Ask some math questions about factorization 1. A & # 178; - B & # 178; + AC + BC = () (factorization) 2. First factorize, then evaluate: (9x & # 178; + 12xy + 4Y & # 178;) - (2x-3y) &# 178;, where x = 4 / 5, y = - 1 / 5 3. Given X & # 178; + Y & # 178; - 4x + 6y + 13 = 0, find the value of X and y

Ask some math questions about factorization 1. A & # 178; - B & # 178; + AC + BC = () (factorization) 2. First factorize, then evaluate: (9x & # 178; + 12xy + 4Y & # 178;) - (2x-3y) &# 178;, where x = 4 / 5, y = - 1 / 5 3. Given X & # 178; + Y & # 178; - 4x + 6y + 13 = 0, find the value of X and y

1. A & # 178; - B & # 178; + AC + BC = () (factorization is required) = (a + b) (a-b) + C (a + b) (a-b + C) 2. Factorization first, then evaluation: (9x & # 178; + 12xy + 4Y & # 178;) - (2x-3y) &# 178;, where x = 4 / 5, y = - 1 / 5. (9x & # 178; + 12xy + 4Y & # 178;) - (2x
Original formula = (a + b) (a-b) + (a + b) C = (a + b) (a-b + C) original formula = (3x + 2Y) & # 178; - (2x-3y) & # 178; = (3x + 2Y + 2x-3y) (3x + 2y-2x + 3Y) = (5x-y) (x + 5Y) = (21 / 5) (- 1 / 5) = - 21 / 25 (X-2) & # 178; + (y + 3) & # 178; = 0; X = 2. Y = - 3
1. The original formula = (a + b) (a-b) + C (a + b) = (a + b) (a-b + C)
2. Original formula = (3x + 2Y) ^ 2 - (2x-3y) ^ 2 = (3x + 2Y + 2x-3y) (3x + 2y-2x + 3Y) = (5x-y) (x + 5Y)
X = 4 / 5, y = - 1 / 5. The results show that: (5x-y) (x + 5Y) = (4 + 1 / 5) (4 / 5-1) = - 21 / 25
3. The original formula = (X-2) & #178; + (y + 3) & #178; = 0; X = 2. Y = - 3
If the x power of 3 equals 15 and the Y power of 3 equals 5, then the x minus y power of 3 equals 15
X minus y power of 3 = x power of 3 △ y power of 3 = 15 / 5 = 3
(3b's square-2a's Square) - 2 (ab-2b's square-a's Square), where a = 2, B = - 1 / 2
(3b's square-2a's Square) - 2 (ab-2b's square-a's Square)
=3b²-2a²-2ab+4b²+2a²
=7b²-2ab
=7*1/4-2*2*(-1/2)
=7/4+2
=15/4
(the square of 3b-2a) - 2 (the square of ab-2b-a) = 7b ^ 2-2ab = B (7b-2a) = (- 1 / 2) * (- 7 / 2-4) = 15 / 4
Multiplication and division of integral and factorization in eighth grade mathematics (4 questions) (please explain in detail)
1. If X-Y = 2, x ^ 2-x ^ 2 = 10, then x + y = 2.100 ^ 2-99 ^ 2 + 98 ^ 2-97 ^ 2 + 96 ^ 2-95 ^ 2 +... + 2 ^ 2-1 ^ 2 3. (1-1 / 2 ^ 2) (1-1 / 3 ^ 2) (1-1 / 4 ^ 2)... (1-1 / 9 ^ 2) (1-1 / 10 ^ 2) 4. Given m ^ 2 + n ^ - 6m + 10N + 34 = 0, find the value of M + n
Two questions and three questions are calculation questions
⒈∵x²－y²＝10
∴﹙x＋y﹚﹙x－y﹚＝10
∵x－y＝2
∴x＋y＝5
⒉100²－99²＋98²－97²＋96²－95²﹢···＋2²－1²
＝﹙100＋99﹚﹙100－99﹚＋﹙98＋97﹚﹙98－97﹚＋···＋﹙2＋1﹚﹙2－1﹚
＝199＋195＋191＋···＋7＋3
＝﹙199＋3﹚＋﹙195＋7﹚＋﹙191＋11﹚＋···＋﹙103＋99﹚
＝202＋202＋···＋202
＝202×25
=5050
⒊﹙1－1/2²﹚﹙1－1/3²﹚﹙1－1/4²﹚… （1－1/9²﹚﹙1－1/10²﹚
＝﹙1＋½﹚﹙1－½﹚﹙1＋⅓﹚﹙1－⅓﹚… （1＋1/9﹚﹙1－1/9﹚﹙1＋1/10﹚﹙1－1/10﹚
＝3/2×4/3×5/4×… 10/9×11/10
＝11/2
⒋∵m²＋n²－6m＋10n＋34＝0
∴m²－6m＋9＋n²＋10n＋25＝0
