Solving the problem of factorization in junior two 1.(a-b)+2m(a-b)-m²（b-a） 2.125a²（b-1）-100a(1-b) 3.1/4m⁴+2m²n+4n² 4.-a⁴+2a²b²-b⁴ 5.25(3x-y)²-36(3x+y)² 6.a³-2a²+a-1 Excuse me. Thank you! I didn't understand you in class, so please ask me!

Solving the problem of factorization in junior two 1.(a-b)+2m(a-b)-m²（b-a） 2.125a²（b-1）-100a(1-b) 3.1/4m⁴+2m²n+4n² 4.-a⁴+2a²b²-b⁴ 5.25(3x-y)²-36(3x+y)² 6.a³-2a²+a-1 Excuse me. Thank you! I didn't understand you in class, so please ask me!

The answers are: 1. (a-b) (1 + 2m + m ^ 2) 2. (B-1) (125A ^ 2 + 100a) 3. (1 / 2m ^ 2 + 2n) ^ 24. (a ^ 2-B ^ 2) ^ 25. (5 (3x-y)) ^ 2 - (6 (3x + Y0) ^ 2 = (15x-5y) ^ 2 - (18x-6y) ^ 2 = (15x-5y + 18x-6y) (15x-5y-18x + 6y) = (33x-11y) (y-3x) 6. A (A-1) ^ 2-1
1 =(a-b)(1+2m+m^2)
=(a-b)(m+1)
2 = -a(125a+100)(1-b)
3 =(0.5m^2)^2+2m^2n+4n^2
=[(root 2 / 2) m ^ 2 + 2n] ^ 2
zhijizuoba
1) Extract the common factor A-B, the original formula = (a-b) [1 + 2m + m ^ 2] = (a-b) (M + 1) ^ 2
2) Extract the common factor 25A (B-1), the original formula = 25A (B-1) (5a + 4)
3) This is the complete square formula, the original formula = (1 / 2 * m ^ 2 + 2n) ^ 2
4) Extract the negative sign, which is the complete square formula, the original formula = - (a ^ 2-B ^ 2) ^ 2 = - (a + b) ^ 2 (a-b) ^ 2,
5) Square difference formula, the original formula = [5 (3x-y) + 6 (3x +... Expansion
1) Extract the common factor A-B, the original formula = (a-b) [1 + 2m + m ^ 2] = (a-b) (M + 1) ^ 2
2) Extract the common factor 25A (B-1), the original formula = 25A (B-1) (5a + 4)
3) This is the complete square formula, the original formula = (1 / 2 * m ^ 2 + 2n) ^ 2
4) Extract the negative sign, which is the complete square formula, the original formula = - (a ^ 2-B ^ 2) ^ 2 = - (a + b) ^ 2 (a-b) ^ 2,
5) Square difference formula, original formula = [5 (3x-y) + 6 (3x + y)] [5 (3x-y) - 6 (3x + y)] = (33x + y) (- 3x-11y)
6) Maybe you copied the wrong question? A & # 179; - A & # 178; + A-1 = A & # 178; (A-1) + (A-1) = (A-1) (A & # 178; + 1) put away
Solve equation 15 + 8x + X & # 178; = 39
15+8x+x²=39
x²+8x+16=40
(x+4)²=40
x+4=±√40
x=-4±2√10
The quadratic power of polynomial 3a-2ab + 4B plus what is equal to the quadratic power of 2a-ab
(2a²-ab)-(3a²-2ab+4b²)
=2a²-ab-3a²+2ab-4b²
=-a²+ab-4b²
Chapter 14 multiplication and factorization of integers
The operation result of (the quadratic of 5x - the quadratic of 4Y) (- the quadratic of 5x + the quadratic of 4Y) requires the use of complete square formula
=-(5x²-4y²)²
=-(the fourth power of 25x-40x & # 178; Y & # 178; + the fourth power of 16y)
=-The fourth power of 25X + the fourth power of 40x & # 178; Y & # 178; - 16y
X & # 178; + 8x-33 = 0 solution with process velocity
Factorization in detail/~~
x^2+8x+16-16-33=0
(x+4)^2-7^2=0
x+4=7
X=3
Or x + 4 = - 7
x=-11
X²+8X-33=0
﹙x＋11﹚﹙x－3﹚=0
x1=－11, x2=3
X²+8X-33=0
(x+11)(x-3)=0
x1=-11,x2=3
(X-3)(X+11)=0
X=3,X=-11
X²+8X-33=0
（x+11）（x-3）=0
x+11=0 x-3=0
x1= -11 x2=3
x²+8x+16=49
(x+4)²=49
x+4=±7
x1=-11 x2=3
When the value of a is, the square + 2A + 2 of polynomial a gets the minimum value
RT
Square of a + 2A + 2
=a^2+2a+1+1
=(a+1)^2+1
A = - 1 min = 1
a²+2a+2
=a²+2a+1+1
=(a+1)²+1
The least square is 0
