leave from a and B at the same time. Passenger cars travel 60 kilometers per hour, while trains travel 1 / 15 of the whole journey per hour. When they meet, the distance ratio of passenger cars and freight cars is 5:4. How many kilometers are there between a, B and B?
5+4=9
4/9÷1/15 ×60÷ 5/9
=400÷5/9
=720km
Meeting time: 4 / (5 + 4) △ 1 / 15 = 20 / 3 (hours)
A. B. distance between the two places: 60x20 / 3 △ 5 / (5 + 4) = 720 (km)
Let's meet in X hours
x/15=4/(5+4)
x=20/3
Distance = 60 × 20 / 3 △ 5 / 9 = 720km
For a batch of goods, a and B can complete 56% of this batch of goods in 6 days. If they are transported alone, it takes the same time for a to complete 13 and B to complete 12______ Day B: Yes______ Day
A. The work efficiency ratio of B is: 13:12 = 2:3, the work efficiency of a is: 56 △ 6 × 23 + 2, = 536 × 25, = 118; the work efficiency of B is: 56 △ 6 × 33 + 2, = 536 × 35, = 112; when doing it alone, a needs: 1 △ 118 = 18 (days); B needs: 1 △ 112 = 12 (days); answer: when doing it alone, a needs 18 days to complete; B needs 12 days to complete
Two trucks are used to transport coal. Car a carries coal five times, car B carries coal eight times, and car a transports 1.6 tons more each time. At the end of transportation, car a transports 10 tons less than car B, and how many tons does car B transport each time?
6 tons
(1.6*5+10)/(8-5)=6