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There are 52 workers in a workshop, and then four women workers are transferred in. At this time, the number of women workers is 34 times that of men workers. How many women workers are there in this workshop?
52 - (52 + 4) × 44 + 3, = 52-56 × 47, = 52-32, = 20 (people); a: there were 20 female workers in this workshop
There are 120 employees in a workshop. The number of male employees is one third of that of female employees. How many are male and female employees?
Suppose there are x female workers and 1 / 3 * x male workers. From the meaning of the question: x + 1 / 3 * x = 120 solution: x = 90 answer: there are 30 male workers and 90 female workers
There are 120 workers in a workshop. The ratio of male workers to female workers is 3 to 5. How many percent more female workers than male workers?
（5-3）÷3×100%=66.7%
Have a good time
A and B buses leave from the two places and meet at 30 kilometers away from the midpoint five hours later. How many kilometers does the fast train travel per hour and the slow train travel per hour?
(60 × 5-30 × 2) △ 5 = (300-60) △ 5 = 240 △ 5 = 48 (km) a: the local train runs 48 km per hour
A and B leave each other at the same time. They meet each other in six hours. When they meet, a travels 60 kilometers more than B. the speed ratio of a and B is 11:9. Does a go every hour?
Count
55 km / h
The speed ratio of car a and car B is 11:9. When meeting, car a travels 11 / 9 of car B's. when meeting, car a travels more than car B, which is 2 / 9 of car B's
When meeting, a travels 60 kilometers more than B. when meeting, B travels 60 / (2 / 9) = 270 kilometers. When meeting, a travels 270 * (11 / 9) = 330 kilometers
Meet in 6 hours. Speed of car a: 330 / 6 = 55 km / h
Car a and car B run at the same speed. Car a runs for 8 hours and car B runs for 11 hours. It is known that car a runs 120 kilometers more than car B. how much does car a run
Write the process down
120÷（11-8）×8=320
A: 320 kilometers
There is a workshop a and B. the number of people in the former workshop a is 7:3 more than that in workshop B, so 20 people are transferred from workshop a. the number of people in workshop B is 8:1 more than that in workshop A. how many people are there in the former workshop a and B?
Primary school mathematics, can't use my XY
At the beginning, workshop a accounted for 10 / 17 of the total number of people, while workshop B accounted for 7 / 17. The number of people in workshop a was 7 points more than that in workshop B
After 20 people were transferred, it turned into 8 / 17, B 9 / 17, and B had one eighth more than a
So these 20 people account for (10-8) / 17
So the total number is 170
100 a
B 70
B has 7x / 10
So x-20 = 8 (7x / 10 + 20) / 9
So x = 100
D
Let's set up a original x person and B original 4 / 7X person
4/7x+20=（1+1/8)(x-20)
There must be no problem with the formula, that is, I understand 3 / 7 and 1 / 8 as 3 / 7 and 1 / 8
Suppose: if the number of people in workshop B is x, the number of people in workshop a is 10x / 7
When 20 people fell from workshop a to workshop B
Number of people in workshop a: 10x / 7 - 20
The number of people in workshop B is: x + 20
According to the known formula: (9 (10x / 7 - 20)) / 8 = x + 20
9(10x/7 - 20) = 8x + 160
The fast train runs 100 kilometers per hour, the slow train 80 kilometers per hour, and the two cars meet each other at a distance of 20 kilometers from the midpoint
There should be a formula for the distance between Party A and Party B,
Fast full speed difference is 100-80 = 20 km
20 + 20 = 40 km
40 △ 20 = 2 hours
100 × 2 + 80 × 2 = 360 km
There's no time
20 * 2 = 40 the express train runs more than the local train
100-80 = 20 the distance of the fast train per hour is longer than that of the local train
40 / 20 = 2 time when two cars meet
(100 + 80) * 2 = 360 speed times time
Car a and car B leave from both places at the same time and meet in 6 hours. When they meet, car a travels 60 kilometers more than car B. It is known that the speed ratio of car a and car B is 11:9. How many kilometers does car a travel per hour?
60 △ 1111 + 9 − 911 + 9) × 1111 + 9 △ 6, = 60 ÷ (1120 − 920) × 1120 △ 6, = 60 × 202 × 1120 △ 6, = 330 △ 6, = 55 (km); a: car a travels 55 km per hour
Two cars a and B leave a and B at the same time. They run in opposite directions. Five hours later, the two cars meet. It is known that it takes nine hours for car a to complete the whole journey, and the speed of car B is 48 km / h
Two cars a and B leave a and B at the same time and run in opposite directions. Five hours later, the two cars meet. It is known that it takes nine hours for car a to complete the whole journey. The speed of car B is 48 km / h, and the speed of car a is ()
Suppose the speed of car a is x km / h
（X+48)×5=9X
5X+240=9X
4X=240
X=60
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