The school held the track and field games. 32 people participated in the fourth grade and 126 people participated in the sixth grade, 6 less than the total number of people in the fourth and fifth grades, Equation!
Suppose there are x people in Grade 5, 2 (32 + x) - 6 = 126 64 + 2x = 126 + 6 2x = 132-64 2x = 68 x = 34 A: there are 34 people in Grade 5 who take part in the checking calculation: 2 (32 + 34) - 6 = 64 + 68-6 = 13
There are three numbers a, B and C. the number a is one third of the sum of B and C, the number B is one second of the sum of a and C, and the number C is the sum of a, B and C
The total number of a and C is 1 / 4
B is 1 / (2 + 1) = 1 / 3 of the total
C is 1-1 / 4-1 / 3 of the total number = 5 / 12
There are 48 students in class 1 of grade 5, planting 99 trees in total, and 42 students in class 2 of grade 5, planting 126 trees in total
(99 + 126) / (48 + 42) = 2.5 ≈ 3 trees
Each of the two classes planted three trees on average
A, B and C jointly process 180 parts. The number of parts processed by a is half of that processed by B and C, and the number processed by B is one third of that processed by a and C. how much does C process
A accounts for all = 1 / 2 (1 + 1 / 2) = 1 / 3
B = 1 / 3 (1 + 1 / 3) = 1 / 4
C = 180 × (1-1 / 3-1 / 4) = 75
The number of a is half of that of B and C, and a accounts for 1 / 3 of the total
B processes one third of a and C, and B accounts for 1 / 4 of the total
So C is:
180x(1-1/3-1/4)
=180x5/12
=75
A processes 1 / 2 of the total number (1 + 1 / 2) = 1 / 3
Party B processes 1 / 3 of the total number (1 + 1 / 3) = 1 / 4
So 1-1 / 3-1 / 4 = 5 / 12 of the total
So 180 × 5 / 12 = 75 pieces
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There are 180 students in the fifth grade, 15 more in the sixth grade than in the fifth grade,
Explain the reason carefully
180×5/9+15
=100+15
=115
A: there are 115 students in grade six
Three people of a, B and C process 180 parts, one-half of that of B and C, and one-third of that of a and C. how much do three people process?
I'm a child. Can I use a simple way that I can understand.
180 * 1 / (1 + 2) = 60 (pieces) ···· a
180 * 1 / (1 + 3) = 45 (pieces) ···· B
180-60-45 = 75
A: 60
B: 45
C: 75
180/3=60___ nail
180/4=45___ B
180-60-45=75__ C
180/3=60___ nail
180/4=45___ B
180-60-45=75__ C
Let a be x, B be y and C be Z
X=1/2(Y+Z)
Y=1/3(X+Z)
X+Y+Z=180
The solution is x = 60, y = 45, z = 75
2x=y+z
3y=x+z
x+y+z=180
There are 180 students in the fifth grade, 15 more than 5 / 9 of the sixth grade. How many students are there in the sixth grade?
Math master answer, because I saw others and I the same question, but the answer is different, please master answer
(180-15) △ 5 / 9 = 165 × 9 / 5 = 297 (person)
There are three numbers a, B and C. the known number a is one fifth of the sum of the two numbers B and C. the number B is one half of the sum of the two numbers a and C. the number C is 30. What are the two numbers a and B?
A is the total number: 1 / 5 (1 / 5 + 1) = 1 / 6
B is the total number: 1 / 2 (1 / 2 + 1) = 1 / 3
C is total: 1-1 / 6-1 / 3 = 1 / 2
The sum of the three numbers of a, B and C is 30 △ 1 / 2 = 60
A: 60 × 1 / 6 = 10
B: 60 × 1 / 3 = 20
There are 120 students in grade five, 25% more in grade six than in grade five,
120 * (1 + 25%) = 150 (persons)
There are three numbers a, B and C. B knows that a is the sum of two numbers B and C, 1 / 5. B is the sum of two numbers a and C, 1 / 2. C is 30. What are the two numbers a and B?
There are three numbers a, B and C. B knows that a is 1 / 5 of the sum of the two numbers B and C, B is 1 / 2 of the sum of the two numbers a and C, C is 30. What are the two numbers a and B?
Total 30 △ 1-1 / (1 + 5) - 1 / (1 + 2)]
=30÷【1-1/6-1/3】
=30÷1/2
=60
A 60 × 1 / (1 + 5) = 60 × 1 / 6 = 10
B 60 × 1 / (1 + 2) = 60 × 1 / 3 = 20