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In a circle with chord center distance equal to 2 and radius equal to 4, the degree of the center angle of inferior arc to which the chord is opposite is
cosa=2/4=1/2
a=60°
therefore
The degree of the center angle of the inferior arc to which the chord is connected is 60 ° * 2 = 120 °
As shown in the figure, in ⊙ o with radius of 50, the length of chord AB is 50, (1) Find the degree of ∠ AOB; (2) Find the distance from point O to ab
（1）∵OA=OB=50，AB=50，
The △ OAB is an equilateral triangle,
∴∠AOB=60°；
(2) OC ⊥ AB at point C through point o,
Then AC = BC = 1
2AB=25，
In RT △ OAC, OC=
OA2−AC2=25
3．
That is, the distance from point O to AB is 25
3．
In the center of a circle with a radius of 50 mm, the chord AB is 50 mm long. Calculate the degree of angle AOB and calculate the distance from point O to ab (Fig
The triangle AOB is an equilateral triangle
So the degree of AOB is 60 degrees
Distance from O to ab = 50sin60 = 25 √ 3
In a circle O with a radius of 50 mm and a length of 50 mm, calculate the degree of angle AOB and calculate the distance from point O to ab What I want is the rational format, for example: because of... So
Make OD ⊥ AB in D
Because the radius of circle O is 50 mm
So ob = 50 mm
Because od ⊥ AB, ab = 50mm
So BD = 25 mm
So od = √ 1875mm
In the circle with radius of 50 mm, there is a triangle AOB chord AB with a length of 50 mm There is a triangle in the circle with radius of 50mm. The chord AB is 50mm long. Find the degree of angle AOB and calculate the distance from point O to ab Two concentric circles are centered on point O. a chord AB on the big circle coincides with the string CD of the small circle. It is proved that AC = BD
The degree of AOB should be greater than 30 degrees and less than 180 degrees. The distance should be less than 50 + 25 √ 3mm. OE should be perpendicular to ab (CD) and E. according to the knowledge of circle, AE = be CE = de ∵ AC = ae-ce, BD = be-ed
In the circle O with radius of 50 mm, chord AB is 50 mm long. Calculate the degree of ∠ AOB and calculate the distance from point O to ab
AB=R
OA=R
OB=R
It is an equilateral triangle
The degree of ∠ AOB = 60 °
The distance from point O to AB is
Rcos(60°/2)=√3R/2=25√3
If the chord length of the central angle of a circle of 1 radian is equal to 2, then the arc length of the central angle of the circle is equal to? A.sin1/2 B.π/6 C.1/(sin1/2) D.2sin1/2
Find R: sin (1 / 2) = AB / 2R = 1 / R, then r = 1 / sin (1 / 2), and L = R * 1 = r = 1 / sin (1 / 2), so choose C
If the chord length of the central angle of a circle of 1 radian is equal to 2, then the arc length of the central angle of a circle is equal to () A. sin1 Two B. π Six C. 1 sin1 Two D. 2sin1 Two
Let the radius of the circle be r
2=1，
∴r=1
sin1
2，
The arc length L = α· r = 1
sin1
2．
Therefore, C is selected
If the arc length of the central angle of 1 radian is equal to 2, then the chord length of the central angle of the circle is equal to?
According to the definition of radian, we can know that the radius of the circle is 2,1rad, and the angle is about 57 ° 17'44. Check the sine value of half of it, and the chord length = radius x sine value x2
If the chord length of the central angle of 1 radian is 2, then the arc length of the central angle of 1 arc is () A. 1 sin0.5 B. sin0.5 C. 2sin0.5 D. tab0.5
Connecting the center of a circle and the midpoint of a chord, a right triangle is formed by the distance between chord centers, half of the chord length and radius, and the half chord length is 1,
Its center angle is 0.5
So the radius is 1
sin0.5
The arc length to which the central angle of the circle corresponds is 1 × 1
sin0.5=1
sin0.5
Therefore, a
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