So when a + 1 = 0, there is a minimum
So a = - 1
Note a ^ is the square of a * and a * is cubic
-20x^yz-15xy^z+5xyz
(3a+2b)(2a-3b)+(a+5b)(3b-2a)
x(xy+yz+zx)-xyz
-a(b+c-1)-b(c+b-1)+(1-c-b)^
(a+1)^(2a-3)+(a+1)(3-2a)^-(a+1)(3-2a)
[[[[[[[[[[[to process]]]]]
Man, don't focus on the first question
Thank you. Because the pig is the first to have a full hair, I still have a few questions to solve in other questions
In the first step, we can get the square of = - 5xyz (4x + 3y-1) = [(3a + 2b) - (a + 5b)] (2a-3b) = (3a + 2b-a-5b) (2a-3b) = (2a-3b) (2a-3b) = (2a-3b) = (2a-3b); (3) = (x ^ y + XYZ + x ^ z-xyz = x ^ y + x ^ z = x ^ (y + Z); (4) = (B + C-1) (- a-b-1 + B + C) = (B + C-1)
Question 1 XYZ (- 20x-15y + 5)
Question 3 x ^ (y + Z)
-20x^yz-15xy^z+5xyz
=-5xyz(4x+3y-1)
(3a+2b)(2a-3b)+(a+5b)(3b-2a)
=(2a-3b)(3a+2b-a-5b)
=(2a-3b)(2a-3b)
x(xy+yz+zx)-xyz
=x^2y+xyz+x^2z-xyz
=x^2(y+z)
-A (B + C-1) - B (c + B-1)... Expansion
-20x^yz-15xy^z+5xyz
=-5xyz(4x+3y-1)
(3a+2b)(2a-3b)+(a+5b)(3b-2a)
=(2a-3b)(3a+2b-a-5b)
=(2a-3b)(2a-3b)
x(xy+yz+zx)-xyz
=x^2y+xyz+x^2z-xyz
=x^2(y+z)
-a(b+c-1)-b(c+b-1)+(1-c-b)^2
=-(b+c-1)(a-b+c+b-1)
=-(b+c-1)(a+c-1)
(a+1)^2(2a-3)+(a+1)(3-2a)^2-(a+1)(3-2a)
=(2a-3)[(a+1)^2+(a+1)(2a-3)+a+1]
=(2a-3)(a+1)(a+1+2a-2）
=(2a-3) (a + 1) (3a-1) fold up
1) -20x^yz-15xy^z+5xyz
=-5xyz(4x+3y+1)
2) (3a+2b)(2a-3b)+(a+5b)(3b-2a)
=(3a + 2b) (2a-3b) - (2a-3b) (a + 5b) (minus sign)
=(2a-3b) (3a + 2b-a-5b) (2a-3b)
=(2a-3b)^
3) X (XY + YZ + ZX... Expansion
1) -20x^yz-15xy^z+5xyz
=-5xyz(4x+3y+1)
2) (3a+2b)(2a-3b)+(a+5b)(3b-2a)
=(3a + 2b) (2a-3b) - (2a-3b) (a + 5b) (minus sign)
=(2a-3b) (3a + 2b-a-5b) (2a-3b)
=(2a-3b)^
3)x(xy+yz+zx)-xyz
=x^y+xyz+x^z-xyz
=x(xy+yz+xz-yz)
=x(xy+xz)
=x^(y+z)
4)-a(b+c-1)-b(c+b-1)+(1-c-b)^
=-a(b+c-1)-b(b+c-1)+(b+c-1)^
=(b+c-1)(-a-b+b+c-1)
=(b+c-1)(-a+c-1)
5)(a+1)^(2a-3)+(a+1)(3-2a)^-(a+1)(3-2a)
=(a+1)(2a-3)[(a+1)+(2a-3)+1]
=(a+1)(2a-3)(3a-1)
High quality, high speed, the pursuit of adoption rate don't divide
The method of quoting factor is used
-20x^yz-15xy^z+5xyz
=5xyz(-4x-3y+1)
(3a+2b)(2a-3b)+(a+5b)(3b-2a)
=[(3a+2b)-(a+5b)](2a-3b)
=(3a+2b-a-5b)(2a-3b)
=(2a-3b)(2a-3b)
=(2a-3b)^
X (XY + YZ + ZX) - XYZ = x ^ y + XYZ... Expansion
The method of quoting factor is used
-20x^yz-15xy^z+5xyz
=5xyz(-4x-3y+1)
(3a+2b)(2a-3b)+(a+5b)(3b-2a)
=[(3a+2b)-(a+5b)](2a-3b)
=(3a+2b-a-5b)(2a-3b)
=(2a-3b)(2a-3b)
=(2a-3b)^
x(xy+yz+zx)-xyz=x^y+xyz+x^z-xyz=x^(y+z)
-a(b+c-1)-b(c+b-1)+(1-c-b)^
=-a(b+c-1)-b(c+b-1)+(b+c-1)^
=(b+c-1)(a-b+b+c-1)
=(b+c-1)(a+c-1)
(a+1)^(2a-3)+(a+1)(3-2a)^-(a+1)(3-2a)
=(a+1)(3-2a)[-(a+1)+(3-2a)-1]
=(a + 1) (1-3a) fold up
When the equation x2 + 6x-16 = 0 is solved by the collocation method, the original equation should be transformed into ()
A. （x-3）2=25B. （x+3）2=25C. （x-6）2=55D. （x+6）2=52
The formula is: x2 + 6x + 9 = 25, that is, (x + 3) 2 = 25, so B is chosen
There is a question: a polynomial divided by - 2A, Xiaoxue mistakenly took the multiplication calculation, the result is 4a3-12a2. Then what is the correct result?
The result should be correct for (2a) - 2A = (2 a) - 6A
A total of 100 factoring problems in eighth grade mathematics volume 1
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