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There are 48 students in class 61, including 25 boys. What percentage of the class are boys? What about girls?
Male 25 / 48 female 23 / 48
How to simplify (sin50 ° * cos50 °) / (cos60 ° * cos10 °)
Original formula = 1 / 2 * (2sinx50cos50) / (1 / 2 * cos10)
=sin100/cos10
=sin(90+10)/cos10
=cos10/cos10
=1
cos60 = 0.5
sin50cos50=0.5sin100=0.5cos10
Get by substitution
The original formula is 1
There are 28 boys and 23 girls in class 2 of grade 5. What's the number of boys? What's the number of girls?
What's the percentage of girls in the class?
The number of boys is 28 / 23 of that of girls
The number of girls is 23 out of 28 of boys
The number of girls is 23 out of 51 in the class
（2sin10°+sin50°）÷cos50°
sin10°=sin(60°-50°)=sin60cos50-cos60shin50=√3/2cos50°-1/2sin50°
（2sin10°+sin50°）÷cos50°
=(√3cos50°-sin50°+sin50°）÷cos50°
=√3
There are 28 boys and 16 girls in class 1 of grade 5. What's the percentage of girls? What's the percentage of boys?
Write it on paper and send it
Girls are 4 / 7 of boys and boys are 7 / 11 of the class
What is 50 degrees
one point one nine one seven five three five nine three
There are 23 boys and 25 girls in class one of grade five in a school. What percentage of the class are girls?
25 ÷ (23 + 25), = 25 ÷ 48, = 2548; a: female students account for 2548
What is Tan 50? Why?
About 1.192
There are 48 students in class 5 (1), including 20 boys. What is the proportion of boys in the class? How many times is the number of girls?
The number of boys in the class: 20 △ 48 ≈ 5 / 12
The number of female students is several times that of male students: 48-20 = 28 (people) 28 △ 20 = 1.4
A: Boys account for 5 / 12 of the class, while girls are 1.4 times as many as boys
Tan10 degree + tan50 degree minus root sign 3 times tan10 degree times tan50
tan10º+tan50º+√3tan10ºtan50º
=tan60º (1- tan10ºtan50º)+√3tan10ºtan50º
=√3-√3tan10ºtan50º+√3tan10ºtan50º
=√3
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