We know that two equal triangles corresponding to the opposite angles of two sides and one of them are not necessarily congruent. Under what circumstances will they be congruent? (1) Read and prove: for these two triangles are right triangles, obviously they are congruent. For these two triangles are obtuse triangles, we can prove that they are congruent (the proof is omitted). For these two triangles are acute triangles, they are also congruent, we can prove as follows: it is known that △ ABC, △ a1b1c1 are acute triangles, ab = A1B1, BC = b1cl, ∠ C = ∠ CL Proofs: △ ABC ≌ △ a1b1c1. (please complete the following proofs.) proofs: BD ⊥ Ca in D, b1d1 ⊥ c1a1 in D1 respectively through points B and B1. Then ∠ BDC = ∠ b1d1c1 = 90 °, ≌ - BC = b1c1, ∠ C = ∠ C1, ≌ △ BCD ≌ △ b1c1d1, ≌ BD = b1d1. (2) induction and Narration: a correct conclusion can be obtained from (1), please write this conclusion

We know that two equal triangles corresponding to the opposite angles of two sides and one of them are not necessarily congruent. Under what circumstances will they be congruent? (1) Read and prove: for these two triangles are right triangles, obviously they are congruent. For these two triangles are obtuse triangles, we can prove that they are congruent (the proof is omitted). For these two triangles are acute triangles, they are also congruent, we can prove as follows: it is known that △ ABC, △ a1b1c1 are acute triangles, ab = A1B1, BC = b1cl, ∠ C = ∠ CL Proofs: △ ABC ≌ △ a1b1c1. (please complete the following proofs.) proofs: BD ⊥ Ca in D, b1d1 ⊥ c1a1 in D1 respectively through points B and B1. Then ∠ BDC = ∠ b1d1c1 = 90 °, ≌ - BC = b1c1, ∠ C = ∠ C1, ≌ △ BCD ≌ △ b1c1d1, ≌ BD = b1d1. (2) induction and Narration: a correct conclusion can be obtained from (1), please write this conclusion

B, B1, B1, and b1d1 ⊥ Ca in D, and b1d1 c1a1in D1. Then, the {BDC = b1d1c1 = 90 °, \8780;≌ ≌ ≌ b1c1c1d1d1, pointb, B1, B1, B1, B1, B1, b1d1 c1a1in D1. Then \\\58; BDC = b1d1d1c1c1c1c1c1 = 90 °, then {BDC \: BDC = ≌≌≌≌ a1d1d1d1d1b1 (HL), \\\\\\\\\\\\\\\= c1bc (2) if two triangles (△ ABC, △ a1b1c1) are acute angle triangles or right angle triangles or obtuse angle triangles, they are congruent (AB = A1B1, BC = b1c1, ∠ C = ∠ C1, then △ ABC ≌ △ a1b1c1)
Natural numbers can be divided into ()
A. Odd and even B. prime and composite C. prime, composite, 0 and 1
Natural numbers can be divided into even numbers and odd numbers according to whether they are multiples of 2
Are two equal triangles corresponding to the diagonal of two sides and one of them congruent
In this way, we can also take the total angle of a triangle as an example, and we can make sure that B C is not equal to the center of a triangle
Unequal
Although two sides are equal, the diagonal correspondence of one side is not equal
Natural number, decimal, fraction, integer, integer, negative number, factor, composite number, prime number, even number, odd number, percentage, multiple, greatest common factor
The least common multiple, as well as the characteristics of multiples of 2, 3, 5, 7 and 11, please be brief and not too complicated. I will increase the reward for wealth
In front of those natural numbers, decimals and so on, are to their definition
Natural numbers: like 0,1,2,3,4 The number represented
Decimal: a number consisting of an integral part, a decimal part, and a decimal point
Fraction: the unit "1" is divided into several parts equally, which means that such a number or parts is called fraction
Integers: numbers like - 2, - 1,0,1,2 are called integers
Negative number: smaller than zero（
Are two triangles congruent if the diagonals of the two sides and one side of the two triangles are equal?
If not, hope to write counter examples
If it's right, please write the reason
not always
For triangle ABC, take point D on BC so that ad = ab,
For triangle ABC and triangle ADC
There are: ab = ad
AC=AC
∠C=∠C
But it is obvious that triangle ABC and triangle ADC are not equal
Natural numbers include prime numbers, composite numbers and 1______ .
Natural number should include 0, prime number, composite number and 1, so the original answer is wrong
Two equal triangles corresponding to the diagonals of two sides and one side are not necessarily congruent counterexamples
Power, base (), exponent (), which can be expressed by letters as the n-th power of (m-th power of a) = () (M and N are all positive integers)
The power, base (constant), exponent (multiplication) can be expressed by letters as the n power of (m power of a) = (a ^ Mn) (M and N are all positive integers)
Why is it impossible to prove congruence for two triangles whose opposite angles of two sides and one of them are equal?
Congruence can only be proved if the angle is a right angle
In addition, if the diagonal is obtuse, can we prove congruence? I can't give a counter example, that is to say, I think it is proved to be congruent, but actually there is no such theorem. So why?
It's really impossible to prove congruence. Take a point on an edge of an acute angle as the center of the circle and draw an arc with a compass. You can have two focal points with the other edge. Connecting the center of the circle and the two focal points, two triangles will appear. They will satisfy that the diagonal correspondence between the two sides and one side is equal, and they are not congruent. If it's an obtuse angle, it should be able to prove congruence. I'm not sure about that
How to multiply with exponential power
One third power of 2 times one third power of 3
a^c*b^c=(ab)^c
The derivation process is as follows
Example: (2 ^ 3) * (3 ^ 3)
=(2*2*2)*(3*3*3)
=(2*3)(2*3)(2*3)
=(2*3)^3
Ha ha, come on! If you have any questions you don't understand, please answer sincerely!