There are 1458 students in a middle school. Among them, the number of female students is 20% less than that of male students. How many are there for male and female students?

There are 1458 students in a middle school. Among them, the number of female students is 20% less than that of male students. How many are there for male and female students?

Male = 1458 ÷ (1 + 1-20%) = 810
Female = 1458-810 = 648
Do not understand can ask, help please adopt, thank you!
The average number of a, B and C is 19. The ratio of a to B is 3:2, and the ratio of B to C is 3:2. What are the numbers of a, B and C?
The sum of three numbers: 19 × 3 = 57, a: B: C = (3 × 3): (3 × 2): (2 × 2) = 9:6:4, 9 + 6 + 4 = 19, a: 57 × 919 = 27, B: 57 × 619 = 18, C: 57 × 419 = 12
The ratio of male to female in the fifth grade of a school is 5:4. There are 20 more male students than female students. How many female students are there?
A: there are 80 girls
There are three natural numbers a, B and C. The sum of a and B is 120; the sum of B and C is 150. It is known that a is four seventh of C, and C is?
150-120 = 30 (subtract B from sum, and subtract a from C)
30÷（7-4）×7=70
C is 70
Let C be X
A is 4 / 7X
B is 150-x
Then: 4 / 7X + (150-x) = 150-3 / 7X = 120
3/7X=30
X=70
There are 94 students in class 51, of which the number of boys is 20% less than that of girls. How many boys and girls are there in this class?
The number of class 51 is 54. I'm careless and wrong. Please understand
Binary once
Boys x girls y
X+Y=54
Y * 0.8 = x (the number of boys is 20% less than that of girls, that is, the number of boys is 80% of that of girls)
X=24
Y=30
30 girls
24 boys
One yuan a time
Girl y
Y+Y*0.8=54
Y=30
The number of boys is the total minus the number of girls: 54-30 = 24
30 girls
24 boys
Number a accounts for three seventh of the sum of two numbers B and C, and number C accounts for four fifths of the sum of two numbers a and B. It is known that number B is 114, and what is the sum of three numbers a, B and C
Let a be a, B be B, and C be c
（B+C）*3/7=A
(A+B)*4/5=C
Substituting B = 114, so:
（114+C）*3/7=A
(A+114)*4/5=C
This will solve it, calculate the value of AC, and then add 114, OK
There are 25 boys and 20 girls in a class. What percentage of the class are boys and girls?
Male: 55.6% (25 / (25 + 20) X100%)
Female: 44.4% (20 / (25 + 20) X100%)
Three fifths of the number a is one fourth of the sum of the two numbers a and B. what is the ratio of the two numbers a and B?
A is the sum of a and B
1 / 4 △ 3 / 5 = 5 / 12
B is the sum of a and B
5 out of 12 = 7 out of 12
What is the ratio of a and B
5:12:7 = 5:7
5 / 7 equation 3 / 5 × x = (x + y) × 1 / 4
After calculation, X / y = 5 / 7
0.6 vs. 0.25 = 60 vs. 25 = 12 vs. 5
There were 10 more boys than girls on the field. Then boys decreased by one fourth and girls by one sixth, and the remaining men and women were equal
How many people are playing?
Suppose the number of girls x boys x + 10 (1-0.25) * (x + 10) = (1-1 / 6) x, the solution is x = 90 x + 10 = 100
The total number is 190
Three numbers of a, B and C, a is 3 / 7 of the sum of two numbers of B and C, C is 4 / 5 of the sum of two numbers of a and B, and B is 115?
115/(1-3/10-4/9)=450
A is 3 / 7 of the sum of two numbers of B and C, a is three, B and C are seven, three are ten, a is 3 / 10 of three. Similarly, C is 4 / 9 of three
Four hundred and fifty