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The number of female workers in a factory is 4 less than 3 / 5 of the total number of workers, and there are 36 male workers?
There are 80 workers in the factory
The method is as follows:
Suppose there are x employees in the whole field, and the equation is
（3／5）X—4+36=X
32=（2／5）X
X=80
There were 500 workers in a factory, of which 25 were women workers. This year, another batch of women workers were recruited. At this time, the number of women workers accounted for 23 of the total number of workers in the factory. How many women workers were recruited this year?
500 × 25 = 200 (person), 500-200 = 300 (person), 300 ／ (1-23) = 900 (person), 900-300 = 600 (person), 600-200 = 400 (person); a: 400 female workers will be recruited this year
There are 450 workers in the factory, 36% of them are women workers. Now another batch of women workers are added. At this time, the number of women workers accounts for 40% of the total workers in the factory. Now there are workers in the factory
480 it can be seen from the question that there are 450 male workers * (1-36%) = after more than 288 recruitment, male workers account for 1-40% = 60% of the total number, so the total number is 288 divided by 60%, and 480 people will be obtained
The first car transported 30 tons more than the second car, the third car transported 20 tons less than the second car, and the first car transported goods______ Tons
If the first vehicle carries x tons of goods, the second vehicle will be (X-30) tons, and the third vehicle (x-30-20) will be (x-50) tons (x-50) tons (X-30) + (X-30) + (X-30) + (X-30) + (X-30) + (x-50) (x-50) (x-50) (x-50) (x-50) (X-30) + (X-30) + (X-30) + (X-30) + (x-50) (x-50) = 910, and the & nbsp; & nbsp & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp & nbsp; & nbsp & nbsp & nbsp & nbsp; & & nbsp; & nbsp & nbsp & nbsp & nbsp & nbsp; & & nbsp & nbsp & nbsp & nbsp; & & nbsp & nbsp & nbsp; & & nbsp & nbsp & nbsp; & & nbsp & nbsp & nbsp; & & nbsp & nbsp & nbsp & nbsp & nbsp & nbsp; & & nbsp & nbsp; & & nbsp & nbsp & nbsp & nbsp; & & nbsp; &A: the first car carried 340 tons of goods
Workshop a is 75% of workshop B's population. 10 people are transferred from workshop B to workshop A. at this time, workshop a is 80% of workshop B's population. How many people are there in the original two workshops?
Would you please use the solution of the equation?
The key to this problem is to find an equivalent relationship: the original, workshop a + 10 = (workshop B - 10) x 80% suppose that the original workshop B has x people, workshop a has 75% x people. 75% x + 10 = (x - 10) x [multiplication number] 80% 0.75 x + 10 = 0.8x - 8 10
The answers are as follows:
1. At the beginning, a: B = 3:4
2. After transfer, a: B = 4:5
3. The total number of people remains unchanged, so
A: B = 27:36
B: a = 35
That means 10 people are one share
4. Original workshop a = 270 people, workshop B = 360 people
It turns out that workshop a is the largest number of people in the two workshops
75% △ 1 + 75% = 3 / 7
At present, the number of people in workshop a is one third of the total number of people in the two workshops
80 (1 + 80%) = 4 / 9
There were two workshops in common
10 (4 / 9-3 / 7) = 630 (person)
It turns out that workshop a has
630 × 3 / 7 = 270 (person)
It turns out that workshop B has
630-270 = 360
It turns out that workshop a is the largest number of people in the two workshops
75% △ 1 + 75% = 3 / 7
At present, the number of people in workshop a is one third of the total number of people in the two workshops
80 (1 + 80%) = 4 / 9
There were two workshops in common
10 (4 / 9-3 / 7) = 630 (person)
It turns out that workshop a has
630 × 3 / 7 = 270 (person)
It turns out that workshop B has
630-270 = 360
linear equation in two unknowns
On the map with a scale of 1:6000000, the distance between the two places is 9cm. Two trains leave from the two places at the same time. Car a runs 57km per hour, car B runs 43km per hour. How many hours is the distance between the two trains 40km?
The distance between the two places is: 9 △ 16000000, = 9 × 6000000, = 54000000 (CM), 54000000 cm = 540km, the meeting time is: (540-40) △ 57 + 43, = 500 △ 100, = 5 (hours); a: after 5 hours, the two cars are 40 km apart
A and B two cars are running from ab at the same time. They meet at 5km away from the midpoint. It is known that the speed of a car is 6 / 7 of that of B car. How many kilometers is the distance between AB and B
Let's set the whole journey as 2x km. Because B is fast, when we meet, a walks (X-5) km and B walks (x + 5) km
The distance ratio equals the speed ratio, so
（x－5）：（x+5）＝6：7
So 7x-35 = 6x + 30
x＝65
So the whole journey is 2x = 2 × 65 = 130 km
Answer
The speed ratio is 6:7
Car B takes 5 × 2 = 10 km more than car a
So AB is (6 + 7) * 10 / (7-6) = 130 km
5*2=10
10/(1-6/7)=70
70*6/7=60
60+70=130
5*2*（6+7）=130
Less time to meet, no answer
Each car can carry 180 tons of goods per day. If you add 9 more cars, how many tons of goods can be carried per day
1:180=9：x
1x=1620
1x÷1=1620÷1
x=1620
A: it can transport 1620 tons per day
If 10 people are transferred from workshop a to workshop B, the number of people in workshop B is 75% of that in workshop A. if 10 people are transferred from workshop B to workshop a
Then the ratio of workshop a to workshop B is 5:2. How many workers are there in the original workshop?
Let a have X and B have y
(x-10)75%=y+10
(x+10):(y-10)=5:2
The solution is x = 40, y = 30
Total number 40 + 30 = 70
If there are x persons in workshop a and Y persons in workshop B, then
Y+10=（x-10)75%
(X+10)/(Y-10)=5/2
The solution is x = 90, y = 50
On the map with a scale of 1:6000000, the distance between the two places is 5cm. The two cars run from each other at the same time, and they meet three hours later. It is known that the speed ratio of the two cars is 2:3. How many kilometers is the speed of the two cars?
5 △ 16000000 = 30000000 (CM) = 300 (km), 300 △ 3 = 100 (km), 100 × 22 + 3 = 40 (km), 100-40 = 60 (km); a: the speed of car a is 40 km / h, and that of car B is 60 km / h
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