If 3AB + 2A + 5B = 4ab-m, then M=_____

If 3AB + 2A + 5B = 4ab-m, then M=_____

M
=4AB - (3AB + 2a to the second power + 5B to the second power)
=The second power of ab-2a-the second power of 5B
If the equation (M + 2) x & # 178; + 4mx-4m = O of X is a linear equation of one variable, then what is the solution of the equation?
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Because it is unary, so m + 2 = 0, M = - 2, substituting, - 8x - (- 8) = 0, x = 1
The equation (M + 2) x & # 178; + 4mx-4m = O of X is a linear equation of one variable,
Then M + 2 = 0, M = - 2
Then, substituting into the equation (M + 2) x & # 178; + 4mx-4m = O about X is: - 8x + 8 = O, so, x = 1, why m + 2 = 0? In order to make the equation (M + 2) x & # 178; + 4mx-4m = O with respect to X be a one variable linear equation (please note that it is one variable linear), we must make the coefficient of the quadratic term (M + 2) x & # 178; 0, so that the quadratic term disappears
The equation (M + 2) x & # 178; + 4mx-4m = O of X is a linear equation of one variable,
Then M + 2 = 0, M = - 2
Then, substituting into the equation (M + 2) x & # 178; + 4mx-4m = O about X is: - 8x + 8 = O, so, x = 1. Why m + 2 = 0?
How to do golden section?
How to draw the golden section?
A line segment is divided into two parts, so that the ratio of one part to the whole length is equal to the ratio of the other part to this part. The ratio is an irrational number, and the approximate value of the first three digits is 0.618
(the 2nd power of 2A + the 2nd power of 3ab-b) - (- the 2nd power of 3A + the 2nd power of AB + 5b)
(the 2nd power of 2A + the 2nd power of 3ab-b) - (- the 2nd power of 3A + the 2nd power of AB + 5b)
=2a^2+3ab-b^2+3a^2-ab-5b^2
=5a^2+2ab-6b^2.
If the equation (M + 2) x & # 178; + 4mx-4m = 0 about X is a linear equation with one variable, what is the solution of the equation?
Because the equation is a linear equation with one variable
Therefore, let the quadratic coefficient of the equation be 0, that is, M + 2 = 0, and M = - 2
Substituting the problem into the equation, we can get: - 8x + 8 = 0
The solution is: x = 1
The solution of the equation is x = 1
From the title, we know that 4mx-4m = 0
x-1=o
X=1
What fraction of a line is the golden section
A line segment has two golden section points. At 0.618 from the end point
Given 1a − 1b = 5, find the value of 2A + 3AB − 2BA − 2Ab − B
∵ 1a-1b = B − AAB = 5, ∵ B-A = 5ab, that is, A-B = - 5ab, then 2A + 3AB − 2BA − 2Ab − B = 2 (a − b) + 3AB (a − b) − 2Ab = − 10ab + 3AB − 5ab − 2Ab = − 7ab − 7ab = 1
If the equation (M & # 178; - 1) x & # 178; + (M + 1) X-6 = 0 is a linear equation with one variable, then the value of M should be
The coefficient of quadratic term is 0
M & # 178; - 1 = 0, M = 1 or M = - 1
And the coefficient of the first term is not 0
M + 1 ≠ 0: m ≠ - 1
To sum up, M = 1
Two
If the equation (M & # 178; - 1) x & # 178; + (M + 1) X-6 = 0 is a linear equation with one variable,
Then M & # 178; - 1 = 0, M + 1 ≠ 0
So m = ± 1, m ≠ - 1
So m = 1
I wish you progress in your study!
If the stage is regarded as a line segment, the best lighting effect is that the lighting device is just at the two golden section points. Given that the distance between the two lighting devices of the stage is 2.36M, find the length of the stage (root 5 ≈ 2.236)
The golden section is (√ 5-1) / 2 of the whole length
The proportion of the middle part in the whole stage length [1 - (√ 5-1) / 2] * 2 = 3 - √ 5 ≈ 0.764
2.36/0.764=3.09m
-XY + X + 4xy-y merges the same category, 2A's Square, b-4ab's square + 3A's Square, B + 3AB's Square merges the same category
-xy+x+4xy-y=x-y+3xy
Square of 2a, square of b-4ab + square of 3a, square of B + 3AB = 5A ^ 2b-ab ^ 2
-xy+x+4xy-y
＝x-y+3xy
The square of 2A the square of b-4ab + the square of 3A the square of B + the square of 3AB
=5a^2-ab^2
-XY + X + 4xy-y is the same as 3xy + X-Y
The square of 2a, the square of b-4ab + the square of 3a, and the square of B + 3AB are merged into the same category as 5A ^ 2b-ab ^ 2
-XY + X + 4xy-y is the same as 3xy + X-Y
The square of 2a, the square of b-4ab + the square of 3a, and the square of B + 3AB are merged into the same category as 5A ^ 2b-ab ^ 2
-xy+x+4xy-y=3xy+x-y
The square of 2A the square of b-4ab + the square of 3A the square of B + the square of 3AB
=The square of 5A the square of b-ab
=ab(5a-b)
-xy+x+4xy-y
The merging congener is 3xy + X-Y
The square of 2a, the square of b-4ab + the square of 3a, and the square of B + 3AB are merged into the same category as 5A ^ 2b-ab ^ 2