In a workshop, the ratio of male workers to female workers is 5; 6. Later, a male worker was transferred from other places. At this time, the number of male workers is just 87.5% of the number of female workers. How many people are there in total

In a workshop, the ratio of male workers to female workers is 5; 6. Later, a male worker was transferred from other places. At this time, the number of male workers is just 87.5% of the number of female workers. How many people are there in total

Female workers = 1 / (87.5% - 5 / 6) = 24
Male workers = 24 * 87.5% = 21
Total = 28 + 21 = 49
Suppose the original number of male workers is 5x and that of female workers is 6x
（5x＋1）/6x＝87.5％
Solution
x＝4，
So 5x + 6x = 20
That is, there were 20 people in the past, and now there are 21
There are 60 workers in one workshop, and then three women workers are lost from other workshops. This is three fourths of the number of women workers. How many women workers are there?
24 females and 36 males
There are 52 workers in a workshop, and then four women workers are transferred in. At this time, the number of women workers accounts for 75% of the total number. How many women workers were there?
Now there are 52 + 4 = 56 workers in the workshop
Three quarters of the female workers are men
The ratio of female workers to male workers is 3:4
There were 56 * (3 / 7) = 24 female workers
The original number of female workers is 24-4 = 20
The distance between the two places is 90km. The two cars run from the two places at the same time and meet in two thirds of an hour. The speed ratio of the two cars is 4:5, and the two cars run from each other every hour
How many kilometers are there?
There should be no unknowns, and there should be units. Those who answer well will offer extra rewards~
Speed sum = 90 (2 / 3) = 135 km / h;
A speed = 135 × (4 / (4 + 5)) = 60 km / h;
B speed = 135-60 = 75 km / h;
A drove 40km, B drove 50km,
90 / (2 / 3) = 135km / h speed and speed of two people
135 * (5 / 9) = 75KM / h, and the speed of B accounts for five ninths of the total speed
135-75 = 60km / h the speed of a is the total speed minus the speed of B
Anyway, that's the idea. I'll see what I can do.
A 40km
B 50km
A, 75KM / h, B, 60km / h
Speed sum = 90 (2 / 3) = 135 km / h;
A speed = 135 × (4 / (4 + 5)) = 60 km / h;
B speed = 135-60 = 75 km / h; add subtract multiply divide with words speed sum = 90 divided by (2 / 3) = 135 km / h; a speed = 135 times (4 divided by (4 plus 5)) = 60 km / h; B speed = 135 minus 60 = 75 km / h; OK, please adopt @! Thank you for... Unfolding
Speed sum = 90 (2 / 3) = 135 km / h;
A speed = 135 × (4 / (4 + 5)) = 60 km / h;
B speed = 135-60 = 75 km / h
When car a runs 3 / 7 of the whole, car B runs 36 kilometers;
When car a runs 3 / 7 of the whole journey, car B runs 36 km; when car a arrives at place B, car B runs 7 / 10 of the whole journey. What is the distance between two places?
It takes six minutes for a to make a part, five minutes for B, and four minutes for C. At present, 1590 parts are assigned to three of them, which are required to be completed in the same time. How many parts should each person assign?
1. According to the meaning of the title, the speed ratio of a and B is 10:7
The distance between the two places is x km
3x/7=36÷（7/10）
3x/7=36×（10/7）
x=36×（10/7）×（7/3）
X = 120 km
A: AB is 120 kilometers away
2. A: B: C
=1/6：1/5：1/4.5
=15：18：20
A = 1590 ÷ (15 + 18 + 20) × 15 = 450
B = 1590 ÷ (15 + 18 + 20) × 18 = 540
C = 1590 △ (15 + 18 + 20) × 20 = 600
1.36÷（3 /7 ×7 /10 ），
=36÷3 /10
=120 km;
A: AB is 120 kilometers apart
Two
Let's say three people have worked for X minutes
x/6+x/5+x/4.5=1590
X = 2700 minutes
A: 2700 / 6 = 450
B: 2700 / 5 = 540
C: 2700 / 4.5 = 600
According to the meaning of the title, the speed ratio of a and B is 10:7. .
