x3+y3+z3-3xyz x8+x6+x4+x2+1

x3+y3+z3-3xyz x8+x6+x4+x2+1

1、x^3+y^3+z^3-3xyz = (x^3+3yx^2+3xy^2+y^3)+z^3-3xyz-3yx^2-3xy^2 = (x+y)^3+z^3-3xy(x+y+z) = (x+y+z)[(x+y)^2-(x+y)z+z^2]-3xy(x+y+z) = (x+y+z)[(x^2+2xy+y^2-xz-yz+z^2)-2xy] = (x+y+z)(x^2+y^2+z^2-xy-yz-zx...
5x + 2 = 3x, what is x equal to
5x+2=3x
5x-3x=-2
2x=-2
x=-1
-1
Transform 5x-3x = - 2
2X=-2
X=-1
Given a ^ 2 + B ^ 2 + C ^ 2-4a + 4B BC ≤ 17, what is the value of a + B + C
Here's a formula: a square + b square + 2Ab = (a + b) square
According to this
Assign the above questions
I believe you can
(1-A & # 178;) (1-B & # 178;) - 4AB 2x & # 178; + 4xy + 2Y & # 178; - x-y-11 + X & # 178; - Y & # 178; - 2x + 2yz 12x & # 178; + 11xy-15y & # 178; - 30x + 8y + 12a's fourth power + A & # 178; B & # 178; + B's fourth power
① (1-a²)(1-b²)-4ab=1-a²-b²+a²b²-4ab=1-2ab+a²b²-(a²+b²+2ab)=(1-ab)²-(a+b)²=(1-ab-a-b)(1-ab+a+b)② 2x²+4xy+2y²-x-y-1=2(x+y)²-(...
5x-3x = 1 what is x equal to?
5x-3x=1
x =1\2
x=0.5
5x-3x=1
2x=1
x=1/2
a half
Zero point five
5x-3x=1
2x=1
x=1/2
Given that a and B satisfy A2 + 4A + b2-12b + 40 = 0, the value of a · B is obtained
That is, (A & # 178; + 4A + 4) + (B & # 178; - 12b + 36) = 0
(a+2)²+(b-6)²=0
So a + 2 = B-6 = 0
a=-2,b=6
So AB = - 12
(a^2+4a+4)+(b^2-12b+36)=0
(a+2)^2+(b-6)^2=0
Because (a + 2) ^ 2 > = 0, (B-6) ^ 2 > = 0 equals zero if and only if a = - 2, B = 6
a*b=-12
Factorization of quadratic equation of one variable
When the coefficient of quadratic term is not 1, how to decompose the factor without simplification, thank you, for example
Example: 2x ^ 2 + 3x + 1 = 0
The cross multiplication in factorization is used
X 1
2x 1
_______
2x+x=3x
It is decomposed into (x + 1) (2x + 1) = 0
x1=-1,x2=-1/2
Take 2Y + 1 as a whole
15 can be divided into (- 3) * (- 5)
（2Y+1-3）*（2Y+1-5）=0
（2Y-2）*（2Y-4）=0
Y = 1 or 2
Ax ^ 2 + BX + C = a (x-x1) (x-x2) (X1 and X2 are two solutions of the equation respectively.)
For example: 2x ^ 2-5x-3 = 2 (x-3) (x + 0.5) = (x-3) (2x + 1)
Example: 2x-6y-3
2 (Y-2 / 3 + radical 17) (Y-2 / 3-radical 17)
process
First calculate △ =...
Then we take △ into the - B of 2A ± root sign △ of 2A
Then we extract the coefficient × (unknowns - 2A - B + radical △) (unknowns - 2A - B - radical △)
What is 5x + 2 = 100 + 3x
Forty-nine
Given a + B = 17, A-B = - 7, find the value of 3-573?
Will the elder brother elder sister. Uncle aunt. And uses
A + B = 17, so a = 17-b
a-b=-7,17-b-b=-7
The solution is b = 12, a = 17-b = 5
3（a2+b2）-573=3*（5*5+12*12）-573=-66
A + B = 17, A-B = - 7, find out that a is 5, B is 12. Then calculate it
A + B + A-B = 2A = 10, so a = 5, so 5 + B = 17, so B = 12
3(2*5+12*2)-573=-471
The answer is - 66
Quadratic equation of one variable [factorization method]
（2x-1）^2-1=0
（3x+8）^2-(2x-3)^2=0
y(y-2)=3
（x-1）（x+2）=10
1、
(2x-1+1)(2x-1-1)=0
2x(2x-2)=0
4x(x-1)=0
x=0,x=1
2、
(3x+8+2x-3)(3x+8-2x+3)=0
(5x+5)(x+11)=0
5(x+1)(x+11)=0
x=-1,x=-11
3、
y²-2y-3=0
(y-3)(y+1)=0
y=3,y=-1
4、
x²+x-2-10=0
x²+x-12=0
(x+4)(x-3)=0
x=-4,x=3
(1)2x(2x-2)=0
X = 0 or 1
(2)(5x+5)(x+11)=0
X = - 1 or - 11
(3)(y-3)(y+1)=0
Y = 1 or 3
(4)(x+4)(x-3)=0
X = 3 or - 4
(1)4x²-4x+1-1=4x(x-1)
x=1,0
(2)9x²+48x+64-4x²+12x-9
=5x²+60x+55
=(5x+5)(x+11)
x=-1,-11
(3)y²-2y-3
=(y-3)(y+1)
y=-1,3
(4)x²+x-12
(x+4)(x-3)
x=-4,3
（2x-1）^2-1=0
（2x-1+1）（2x-1-1）=0
2x(2x-2)=0
4x(x-1)=0
x(x-1)=0
X = 0 or x = 1
（3x+8）^2-(2x-3)^2=0
（3x+8+2x-3)（3x+8-2x+3)=0
（5x+5)（x+11)=0
5（x+1)（x+11)=0
（x+1)（x+11)=0