Explain the size of the algebraic expressions X & # 178; - 3x + 3 and X-5 in the way you have learned

Explain the size of the algebraic expressions X & # 178; - 3x + 3 and X-5 in the way you have learned

A:
x^2-3x+3-(x-5)
=x^2-4x+8
=(x-2)^2+4
>=4
>0
So:
x^2-3x+3>x-5
It holds for any real number X
What are the basic formulas of calculus in advanced mathematics?
Advanced mathematics, Volume 1
Generally speaking, there are thousands of calculus formulas, most of which are unnecessary to remember
There are only a dozen basic formulas to remember, four rules and four special methods of integration
The key is to be able to use it freely
Please contact me, you find the topic, I step by step demonstration solution to you
Just memorize the formulas in the textbooks. The others are based on the basic formulas in the textbooks
I haven't read math for a long time. I forgot everything in high school, but now I need to use it in an exam. I'm a little short of time. I feel like I can't do it when I read a book, so I want to ask
Then the ratio of AB to A-2 is known
1/a-1/b=2
(b-a)/ab=2
b-a=2ab
The original formula = [(2a-2b) - AB] / [(a-b) - 3AB]
=[-2(b--a)-ab]/[-(b-a)-3ab]
=[-2*2ab-ab]/[-2ab-3ab]
=[-5ab]/[-5ab]
=1
1/a-1/b=2
So B-A = 2Ab
So (2a-ab-2b) / (a-3ab-b)
=(-4ab-ab)/(-2ab-3ab)
=1
It's equal to one
The value is 1, which is obtained by taking A-B = - 2Ab into the expression to be solved and reducing ab.
Try to compare the size of polynomials X & # 178; - 3x + 1 and X & # 178; + x-4, and explain the reason
Do a bad job
x^2-3x+1-x^2-x+4=5-4x
5-4x > 0 is X
1. Hypothesis
x²-3x+1>x²+x-4
Then x
Calculus sin or cos n-th power integral from 0 to pie
I know the formula from 0 to 2 / 2, but I can't figure out the formula from 0 to 2 / 2. When n is odd, will the product be 0 or double the integral from zero to 2 / 2, even? If it is zero to 2 / 2?
Now that you know the integral formula of sine and cosine function with n power from 0 to π / 2, according to the properties of trigonometric function, the integral interval becomes 0 to π, the integral value of sine function becomes twice of that before, and cosine function needs to discuss the parity of N. if n is odd, then the integral value is 0, if n is even, If the integral interval becomes 0 to 2 π, do a similar analysis
Given 2A + 2B + AB = 23, and a + B + 3AB = -12, then the value of a + bab______ .
According to the meaning of the question, we get 2A + 2B + AB = 23a + B + 3AB = - 12, multiply both sides of the equation 2A + 2B + AB = 23 by 3 to get 6A + 6B + 3AB = 2, subtract equation a + B + 3AB = - 12 from equation 6A + 6B + 3AB = 2 to get a + B = 12, and substitute equation a + B = 12 into equation a + B + 3AB = - 12 to get AB = - 13, then a + bab = - 32
x²+√5/3x=31/36
x=-√5/6±1
Calculus formula in Higher Mathematics
I have a mathematics manual on hand. I have turned it over. There are more than 20 basic formulas of derivative and differential, and there are more integral formulas. It's difficult to list them one by one here. It's better to buy a good quality mathematics manual and keep it nearby
Given (1 △ a) - (1 △ b) = 2, find the value of (2a-ab-2b) / (a-3ab-b)
1/a-1/b=2
(b-a)/ab=2
b-a=2ab
The original formula = [(2a-2b) - AB] / [(a-b) - 3AB]
=[-2(b--a)-ab]/[-(b-a)-3ab]
=[-2*2ab-ab]/[-2ab-3ab]
=[-5ab]/[-5ab]
=1
Solve the equation - 2x & # 178; + 3x-1 = 0
The solution is - 2x & # 178; + 3x-1 = 0
We get 2x & # 178; - 3x + 1 = 0
That is, (2x-1) (x-1) = 0
The solution is x = 1 or x = 1 / 2