If the distance from a point on a straight line to the center of a circle is equal to the radius of the circle, then the straight line is the tangent line of the circle. B. the distance from the center of the circle to the straight line The correct one of the following propositions is () A. If the distance from a point on a line to the center of a circle is equal to the radius of the circle, the line is tangent to the circle B. If the distance from the center of the circle to the straight line is not equal to the radius, the line intersects the circle C. If a line and a circle have a unique common point, the line is tangent to the circle D. If the line AB has no intersection with the circle, then the line AB is separated from the circle PS: I feel both C and D are right~

If the distance from a point on a straight line to the center of a circle is equal to the radius of the circle, then the straight line is the tangent line of the circle. B. the distance from the center of the circle to the straight line The correct one of the following propositions is () A. If the distance from a point on a line to the center of a circle is equal to the radius of the circle, the line is tangent to the circle B. If the distance from the center of the circle to the straight line is not equal to the radius, the line intersects the circle C. If a line and a circle have a unique common point, the line is tangent to the circle D. If the line AB has no intersection with the circle, then the line AB is separated from the circle PS: I feel both C and D are right~

C
D is a line segment, which can be in a circle

The distance from the center of the circle to the straight line is equal to the radius, which is a necessary condition for the line to be tangent to the circle

It is a necessary and sufficient condition

If the distance between the centers of two circles is equal to 4, the radii of the two circles are R and R respectively, and R and R are two of the equations x2-5x + 4 = 0, then the position relationship between the two circles is () A. Contains B. Exotomy C. Intersection D. Exotropism

∵x2-5x+4=0,
∴x1=4,x2=1,
∴R=4,r=1,d=4,
∴R+r=5,R-r=3,
∴3<4<5,
That is, R-R < d < R + R,
The two circles intersect
Therefore, C

Given that the distance between the centers of two circles d = 1.5, and the radii of two circles are the two roots of equation x minus 4x + 4 equal to 0, then the position relationship between the two circles is

x^2-4x+4=0
x1=x2=2
x1+x2=4
x1-x2=0
d=1.5
x1-x2

It is known that the distance between the centers of two circles is equal to 5, and the diameter of the two circles is the two roots of the equation x square-10x + 3 = 0. Try to judge the position relationship between the two circles

I'll give you a way
According to x square - 10x + 3 = 0, x 1 + x 2 = R1 + R2 = 10 is obtained by using the Vader theorem
10 is greater than 5
Therefore, the center distance is less than the sum of radius
Two circles intersect

If the distance d between the centers of two circles satisfies the equation | D-4 = 3, and the radius of two circles is the two roots of equation x2-7x + 12 = 0, the position relationship between the two circles is judged

Because | D-4 | = 3, D1 = 7, D2 = 1. And because x2-7x + 12 = 0, X1 = 3, X2 = 4
When d = 7, the two circles are tangent, and when d = 1, the two circles contain

If the distance between the centers of two circles is 3 and the radii of the two circles are the two roots of the equation x2-4x + 3 = 0, then the position relationship between the two circles is () A. Intersection B. Exotropism C. Contains D. Exotomy

By solving the equation x2-4x + 3 = 0, X1 = 3, X2 = 1
According to the meaning of the title, r = 3, r = 1, d = 3,
∴R+r=4,R-r=2,
2 < 3 < 4, R-R < d < R + R
The two circles intersect
Therefore, a

The radius of the two circles is two of the equation x? - 7x + 6 = 0, and the distance between the centers of the two circles is the root of the equation x? - x-20 = 0

The radii of two circles are two of the equation x? - 7x + 6 = 0
x²-7x+6=0
(x-6)(x-1)=0
x1=6;x2=1
So, the radius of the circle is 6 and 1
The center distance is the root of the equation x? - x-20 = 0
(x-5)(x+4)=0
X=5
Because 6-1 = 5
So two circles are inscribed

The radius of circle O is r, the distance from point O to line L is D, and RD satisfies the absolute value of equation [2r-7] + [D-4] ^ 2 = 0 In order to judge the position relationship between the circle and the straight line L, they are separated, intersected and tangent No and RD satisfies the equation R, D

| 2r-7 | ≥ 0 and (D-4) ° ≥ 0. | from | 2r-7 | + (D-4) ° = 0, it must be: 2r-7 = 0, D-4 = 0. Thus, r = 7 / 2, d = 4, ∵ D ﹤ R.  the circle is separated from the straight line
The sum of several nonnegative numbers is equal to 0, unless every number is equal to 0

If the radius of circle O is 5cm, the distance from O to straight line L is op = 3cm, q is the point above L, PQ = 4.1cm, what is the relationship between point Q and circle O

Q is outside the circle o