Problem solving: please write a linear equation with one variable that meets the following conditions: (1) the coefficient of the unknown is 6; (2) the solution of the equation is 4. Then the equation is

Problem solving: please write a linear equation with one variable that meets the following conditions: (1) the coefficient of the unknown is 6; (2) the solution of the equation is 4. Then the equation is

y=kx+b
The unknown coefficient is 6
y=6x+b
0=6*4+b
b=-24
y=6x-24
6X+8=32
∵ is a linear equation of one variable
Let the equation be KX + B = 0
∵ the unknown coefficient is 6
∴k=6
The solution of the equation is 4
∴x=4
∵k=6，x=4，kx+b=0
∴b=-24
The equation is 6x-24 = 0
Given that the power a of 7 = m, the power B of 7 = n, find the power 2a-3b of 7
7^(2a-3b)
=(7^2a)÷(7^3b)
=(7^a)²÷(7^b)³
=m²÷n³
=m²/n³
=2A power of 7-3b power of 7
The square of a power of 7 = M & # 178;
The third power of B power of 7 = the third power of n
M square of 7 - the third power of n of 7
x²-3x-18＜0 （x-1)(x+2)=(x-2)(2x+1)
1、
（x+3）（x-6）＜0
-3＜x＜6
2、
x²+x-2=2x²-3x-2
2x²-x²-3x-x=0
x²-4x=0
x（x-4）=0
X = 0 or 4
The solution of the equation (x) is the same as that of the equation (x) - 1
Please write a linear equation with one variable which satisfies the following conditions:
(1) The coefficient of the unknown x is - 3
(2) The solution of the equation is the same as that of the equation X-5 = 7-2x
First solve the equation, x = 4,
So the equation can be - 3x = - 12
First simplify and then evaluate the square of (ab-3a) - 2b-5ab-2 (A's square-2ab), where a = 1, B = - 2
The original formula is ab-3a-2b-5ab-2a + 4AB
=-5a-2b
=-5 × 1-2 × (- 2) M3
=-5-8
=-13
The solution of 2x & # 178; - 3x-1 = 0
-1
(a-b) × (a + b) × (the second power of a + the second power of B), using the square difference formula
(a-b) × (a + b) × (quadratic power of a + quadratic power of B)
=(quadratic of a-quadratic of B) × (quadratic of a + quadratic of B)
=The fourth power of a - the fourth power of B
(a-b) × (a + b) × (quadratic power of a + quadratic power of B)
=(quadratic power of a + quadratic power of B) × (quadratic power of a + quadratic power of B)
=The fourth power of a - the fourth power of B
-2 (the square of ab-3a) - [the square of 2B - (the square of 5ab + a) + 2Ab] where a = 4B = 0.5
You must be right
=-2（2-48）-[0.5-（10+16）+4]
=92-（0.5-22）
=113.5
The case of 3x & # 178; a 2x = a 1
unsolvable
Solve equations and coordinate equations
1. There is a train with a carrying capacity of 800 tons and a cargo volume of 795 cubic meters. First of all, pig iron and cotton should be loaded. The volume of pig iron per ton is 0.3 cubic meters and that of cotton per ton is 4 square meters. How many tons of pig iron and cotton can be loaded respectively? In order to make full use of the carrying capacity and volume of the train
Suppose the pig iron is x tons,
The cotton is 800-x
0.3X+(800-X)*4=795X= 650
That is, 650 tons of pig iron and 150 tons of cotton
Suppose that cotton carries x tons, pig iron 800-x tons, 4x + (800-x) * 0.3 = 795, x = 150, 800-150 = 650