∴﹙m－3﹚²＋﹙n＋5﹚²＝0
∵﹙m－3﹚²≥0 ﹙n＋5﹚²≥0
m－3＝0 n＋5＝0
∴m＝3 n＝-5
∴m＋n＝-2
1 x & # 178; - Y & # 178; = (X-Y) (x + y) = 10 because X-Y = 2, so x + y = 5
2 100 & # 178; - 99 & # 178; = (100-99) (100 + 99) = 199 similarly 98 & # 178; - 97 & # 178; = (98-97) (98 + 97) = 195 and so on
The original formula = 199 + 195 + 191 +... + 3 forms the arithmetic sequence with 199 as the first term - 4 as the difference = 5050
3... Unfold
1 x & # 178; - Y & # 178; = (X-Y) (x + y) = 10 because X-Y = 2, so x + y = 5
2 100 & # 178; - 99 & # 178; = (100-99) (100 + 99) = 199 similarly 98 & # 178; - 97 & # 178; = (98-97) (98 + 97) = 195 and so on
The original formula = 199 + 195 + 191 +... + 3 forms the arithmetic sequence with 199 as the first term - 4 as the difference = 5050
3 the original formula becomes (1-1 / 2) (1 + 1 / 2) (1-1 / 3) (1 + 1 / 3) (1-1 / 4) (1 + 1 / 4)... (1-1 / 9) (1 + 1 / 9) (1-1 / 10) (1 + 1 / 10)=
1 / 2 * 3 / 2 * 2 / 3 * 4 / 3 * 3 / 4 * 5 / 4 * 4 / 5... 10 / 9 * 9 / 10 * 11 / 10 numerator, parent offset part = 1 / 2 * 11 / 10 = 11 / 20
4 m and 178; + N and 178; - 6m + 10N + 34 = m and 178; - 6m + 9 + N and 178; + 10N + 25 = (M-3) & 178; + (n + 5) & 178; = 0 only if M = 3, n = - 5
So m + n = - 2 ﹣ put it away
The answer to question 1 is 5, and the answer to question 4 is 2
1. 5 2. 5050 3.11/20
The fourth question is not complete. I hope it can help you
The fourth power of Y minus the fifth power of Y is equal to?
y4(1-y)
If the square of a + AB = 8 and the square of AB + B = 9, then the square of a-ab-2b =?
Detailed point, to process, before 8:10, speed ah
If it's fast enough, I'll give him all 90
So simple, the first equation minus twice the second equation, the answer is negative 10
The square of a + AB = 8, ①
The square of AB + B = 9
② X 2
2ab+2b²=9×2=18③
① - 3, get
A & # 178; - ab-2b & # 178; = 8-18 = - 10: Thank you, but I can't give you the value of wealth. Sorry, thank you for doing it again.
The eighth grade mathematics integral multiplication and division and factorization mathematics book 146 page exercise 2. Simplify x (x-1) + 2x (x + 1) - 3x (2x-5) fast!
x（x-1）+2x（x+1）-3x（2x-5）
=x²-x+2x²+2x-6x²+15x
=-3x²+16x
=x（16-3x）
x(x-1)+2x(x+1)-3x(2x-5)
=x^2-x+2x^2+2x-6x^2+15x
=16x-3x^2
A + 1 / A is equal to 5, (a minus 1 / a) to the second power
a 1/a=5
∴（ a 1/a）²=a² 2 （1/a²）=25
∴a² （1/a²）=23
（a-1/a）²=a²-2 （1/a²）=21
Square of 9 (a + 2b) - square of 4 (a-3b)
The original formula = 9 (A & # 178; + 4AB + 4B & # 178;) - 4 (A & # 178; - 6ab + 9b & # 178;) = 5A & # 178; + 60ab
Ask a few mathematical questions about multiplication and division of integers and factorization
1. Decomposition factor A ^ 3-A =? 2. The area of rectangle is a ^ 3-2ab + a
1. Use the formula ^ A-1 (a = 1-1) to calculate the difference
2. Digong factor
a^3-2ab＋a
=a(a^2-2b+1)