Point P is a point outside the line L, a, B, C are three points on the line L, PA = 4cm, Pb = 5cm, PC = 2cm, then the distance between point P and line L () A. Less than 2cm B. Equal to 2cm C. No more than 2cm D. It's 4 cm

Point P is a point outside the line L, a, B, C are three points on the line L, PA = 4cm, Pb = 5cm, PC = 2cm, then the distance between point P and line L () A. Less than 2cm B. Equal to 2cm C. No more than 2cm D. It's 4 cm

∵ according to the distance from the point to the straight line, it is the vertical line segment from the point to the straight line (the vertical line segment is the shortest),
2<4<5,
The distance from point P to line L is less than or equal to 2, that is, not more than 2,
Therefore, C

If R and R are the two roots of the equation x2-m (M-4) x + 5-m = 0, then find the value of M

∵ two circles are circumscribed, the center distance is 5, and their radii are R and R respectively,
∴R+r=5,
∵ R and R are the two roots of the equation x2-m (M-4) x + 5-m = 0 with respect to x, respectively,
∴R+r=m(m-4)=5,
M = - 1 or M = 5 (omitted)
∴m=-1.

The radii of two circles are R and R (r > R) respectively, and the distance between centers of two circles is d. if the equation x2-2rx + (R-D) 2 = 0 on X has two equal real roots, then the position relationship between the two circles is () A. Must be inscribed B. Definite circumcision C. Intersection D. Endotomy or exotomy

Because the equation has two equal real roots, the discriminant is equal to 0
Then: △ = (2R) 2-4 (R-D) 2 = 0,
[2r-2(R-d)][2r+2(R-d)]=0
The results show that d = R + R or D = r-r
So two circles are circumscribed or inscribed
Therefore, D

If the radii of the two circles are known to be 1 and 5 respectively, and the center distance of the two circles satisfies d ^ 2-10d + 24 < 0, then the position relationship between the two circles is?

intersect

Given that the radii of the two circles are 1 and 4 respectively, and the distance between the centers of the two circles is 3, then the position relationship between the two circles is ...

Concentric circle is a special kind of inclusion. O1O2 = R1-R2 belongs to inscribe

Given that the radii of two circles are the two roots of the equation x2-3x + 2 = 0, and the distance between the centers of the two circles is 4, then the position relationship between the two circles is______ .

∵ the radius of the two circles is the two roots of the equation x2-3x + 2 = 0,
The sum of the two = 3 = the sum of the radii of the two circles,
And ∵ center distance = 4,4 ᦝ 3,
The two circles are separated from each other
So the answer is to leave

As shown in the figure, in the plane rectangular coordinate system xoy, take the ox axis as the starting edge to make two acute angles α and β, and their final edges intersect with the unit circle at two points a and B respectively Two 10,2 Five 5. (1) Calculate the value of Tan (α + β); (2) Find sin2 α + sin2 α 6 cos 2 α + cos 2 α

Cos α=
Two
10,cosβ=2
Five
Five
∵ α and β are acute angles, ᙽ sin α = 7
Two
10,sinβ=
Five
5,tanα=7,
∴tanβ=1
2,
(1)tan(α+β)=7+1
Two
1−7×1
2=-3.
(2)sin2α+sin2α
6cos2α+cos2α=sin2α+2sinαcosα
7cos2α−sin2α=tan2α+2tanα
7−tan2α=49+14
7−49=-3
2.

As shown in the figure, in the plane rectangular coordinate system xoy, make two acute angles α, β with the ox axis as the starting edge, and their final edges respectively intersect the unit circle at two points a and B. It is known that the abscissa of two points a and B are Two 10,2 Five 5. (1) Calculate the value of Tan (α + β); (2) Find the value of α + 2 β

(1) According to the definition of trigonometric function, cos α =
Two
Ten
,cosβ=
Two
Five
Five
,
Because α is an acute angle, then sin α > 0, so sin α =
1−cos2α
=
Seven
Two
Ten
Similarly, sin β =
1−cos2β
=
Five
Five
,
Therefore, Tan α = 7, Tan β =
One
Two
.
So tan (α + β)=
tanα+tanβ
1−tanα•tanβ
=
7+
One
Two
1−7×
One
Two
=−3;
(2)tan(α+2β)=tan[(α+β)+β]=
−3+
One
Two
1−(−3)×
One
Two
=−1,
And 0 < α
PI
Two
,0<β<
PI
Two
Therefore, 0 < α + 2 β <
3 pi
Two
,
Therefore, from Tan (α + 2 β) = - 1, α + 2 β = -1
3 pi
Four
.

In the plane rectangular coordinate system xoyo, the ox axis is the starting edge and two acute angles a and B are made. Their final edges intersect two points a and B respectively with the unit circle A. The abscissa of B is the root 2 / 10 and the root 5 / 5 Find Tan (a + b); find a + 2B

Tan (a + b) = minus 3, a + 2b is 135 degrees, don't you need a detailed process

As shown in the figure, in the plane rectangular coordinate system, the point P (0, - 4) moves along the positive direction of the x-axis with a velocity of 1 unit per second, while the point R (16,0) moves in the negative direction of the x-axis with a velocity of 3 units per second, and the movement time is T seconds. (1) if the distance between points P and R is equal, calculate the value of T? (2) if point Q (0,12) moves at the speed of 2 units per second with P and R at the same time, what is the value of T, Is there a double relationship between the area of △ poq and △ ROQ?

(1) Let the velocity of point p be V1, the velocity of point R be V2, and the movement time be t
V1=1 ,V2=3
According to the meaning of the question, 4-v1t = 16-3t, t = 6
(2) What is the direction of Q point, otherwise it is very complicated