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Pentagram is our common figure, as shown in the figure, where points c and D are the golden section points of line AB, ab = 20cm, find the length of EC + CD
∵ D is the golden section of AB (AD > BD), ∵ ad = 5 − 12ab = 105-10, ∵ EC + CD = AC + CD = ad, ∵ EC + CD = (105-10) cm
(2a-b)^2+(2a-b)(2a+4b)+(a+2b)^2
If the equation (M & # 178; - 1) - (M + 1) x + 8 = 0 is a linear equation of one variable with respect to x, then M = ()
Is it (M & # 178; - 1) x & # 178; - (M + 1) x + 8 = 0?
m²-1=0
m+1≠0
The result is: M = 1
According to the meaning of the title: M & # 178; - 1 = 0, and M + 1 ≠ 0
∴m=1
Do not understand can ask, help please adopt, thank you!
Pentagram is our common figure, as shown in the figure, where points c and D are the golden section points of line AB, ab = 20cm, find the length of EC + CD
∵ D is the golden section of AB (AD > BD), ∵ ad = 5 − 12ab = 105-10, ∵ EC + CD = AC + CD = ad, ∵ EC + CD = (105-10) cm
Given a-2b = - 2, the value of 4-2a + 4b is ()
A. 0B. 2C. 4D. 8
If (M-3) x2 | m | - 5-4m = 0 is a linear equation of one variable with respect to x, find the value of the algebraic formula m2-2m + 1m
According to the characteristics of one variable linear equation, m − 3 ≠ 02 | m | - 5 = 1, M = - 3. When m = - 3, m2-2m + 1m = 9 + 6-13 = 1423
Given that the line segments AB = a, C and D are the two golden section points on AB, the length of the line segment CD is calculated
Let's talk about the process
The golden section point is 0.618
a*(0.618*2-1)=0.236a
0.236a
Given that a and B satisfy a - = 1, find a ^ 2-4ab + 4B ^ 2-2a + 4B
As shown in the title
If the absolute value of (M-3) x ^ 2 * m - 4m = 0 is a one variable linear equation about X, find the value of m ^ 2-2m + 1
(M-3) x ^ (2 * | m |) - 4m = 0 is a linear equation of one variable about X, so it must be 2 * | m | = 1, and M is not = 3. The solution is m = 1 / 2 or M = - 1 / 2. When m = 1 / 2, m ^ 2-2m + 1 = (1 / 2) ^ 2 - 2 * (1 / 2) + 1 = 1 / 4 - 1 + 1 = 1 / 4. When m = - 1 / 2, m ^ 2-2m + 1 = (- 1 / 2) ^ 2 * (- 1 / 2) + 1 = 1 / 4 + 1 = 2 and 1 / 4
Points c and D are two different golden section points of line ab. if CD = 1, then ab=
It's very detailed
AC=BD=x ,AB=2x+1 ,BC=x+1
Golden section BC = (Half Root five minus one) ab
X = half root five plus one
AB = radical five plus two
RELATED INFORMATIONS
- 1. Given a & sup2; + 4AB + 5B & sup2; - 2b + 1 = 0, find the arithmetic square root of - 2A + 4B
- 2. Let u = R, set a = {x | x2 + 3x + 2 = 0}, B = {x | x2 + (M + 1) x + M = 0}; if (a complements in U) intersection B = empty set, find the value of M
- 3. C is the golden section point of line AB, AC > BC, then the square of AC
- 4. When the values of a and B are respectively, the polynomial 4A ^ 2 + B ^ 2 + 4a-6b-8 has the minimum value, and the minimum value can be obtained
- 5. Given a = {x | x = - T & # 178;, t ∈ r}, B = {y | y = x & # 178; + 3, X ∈ r}, and u = R, then A∩B=——；A∪B=——；Cu（A∪B）=——
- 6. Mathematical golden section formula It's a formula for finding long and short line segments
- 7. Given that 2A ^ 2 - 8ab + 17b ^ 2 - 16A - 4B + 68 is greater than or equal to 0, find the value of a and B
- 8. 2X & # 178; (2 / 1xy & # 178; - y) - (X & # 178; Y & # 178;) × (- 3x) - 2Y & # 178; (X & # 178; - 5xy + 2 / 1y) - (2XY) &# 178;
- 9. If point C is the golden section of line AB, then AC of AB is equal to
- 10. It is known that f (x) is an odd function defined on R, and when x > 0, f (x) = X3 + 2x2-1, the analytic expression of F (x) can be obtained
- 11. If (M & # 178; - 1) x & # 178; + (M + 1) + 2 = 0 is a linear equation of one variable with respect to x, then M is ()
- 12. If 3AB + 2A + 5B = 4ab-m, then M=_____
- 13. What is the original function of the fifth power of sin?
- 14. Explain the size of the algebraic expressions X & # 178; - 3x + 3 and X-5 in the way you have learned
- 15. -The number of 2 (ab-3a) - [2B - (5ab + a square) + 2Ab]
- 16. Problem solving: please write a linear equation with one variable that meets the following conditions: (1) the coefficient of the unknown is 6; (2) the solution of the equation is 4. Then the equation is
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- 19. It is known that the | a | - 1 power + 12 = 0 of equation (A-2) x is a linear equation of one variable with respect to x, then the solution of the equation is simple
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