It is known, as shown in the figure: in the plane rectangular coordinate system, O is the coordinate origin, the quadrilateral oabc is a rectangle, the coordinates of points a and C are a (10, 0), C (0, 4), respectively; point D is the midpoint of OA, and point P moves on the edge of BC; when △ ODP is an isosceles triangle with waist length of 5, the coordinates of point P are______ .

It is known, as shown in the figure: in the plane rectangular coordinate system, O is the coordinate origin, the quadrilateral oabc is a rectangle, the coordinates of points a and C are a (10, 0), C (0, 4), respectively; point D is the midpoint of OA, and point P moves on the edge of BC; when △ ODP is an isosceles triangle with waist length of 5, the coordinates of point P are______ .

(1) When od is the bottom of an isosceles triangle, P is the intersection of the vertical bisector of OD and CB, and op = PD ≠ 5;
(2) When od is one waist of isosceles triangle:
① If point O is the vertex of the vertex angle, point P is the intersection point of the arc with point o as the center of the circle and radius of 5 with CB,
In right angle △ OPC, CP=
OP2-OC2=
If 52-42 = 3, then the coordinates of P are (3, 4)
② If D is the vertex of the vertex angle, point P is the intersection point of the arc with point D as the center of the circle and radius of 5 with CB,
D as DM ⊥ BC at point M,
In right angle △ PDM, PM=
PD2-DM2=3,
When p is on the left of M, CP = 5-3 = 2, then the coordinates of P are (2,4);
When p is on the right side of M, CP = 5 + 3 = 8, then the coordinates of P are (8, 4)
So the coordinates of P are: (3,4) or (2,4) or (8,4)
So the answer is: (3,4) or (2,4) or (8,4)

In the rectangular oabc, O is the origin of plane rectangular coordinate system, the coordinates of points a and C are (3,0), (0,5), and point B is in the first quadrant (1) Write the coordinates of point B (,) (2) If the straight line CD passing through point C intersects AB with point D, and the circumference of the rectangular oabc is divided into two parts, i.e. 3:1, to find the coordinates of point D (3) The area of the quadrilateral oad1c1 is calculated by translating the line CD in (2) down two unit lengths to obtain C 1D 1

(1) Because CB / / OA, AB / / OC, so B (3,5) (2) know that the circumference of the rectangle is 3 * 2 + 5 * 2 = 16, so 3:1 = 12:4. Because the straight line passes through C and D is on AB, CB + BD = 4, CB = OA = 3, so BD is equal to 1, so D ordinate is 4-1 = 3, that is, D point coordinate is (3,3) (3) because c1d1 is CD down translation two

It is known that the radius of the circle O is r, the distance from the center of the circle O to the line L is D, and D and R are the two roots of the equation x 2 + 2 MX + 1 = 0, Given that the radius of the circle O is r, the distance from the center of the circle O to the straight line L is D, and D and R are the two roots of the equation x? + 2mx + 1 = 0, then when the line L is tangent to ⊙ o, the value of M is

If a line is tangent to a circle, then d = R
So the equation has equal roots
Then (2m) ^ 2-4 = 0
M = 1 or - 1,
However, when m = 1, two are negative roots, and they are discarded
So we can only take M = - 1

Given that the radius of two circles is r1r2, they are two of the equations 2x? - 14x + 5 = 0, and the distance between the centers of two circles is 7, what is the position relationship between the two circles?

∵ the radius of two circles is R1, R2
Moreover, R1 and R2 are two of the equations 2x? 14x + 5 = 0
 from Weida's theorem, it can be concluded that:
R1+R2=14/2=7
∵ center distance = 7
ν R1 + R2 = center distance of circle
The two circles are circumscribed

Given that the equation of the straight line L is 3x + 4y-25 = 0, then the minimum distance between the point on the circle x2 + y2 = 1 and the line L is () A. 3 B. 4 C. 5 D. 6

∵x2+y2=1
The center of the circle (0, 0), with a radius of 1
The distance from the center of the circle to the straight line is: D = 25
32+42=5
As shown in the figure: the minimum distance between the point on the circle x2 + y2 = 1 and the straight line L is D-R = 4
Therefore, B is selected

Find the equation of the circle passing through the intersection of two circles x 2 + y 2 - 2 x - 2 y + 1 = 0 and x 2 + y 2 - 6 x - 4 y + 9 = 0, and the center of the circle is on the straight line y = 2x

According to the meaning of the question, let the equation of the circle be x? + y? - 2x-2y + 1 + λ (x? + y? - 6x-4y + 9) = 0, and λ is an unknown number. Because the center of the circle is on the straight line y = 2x, the coefficient in front of the Y term of the circular equation must be twice that of the coefficient in front of the X term

Two parallel straight lines 3x + 2y-6 = 0 and 6x + 4y-3 = 0 are known, and the equations of parallel lines equidistant from them are solved

Method 1: let the straight line be 6x + 4Y + T = 0, turn 3x + 2y-6 = 0 into 6x + 4y-12 = 0, then | T + 12 | / √ 6 | 4 | = | T + 3 | / √ 6 ﹤ 4 | t = - 15 / 2, so the equation is 6X + 4y-15 / 2 = 0

Find the length of the string AB that the straight line 3x minus 4Y plus five equals zero and the circle x square plus y square equals to four

It is known that the radius of the circle is 2 and the distance from the center of the circle to the straight line is 1. Using the Pythagorean theorem, it is concluded that half of the chord is root 3, so the chord length is 2 * root 3
We can also combine the equations to get the intersection point and find the chord length
You can also use the string length formula. However, this problem is relatively simple, and the above two methods are faster

Find the linear equation of the longest chord and the shortest chord passing through a point P (- 5, - 1) in the circle x square + y square + 6x-4y-3 = 0

The circle x ^ 2 + y ^ 2 + 6x-4y-3 = 0, i.e. (x + 3) ^ 2 + (Y-2) ^ 2 = 10 center C (- 3,2), radius √ 10, the shortest chord passing through the point P (- 5, - 1) of the circle is the chord with P as the midpoint. The product of the vertical slope k and the slope of PC is - 1kpc = (2 + 1) / (- 3 + 5) = 3 / 2 ﹤ k = - 2 / 3

Find the common chord length of circle x square plus y square minus four equal to zero and x square plus y square minus four x plus 4Y minus 12!

The first circle: Center (0,0) radius = 2 second circle: Center (2, - 2) radius = 2. Consider the line between one of the intersection points of two circles and the line between the centers of two circles. The length of the triangle is 2,2,2 * (2) ^ 0.5, which indicates that the three sides form an isosceles right triangle