-The number of 2 (ab-3a) - [2B - (5ab + a square) + 2Ab]

-The number of 2 (ab-3a) - [2B - (5ab + a square) + 2Ab]

＝－2ab＋6a－（2b－5ab－a²＋2ab）
＝－2ab＋6a－2b＋5ab＋a²－2ab
＝ab＋6a－2b＋a²
2x²-3x+1≤0
-1
Please solve the equation (x-1) to the power of | x | - 1 = 1
-Is a minus sign
The power of 0 of any non-zero real number = 1, so | x | - 1 = 0 and X - 1 ≠ 0, so the value of any exponent of x = - 1 1 = 1, so x - 1 = 1, so x = 2, so x = - 1 or 2
(AB minus the square of 3a) minus the square of 2B minus 5ab minus (the square of a minus 2Ab)
(AB minus the square of 3a) minus the square of 2B minus 5ab minus (the square of a minus 2Ab)
=ab-3a²-2b²-5ab-a²+2ab
=(ab-5ab+2ab)-(3a²+a²)-2b²
=-2ab-4a²-2b²
3x²-2x-7=0
3x²-2x=7
x²-2x/3=7/3
x²-2x/3+1/9=7/3+1/9
(x-1/3)²=22/9
x-1/3=±√22/3
x=(1-√22)/3,x=(1+√22)/3
△=4+84=88
x1,2=(2±√88)/6=(1±√22)/3
What are the first two conditions for solving the equation
An unknown number is x and an unknown number is y
First of all, let's set two unknowns X. Ask: Yes ~ ~ what is that called
If a = 1 / 2, B = 1 / 3, then 3A square + 5ab-2b, 3A square - AB =?
Original formula = a (3a-b) / (3a-b) (a + 2b)
=a/(a+2b)
=(1/2)/(1/2+2/3)
=3/7
3X²-2X-85=0
(3*x-17)(x+5)=0
perhaps
3*(x-17/3)(x+5)=0
In fact, the results obtained by the two methods are the same
It is customary to use only the first method, because there is no direct score
There is no good way to do this kind of problem. You can only scrape it together
Calculus formula and theorem
I'm a freshman this year, and I'm not good at calculus. Is there a master who can summarize the formulas and theorems that calculus must recite, so that I can get a good result in the exam and have a happy new year
I am a professional. My suggestion to you is to generalize the basic theory, such as the continuity and uniform continuity of functions, which can be used to prove the series and n-l definite integral formula, and this proof method can be extended to the transformation proof of double, triple and single definite integral
Given the square + | 2b-1 | = 0 of (a + b), find the value of a + B [2ab-3 (AB-1)] and the square + | 2b-1 | = 0 of (a + b), find the value of a + B [2ab-3 (AB-1)]
∫ (a + b) square + | 2b-1 | = 0,
∴a+b=0,2b-1=0
∴a=-1/2.b=1/2
∴a+b[2ab-3(ab-1)]=a+b[-ab-1]=-1/2+1/2(1/4-1)=-7/8