The distance between the two places is x km
3x/7=36÷（7/10）
3x/7=36×（10/7）
x=36×（10/7）×（7/3）
X = 120 km
A: AB is 120 kilometers away
2. A: B: C
=1/6：1/5：1/4.5
=15：18：20
A = 1590 ÷ (15 + 18 + 20) × 15 = 450
According to the meaning of the title, the speed ratio of a and B is 10:7. .
The distance between the two places is x km
3x/7=36÷（7/10）
3x/7=36×（10/7）
x=36×（10/7）×（7/3）
X = 120 km
A: AB is 120 kilometers away
2. A: B: C
=1/6：1/5：1/4.5
=15：18：20
A = 1590 ÷ (15 + 18 + 20) × 15 = 450
B = 1590 ÷ (15 + 18 + 20) × 18 = 540
C = 1590 △ (15 + 18 + 20) × 20 = 600
In addition, this kind of problem had better ponder by oneself, because others tell is not as good as what they think of all the time!!!!! Put it away
The meeting time is t, the distance is s, and the speed is V A and V B
7 / 10V a = v b
T is the same, 7 / 10s a = s B
When s b = 36, s a is 360 / 7
And s a is 3 / 7 of the whole process
So the whole journey is 360 / 7 / (3 / 7) = 120 km
The minimum common multiple is 90 minutes
90 minutes, a 15, B 18, C 20, a total of 53
1590/53=30
A 30 *. Deployment
The meeting time is t, the distance is s, and the speed is V A and V B
7 / 10V a = v b
T is the same, 7 / 10s a = s B
When s b = 36, s a is 360 / 7
And s a is 3 / 7 of the whole process
So the whole journey is 360 / 7 / (3 / 7) = 120 km
The minimum common multiple is 90 minutes
90 minutes, a 15, B 18, C 20, a total of 53
1590/53=30
A 30 * 15 = 450
B 30 * 18 = 540
C 30 * 20 = 600
Primary school solution:
1. When car a goes 1 / 7 of the whole journey, car B goes 12 km. When car a arrives at place B, car B goes 12 km * 7, and car B goes 7 / 10 of the whole journey, so the distance between AB and ab is 12 km * 10 = 120 km;
2. In 90 minutes, a made 15, B 18, C 20, a total of 53, so 1590 / 53 = 30, so a should do 30 * 15 = 450, B should do 30 * 18 = 540, C should do 30 * 20 = 600.
Middle school solution
Primary school solution:
1. When car a goes 1 / 7 of the whole journey, car B goes 12 km. When car a arrives at place B, car B goes 12 km * 7, and car B goes 7 / 10 of the whole journey, so the distance between AB and ab is 12 km * 10 = 120 km;
2. In 90 minutes, a made 15, B 18, C 20, a total of 53, so 1590 / 53 = 30, so a should do 30 * 15 = 450, B should do 30 * 18 = 540, C should do 30 * 20 = 600.
Learning the solution,
Set the unknown number and solve the equation. The answer is the same. Put it away
First of all, you can make an analysis. When a drives 3 / 7 and B drives 36 km, you can infer that when a completes the remaining 4 / 7, B drives 48 km again. At this time, B drives 84 km, which is 7 / 10 of the whole journey, so you can get the whole journey of 120 km!
The second question, I don't think it's too troublesome to calculate the result, but I can think about it like this. If the time required is x, then everyone's completion quantity is x / their speed, that is 6,5 and 4.5, and then the total is 1590! After calculating x, calculate the finished quantity respectively! ... unfold
First of all, you can make an analysis. When a drives 3 / 7 and B drives 36 km, you can infer that when a completes the remaining 4 / 7, B drives 48 km again. At this time, B drives 84 km, which is 7 / 10 of the whole journey, so you can get the whole journey of 120 km!
