When the two vehicles meet, the distance ratio of the two vehicles is 5:4; after the meeting, the truck is 27 kilometers faster than the bus per hour As a result, the two cars arrived at the other side's departure station at the same time. It is known that the freight car has been running for 10 hours. How many kilometers is the distance between a and B?

When the two vehicles meet, the distance ratio of the two vehicles is 5:4; after the meeting, the truck is 27 kilometers faster than the bus per hour As a result, the two cars arrived at the other side's departure station at the same time. It is known that the freight car has been running for 10 hours. How many kilometers is the distance between a and B?

After the meeting, if the distance between the passenger car and the freight car is the same as that between the freight car and the passenger car, then the distance ratio between the freight car and the passenger car is 5:4. (5-4) if the freight car is more than the passenger car, that is, the freight car is 27 km faster than the passenger car, 27x5 = 135 km is the speed of the freight car, 135x10 = 1350 km, 1350 km is 5 / 9 of the whole journey of Party A and Party B, then 1350 △ 5 / 9 = 2430 km
The distance between a and B is 2430 km
If there are 6500 kilos of goods per truck, how many kilos of goods can be delivered?
With X cars
6500(x-6)=5000x
6500x-39000=5000x
6500x-5000x=39000
1000x=39000
x=39
39x5000 = 195000 kg = 195 tons
If you don't understand this question, you can ask,
5000×6÷(6500-5000)
=30000÷1500
=20 vehicles
(20 + 6) × 5000 = 130000kg = 130t
It's 130 tons
If it's full of 6500 cars, it's not a complete problem?
If every car is full, it's easy.
(5000 * 6 / (6500-5000) + 6) * 5000 = 130000 kg = 130t
A pile of coal is transported in six hours, and B is one fifth more efficient. How many hours is it transported by two teams?
A transports one sixth of the total amount per hour, and B is one fifth more efficient. That is to say, B transports one sixth of the total amount per hour by six fifths, which is equal to one fifth. I believe you can solve the rest by yourself! It's good for you to exercise yourself!
The two passenger and freight cars leave each other at the same time. When they meet, the distance ratio of the two cars is 6:5. After meeting, the freight car is 12 kilometers faster than the passenger car per hour
The bus is still going at the same speed, but the two cars arrive at the other side's departure station at the same time. It is known that the truck has been running for 10 hours. How many kilometers is the distance between a and B? Explain the meaning of each step and how to find it
When the time is fixed, the distance ratio is the speed ratio, that is, before the meeting, the ratio of the speed of the bus to that of the truck is also 6:5. Let the speed of the bus be unit one and that of the truck be 5 / 6 (unit one)
When we met, the bus took the whole journey: 6 / (6 + 5) = 6 / 11, and the truck took the whole journey: 5 / (6 + 5) = 5 / 11
After the meeting, the passenger car took 5 / 11 of the whole journey, and the freight car took 6 / 11 of the whole journey. The speed of the freight car was 6 / 11 △ 5 / 11 = 6 / 5 (unit 1). The freight car was faster than the passenger car: 6 / 5-1 = 1 / 5 (unit 1). The speed of the passenger car was 12 △ 1 / 5 = 60 (km / h)
The original speed of the freight car is 60 × 5 / 6 = 50 (km / h), and the speed of the freight car after speed increase is 60 × 6 / 5 = 72 (km / h)
The distance between a and B is 60 × 10 = 600 (km)
Suppose the speed of passenger cars is 6x and that of freight cars is 5x.
After the meeting, the speed of the truck is 6x + 12
The total distance is 6x * 10 = 60x
Before the meeting, the truck drove 300 / 11x and the bus 360 / 11x
The driving time before the meeting was 60 / 11
So the equation is
360/11x=(10-60/11)(6x+12)
360x=50(6x+12)
360x=300x+600
60x = 600... Unfold
Suppose the speed of passenger cars is 6x and that of freight cars is 5x.
The speed of the lorries after meeting is 6x + 12
The total distance is 6x * 10 = 60x
Before the meeting, the truck drove 300 / 11x and the bus 360 / 11x
The driving time before the meeting was 60 / 11
So the equation is
360/11x=(10-60/11)(6x+12)
360x=50(6x+12)
360x=300x+600
60x=600
x=10
A: the distance between a and B is 600 kilometers
Hope to help you have something you don't understand. Ask: after meeting, the speed of the lorry is 6x + 12, the total distance is 6x * 10 = 60x, there is + 12 before, how can there be + 12 after? Where did 300 and 360 come from? I'm only in the sixth grade, so I can understand it if it's easy to understand!
One truck can transport 5000 kg of goods at a time, and how many kg of goods can two trucks transport four times? How many tons?
2. How many kilos of goods can be transported by trucks four times? 40000 kilos, 40 tons
5000x2x4 = 40000 kg = 40 t
There are two kinds of trucks, car a can load 6 tons of coal each time, car B can load 8 tons of coal each time. There are 146 tons of coal at present, which are required to be transported at one time, and each truck is full. How many trucks do you need?
Suppose you need x cars a and Y cars B. according to the meaning of the question, you can get the equation: 6x + 8y = 64. The equation can be transformed into y = 32 − 3x4. Because X and y are integers, 32-3x must be a multiple of 4. Because 32 is a multiple of 4, 3x is also a multiple of 4. So when x = 4, y = 5, x = 8, y = 2. A: you need 4 cars a, 5 cars B, or 8 cars a and 2 cars B
Both passenger and freight cars leave from a and B at the same time. The passenger cars travel 44 kilometers per hour and the freight cars 52 kilometers per hour. After the two cars meet, they continue to move at the same speed
Return immediately after you arrive at B A. when you meet for the second time, the truck will travel 80 kilometers more than the bus. How many kilometers is the distance between a and B
If the distance between the two places is x km, the time taken is 3x / (52 + 44),
Because freight cars travel 80 times more than passenger cars, there are: (52-44) * 3x / (52 + 44) = 80
The solution is x = 320
The transport team transported a batch of rice to the disaster area. In the morning, it took 4 trucks to transport 25, with an average of 20% per truck______ What about the rest of the rice______ The car can't be finished
How many parts of this batch of rice can be transported by each truck on average: 25 △ 4, = 25 × 14, = 110; how many trucks can the rest of the rice be transported by: (1-25) △ 110, = 35 △ 110, = 6 (trucks); a: 110 of this batch of rice can be transported by each truck on average, and the rest of the rice can be transported by 6 trucks
There are two kinds of trucks, car a can load 6 tons of coal each time, car B can load 8 tons of coal each time. There are 146 tons of coal at present, which are required to be transported at one time, and each truck is full. How many trucks do you need?
Suppose you need x cars a and Y cars B. according to the meaning of the question, you can get the equation: 6x + 8y = 64. The equation can be transformed into y = 32 − 3x4. Because X and y are integers, 32-3x must be a multiple of 4. Because 32 is a multiple of 4, 3x is also a multiple of 4. So when x = 4, y = 5, x = 8, y = 2. A: you need 4 cars a, 5 cars B, or 8 cars a and 2 cars B
The speed of the freight car is 910 times that of the passenger car. The freight car and the passenger car are going towards each other at the same time from a and B. they meet at a distance of 3km from the midpoint of the two places. After meeting, the two cars continue to advance at the original speed to reach a and B. when the passenger car reaches a, how far is the freight car from B?
3 × 2 ^ (1-910), = 6 ^ 110, = 60 (km); 60 × 910 = 54 (km), (60 + 54) × (1-910), = 114 × 110, = 11.4 (km); a: when the bus arrives at B, the truck is still 11.4 km away from B