The ratio of male to female workers in a workshop is 8:5. Later, 20 female workers were transferred in. At this time, the number of female workers is 3 / 4 of that of male workers. How many workers are there in this workshop?

The ratio of male to female workers in a workshop is 8:5. Later, 20 female workers were transferred in. At this time, the number of female workers is 3 / 4 of that of male workers. How many workers are there in this workshop?

Solution: suppose there are 8x male workers and 5x female workers
(5x+20)/8x=3/4
The solution is x = 20
So 8x = 8 * 20 = 160
5x=5*20=100
So there were 160 + 100 = 260 workers
If we add in 20 female workers now, there will be 280
If you want to find out the proportion of all the men and women in the past, it will be 1:20
5x-8y=0
4*(20+y)=3x
In a workshop, male workers account for 8 / 5 of female workers, and then 20 female workers are transferred. At this time, the number of female workers is 3 / 4 of that of male workers
If there were x female workers, there were 8x male workers
Then x + 20 = (3 / 4) * (8x / 5)
We can get x = 100
So there were 100 female workers and 160 male workers
100 people.
If the original number of female workers is x, the original number of male workers is 8 / 5 X
Then 20 female workers came, and the number of female workers became x + 20
Then compare the number of female workers (x + 20) with the number of male workers (8 / 5 x), the ratio is 4 / 3
Finally, solve the unknown x to get the answer.
The distance between the two places is 60 kilometers. The two vehicles leave each other at the same time and meet after 40 minutes. The speed ratio of the two vehicles is 4:5. How many kilometers do the two vehicles travel each hour?
Hello:
40 minutes = 2 / 3 hours
Speed sum of two cars = 60 △ 2 / 3 = 90 (km)
(4 + 4 km) × 90
Vehicle B speed = 90-40 = 50 (km)
A 80 / 3km
B 100 / 3km
First ask how many kilometers a and B walk each minute. 5 km divided by 60
The speed ratio of a and B is 4:5, which a's speed is 1.5 times 4 / 9 (denominator 4 + 5) = 2 / 3 km
B is 1.5 times 5 / 9 (denominator 4 + 5) = 5 / 6 km
If the distance of car a is 1 / 4 more than that of car B, and the time of car B is 1 / 4 more than that of car a, what is the speed ratio of two cars?
If the distance of car a is 1 / 4 more than that of car B, then the distance of car a = (1 + 1 / 4) the distance of car B = 5 / 4 the distance of car B
If B takes 1 / 4 more time than a, then B's time = (1 + 1 / 4) a's time = 5 / 4 A's time
A's speed: B's speed = (5 / 4 / 1): (1 / 5 / 4) = 25:16
There are two workshops a and B. if 10 people are transferred from workshop a to workshop B, the number of people in the two workshops is exactly the same; if 20 people are transferred from workshop B to workshop a
Then the number of people in workshop a is just three times that of workshop B. how many people are there in each of the two workshops
Let B have X people, then a has x + 10 + 10 people
x+10+10+20=3(x-20)
x+40=3x-60
3x-x=40+60
2x=100
x=50
50 + 10 + 10 = 70 people
A: 70 in a and 50 in B
A and B buses leave from both places at the same time. After 5 hours, they meet at 30 kilometers away from the midpoint. How many kilometers does the slow train run 48 kilometers per hour and the fast train run? Let the express train run x kilometers per hour. The following equation is correct ()
A. 5x-48×5=30×2B. 5x-48×5=30C. 5x-30=48×5+30×2
Let the express train run x kilometers per hour & nbsp; 5x-48 × 5 = 30 × 2 & nbsp; & nbsp; & nbsp; & nbsp; 5x-240 = 605x-240 + 240 = 60 + 240 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 5x △ 5 = 300 △ 5 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 60 A: the express train runs 60 kilometers per hour
The distance between the two places is 1140km. A and B are going towards each other at the same time. They meet five hours later. The speed of a is nine tenths of that of B. how many kilometers is the speed of B?
Speed sum = 1140 △ 5 = 228km / h
B speed = 228 ÷ (1 + 9 / 10) = 120 km / h
1140÷5÷(1+9/10)
=228÷19/10
=120 km / h
B's speed is 1140 / 5 / (1 + 9 / 10) = 120 km
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Let B speed be XKM / h and a speed be 9 / 10x
5(x+9/10x)=1140
The solution is: x = 120
A: B's speed is 120km / h
When car a runs 37 km, car B runs 36 km. When car a arrives at place B, car B runs 710 km. How many km is the distance between two places?
A: the distance between AB and ab is 120 km
There are two workshops a and B. if 10 people are transferred from workshop a to workshop B, the number of people in the two workshops is equal. If 20 people are transferred from workshop B to workshop a, the number of people in workshop a is equal
There are two workshops a and B. if 10 people are transferred from workshop a to workshop B, the number of people in the two workshops is equal. If 20 people are transferred from workshop B to workshop a, the number of people in workshop a is three times that of workshop B. how many people are there in each workshop? There are x people in workshop a, y people in workshop B. X-10 = y + 10, X-Y = 20 (1)x+20=3(y-20) x-3y=-...
Let a have X people and B have y people
x-10=y+10
x+20=3(y-20)
x=70,y=50
A and B buses leave from two places at the same time, and meet at 30 kilometers from the midpoint after 5 o'clock. The express train travels 80 kilometers per hour, and the local train travels how many kilometers per hour
Because we met at the distance of 30 km from the midpoint, the express train went more than the local train
30 * 2 = 60 (km)
Walk more every hour:
60 / 5 = 12 (km)
80 km / h for express train and 80 km / h for local train
80-12 = 68 (km)