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There are 160 workers in a workshop. The number of male workers is 3 / 5 of that of female workers. How many fewer male workers than female workers
The number of male workers is three fifths of that of female workers
There are x female employees
X+X*3/5=160
X=100
160-100=60
So there are 60 male workers and 100 female workers. There are 40 fewer male workers than female workers
No unknowns
160 ／ (1 + 3 / 5) = 160 ／ 8 / 5 = 100 people
160-100 = 60
As shown in the figure on the right, a rectangle is 10 cm long and 6 cm wide. Both a and B small ants crawl along the edge of the rectangle from point a at the same time, with a speed ratio of 3:2. & lt; BR & nbsp; / & gt; how many centimeters did a ant crawl when they met
Crawling in the same direction, (10 + 6) * 2 / (1-2 / 3) = 96cm
Relative creep, (10 + 6) * 2 * (2 / 3) = 21.33 cm
The number of male workers in a workshop is 20% less than that of female workers. The number of male workers is 48. How many workers are there in the workshop?
Answer: there are 108 people in this workshop
On the highway, a 5-meter-long car with a speed of 110 km / h is prepared to surpass a 15 meter long truck with a speed of 100 km / h
The process of solving linear equation with one variable
When the car surpasses the truck, the car has more lines than the truck, the length of the car + the length of the car and the distance of the truck
If the overtaking time is t, then
110t-100t=0.015+0.005
T = 0.002 hours = 7.2 seconds
It takes 7.2 seconds
The relative speed ratio of a and B from ab at the same time is 3; 2 after meeting, a speeds up by 20% and B speeds up by 30%. When a arrives at B, B still has 14 kilometers, and ab is far away
After increasing the speed, a becomes 3 × 1.2x, B becomes 1.3 × 2x, and after t hours, a reaches a
Then: 3 × 1.2xt = 1.3 × 2x + 14, and the solution is: XT = 14
AB=3×1.2xt=3×1.2×14=50.4Km
A and B leave each other from two places 360 km away. It is known that the speed of a is 60 km / h and that of B is 40 km / h. If a leaves for one hour first, how long will it take for B to meet each other?
Let B drive for X hours and the two cars meet. From the meaning of the question, we get 60 (x + 1) + 40x = 360. The solution is: x = 3. A: the two cars meet three hours after B drives,
The ratio of the original number of people in factory a and factory B is 7:6. After 360 people are transferred from factory a to factory B, the ratio of the original number of people in factory a and factory B is 2:3. How many people are there in factory a and factory B?
Answer: there are 2600 people in the two factories
On the highway, how long does it take for a car with a length of four meters and a speed of 110 km / h to surpass a truck with a length of 12 meters and a speed of 100 km / h?
Set the required time x seconds
According to the meaning and known, there are:
110x/3600-100x/3600=(4+12)/1000
(11x-10x)/360=16/1000
x/360=16/100
x=(16×360)/1000
X = 5.76 (SEC)
A: it takes 5.76 seconds
The two trains a and B start from a and B at the same time and run in opposite directions. After 1.5 hours, they meet at 18 kilometers away from the midpoint. It is known that the speed of train a is 1.2 times that of train B. how many kilometers did the two trains travel when they met?
18 × 2 △ 1.5 △ 1.2-1 = 24 △ 0.2, = 120 (km). 120 × 1.2 = 144 (km). 120 × 1.5 = 180 (km). 144 × 1.5 = 216 (km)
Car a and car B start from place a at the same time and run in opposite directions. Car a's speed is 40 km / h, and car B's speed is 30 km / h. two hours later, car a returns important materials to car B and goes back to chase car B. how many hours from place a does car a catch up with car B?
The equivalent relation is______ Let car a overtake car B after X hours from a, and the equation is______ The solution is obtained______
Let car a catch up with car B x hours after starting from a
The distance between two vehicles: 2 * (30 + 40) = 140 (km)
The equivalent relationship is that the time used is equal, the total distance of a minus 2 hours, the distance between two vehicles is equal to the distance of B
40(x-2)-2*(30+40)=30(x-2)
The solution is: x = 16 (H)
That is, 16 hours after starting from a, car a catches up with car B
Let car a catch up with car B x hours after starting from a
The distance between two vehicles: 2 * (30 + 40) = 140 (km)
The equivalent relationship is that the time used is equal, the total distance of a minus 2 hours, the distance between two vehicles is equal to the distance of B
40(x-2)-2*(30+40)=30(x-2)
The solution is: x = 16 (H)
That is, 16 hours after starting from a, car a catches up with car B. Thank you for pushing me once. OK
Let car a catch up with car B x hours after starting from a
The distance between two vehicles: 2 * (30 + 40) = 140 (km)
The equivalent relationship is that the time used is equal, the total distance of a minus 2 hours, the distance between two vehicles is equal to the distance of B
40(x-2)-2*(30+40)=30(x-2)
The solution is: x = 16 (H)
That is, 16 hours after starting from a, car a catches up with car B. Give me a lift. Thank you. Put it away
The solution of 40x = 30x + (40 + 30) X2 is x = 14
The equivalent relation is (same time and same displacement)_
30X=40*（X-2)-(30+40)*2
30X=40X-80-140
X = 22 hours
40x = 30 (x + 4) gives x = 12h
There are 360 people in three workshops of a factory. The number of people in the second workshop is three times more than that in the first workshop. The number of people in the third workshop is two times less than half of that in the first workshop,
The gross output value of a and B plants is 100000 yuan per year. In the second year, the output value of a plant will increase by 10%, and that of B plant will increase by 15%. The gross output value of the two plants will increase by 12% compared with that of the first year
Let 123 workshop be XYZ people, x + y + Z = 360y = 3x + 2Z = x / 2-2 or 1 workshop be x people, then 23 workshops are (3x + 2), (x / 2-2) people, x + (3x + 2) + (x / 2-2) = 360, 4.5X = 360, x = 80, 2, 3 workshops are 242, 382 respectively
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