The second question, I don't think it's too troublesome to calculate the result, but I can think about it like this. If the time required is x, then everyone's completion quantity is x / their speed, that is 6,5 and 4.5, and then the total is 1590! After calculating x, calculate the finished quantity respectively! Put it away
36 / [3 / 7 * (7 / 10)] = 120 km, the speed of vehicle B is 7 / 10 of that of vehicle a, so 36 km is 3 / 7 times 7 / 10 of the whole journey
1590 / (1 + 6 / 5 + 4 / 3) = 450, which is the quantity given to a, B: 450 * 6 / 5 = 540, C: 450 * 4 / 3 = 600
The manufacturing speed of a is 1, and that of C is 6 / 5 of that of A. similarly, that of C is 4.5/6, or 4 / 3
The number of people in workshop a is three times that of workshop B, less than 10 people. If 20 people are transferred from workshop a to workshop B, the number of people in workshop a and workshop B are equal, the original number of people in workshop a and workshop B should be calculated
With the equation, there must be a quantitative relationship
If there are x people in workshop B, there are 3x-10 people in workshop a
3x-10-20=x+20,2x=50,x=25,3x-10=65
The original number of workshop a and workshop B were 65 and 25 respectively
A and B buses leave from the two places and meet at 30 kilometers away from the midpoint five hours later. How many kilometers does the fast train travel per hour and the slow train travel per hour?
(60 × 5-30 × 2) △ 5 = (300-60) △ 5 = 240 △ 5 = 48 (km) a: the local train runs 48 km per hour
Car a and car B leave from both places at the same time and meet in 6 hours. When they meet, car a travels 60 kilometers more than car B. It is known that the speed ratio of car a and car B is 11:9. How many kilometers does car a travel per hour?
60 △ 1111 + 9 − 911 + 9) × 1111 + 9 △ 6, = 60 ÷ (1120 − 920) × 1120 △ 6, = 60 × 202 × 1120 △ 6, = 330 △ 6, = 55 (km); a: car a travels 55 km per hour
When car a runs 3 / 7 of the whole journey, car B runs 36 kilometers. When car a arrives at place B, car B runs 36 kilometers
How many kilometers are there between a and B?
A: 3 / 7 of the first stage, 1-3 / 7 of the second stage = 4 / 7
As you can see, car B has driven 3 / 7 and 4 / 7 of the total distance of car B in these two periods
Car B drove 7 / 10 × 3 / 7 = 3 / 10 in the first period of time
So the distance between the two places = 36 △ 3 / 10 = 120 (km)
Suppose the total distance is 1
So car a is 3 / 7
Let's say the speed of home is X
Then the travel time is (3 / 7) / X
At this time, car B traveled 36 kilometers
So the speed of car B is... 36/[（3/7）/X]=84X
And because when car a arrived at place B, car B went all the way
So the distance between a and B is 36 / [(3 / 7) / x] = 84x times the total time 1 / X
Get the result.. 84... Unfold
Suppose the total distance is 1
So car a is 3 / 7
Let's say the speed of home is X
Then the travel time is (3 / 7) / X
At this time, car B traveled 36 kilometers
So the speed of car B is... 36/[（3/7）/X]=84X
And because when car a arrived at place B, car B went all the way
So the distance between a and B is 36 / [(3 / 7) / x] = 84x times the total time 1 / X
The result is.. 84. Put it away
First question:
Three out of seven to 36 equals four out of seven??? After calculation, 48
？？？ It represents the second driving distance of car B, that is, the second driving distance of 48 km
36 for the first time + 48 for the second time = 84
The second question: car B drove to 7 / 10 of the whole journey twice, driving 84km... Unfolding
First question:
Three out of seven to 36 equals four out of seven??? After calculation, 48
？？？ It represents the second driving distance of car B, that is, the second driving distance of 48 km
36 for the first time + 48 for the second time = 84
Second question: car B drove to 7 / 10 of the whole journey twice, driving 84 kilometers
Seven out of ten to 84 = three out of ten??? Calculated 36 km
？？？ The representative is car B. the remaining distance is 36 kilometers
84 + 36 = 120 ° Stow
There are two workshops a and B. if 10 people are transferred from workshop a to workshop B, the number of people in the two workshops is exactly the same. If 20 people are transferred from workshop B to workshop a, the number of people in workshop a is the same
The number of people in the workshop is just three times that of workshop B, with two workshops each