The school held the track and field games. 32 people participated in the fourth grade and 126 people participated in the sixth grade, 6 less than the total number of people in the fourth and fifth grades, Equation!

The school held the track and field games. 32 people participated in the fourth grade and 126 people participated in the sixth grade, 6 less than the total number of people in the fourth and fifth grades, Equation!

Suppose there are x people in Grade 5, 2 (32 + x) - 6 = 126 64 + 2x = 126 + 6 2x = 132-64 2x = 68 x = 34 A: there are 34 people in Grade 5 who take part in the checking calculation: 2 (32 + 34) - 6 = 64 + 68-6 = 13
There are three numbers a, B and C. the number a is one third of the sum of B and C, the number B is one second of the sum of a and C, and the number C is the sum of a, B and C
The total number of a and C is 1 / 4
B is 1 / (2 + 1) = 1 / 3 of the total
C is 1-1 / 4-1 / 3 of the total number = 5 / 12
There are 48 students in class 1 of grade 5, planting 99 trees in total, and 42 students in class 2 of grade 5, planting 126 trees in total
(99 + 126) / (48 + 42) = 2.5 ≈ 3 trees
Each of the two classes planted three trees on average
A, B and C jointly process 180 parts. The number of parts processed by a is half of that processed by B and C, and the number processed by B is one third of that processed by a and C. how much does C process
A accounts for all = 1 / 2 (1 + 1 / 2) = 1 / 3
B = 1 / 3 (1 + 1 / 3) = 1 / 4
C = 180 × (1-1 / 3-1 / 4) = 75
The number of a is half of that of B and C, and a accounts for 1 / 3 of the total
B processes one third of a and C, and B accounts for 1 / 4 of the total
So C is:
180x(1-1/3-1/4)
=180x5/12
=75
A processes 1 / 2 of the total number (1 + 1 / 2) = 1 / 3
Party B processes 1 / 3 of the total number (1 + 1 / 3) = 1 / 4
So 1-1 / 3-1 / 4 = 5 / 12 of the total
So 180 × 5 / 12 = 75 pieces
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There are 180 students in the fifth grade, 15 more in the sixth grade than in the fifth grade,
Explain the reason carefully
180×5/9+15
=100+15
=115
A: there are 115 students in grade six
Three people of a, B and C process 180 parts, one-half of that of B and C, and one-third of that of a and C. how much do three people process?
I'm a child. Can I use a simple way that I can understand.
180 * 1 / (1 + 2) = 60 (pieces) ···· a
180 * 1 / (1 + 3) = 45 (pieces) ···· B
180-60-45 = 75
A: 60
B: 45
C: 75
180/3=60___ nail
180/4=45___ B
180-60-45=75__ C
180/3=60___ nail
180/4=45___ B
180-60-45=75__ C
Let a be x, B be y and C be Z
X=1/2(Y+Z)
Y=1/3(X+Z)
X+Y+Z=180
The solution is x = 60, y = 45, z = 75
2x=y+z
3y=x+z
x+y+z=180
There are 180 students in the fifth grade, 15 more than 5 / 9 of the sixth grade. How many students are there in the sixth grade?
Math master answer, because I saw others and I the same question, but the answer is different, please master answer
(180-15) △ 5 / 9 = 165 × 9 / 5 = 297 (person)
There are three numbers a, B and C. the known number a is one fifth of the sum of the two numbers B and C. the number B is one half of the sum of the two numbers a and C. the number C is 30. What are the two numbers a and B?
A is the total number: 1 / 5 (1 / 5 + 1) = 1 / 6
B is the total number: 1 / 2 (1 / 2 + 1) = 1 / 3
C is total: 1-1 / 6-1 / 3 = 1 / 2
The sum of the three numbers of a, B and C is 30 △ 1 / 2 = 60
A: 60 × 1 / 6 = 10
B: 60 × 1 / 3 = 20
There are 120 students in grade five, 25% more in grade six than in grade five,
120 * (1 + 25%) = 150 (persons)
There are three numbers a, B and C. B knows that a is the sum of two numbers B and C, 1 / 5. B is the sum of two numbers a and C, 1 / 2. C is 30. What are the two numbers a and B?
There are three numbers a, B and C. B knows that a is 1 / 5 of the sum of the two numbers B and C, B is 1 / 2 of the sum of the two numbers a and C, C is 30. What are the two numbers a and B?
Total 30 △ 1-1 / (1 + 5) - 1 / (1 + 2)]
=30÷【1-1/6-1/3】
=30÷1/2
=60
A 60 × 1 / (1 + 5) = 60 × 1 / 6 = 10
B 60 × 1 / (1 + 2) = 60 × 1 / 3 = 20