The number of girls in class 6 (1) is 80% of that of boys, and the number of boys is more than that of girls () A. 20%B. 25%C. 60%D. 80%

The number of girls in class 6 (1) is 80% of that of boys, and the number of boys is more than that of girls () A. 20%B. 25%C. 60%D. 80%

(1-80%) / 80%, = 20% / 80%, = 25%; a: there are 25% more boys than girls
sin20=cos?cos20=sin
sin20=cos70
cos20=sin70
The number of girls in a class is 80% of that of boys, and boys account for a few percent of the class. The number of boys is () more than that of girls, and the number of boys is ()% of that of girls
The total number of male students is 1, while that of female students is 0.8,
Boys in the class 1 divided by (1 + 0.8) = 5 / 9
More boys than girls (1-0.8) divided by 0.8 = 25%
The number of boys is 1 of girls divided by 0.8 = 125%
Sin20 ° = cos α - cos20 ° = sin α how much is α?
sin20°= cosα = cos70°= cos(-70°)
-cos20°= sinα = -sin70°= sin(-70°)
α = 360°n - 70°
The number of girls in a class is 4 / 5 of the number of boys. What is the ratio of girls to the whole class, and what is the percentage of boys in the whole class
Four out of nine girls
Five out of nine boys
cos(-40')cos20'-sin(-40')sin(-20')
Because y = SiNx is an odd function and y = cosx is an even function, the original formula is: cos40'cos20 '- sin40'sin20'. According to the formula of two corner cosine, this formula = cos (40 '+ 20') = cos60 '= 1 / 2
Zero point five
Original formula = cos40cos20-sin40sin20
=cos(40+20)=cos60=1/2
The ratio of boys to girls in class 1 of grade 6 is 4:5, girls are more than boys (), and boys account for a few percent of the class
11% four out of nine
Sin^2(120º)+cos180º+tan45º-cos^2(-330º)+sin(-210º)=?
Sin ^ 2 is the power of sin
Sin ^ 2 (120 & ordm;) is 120 ° of the second power of sin
It's better to write down the process
sin120=√3/2
cos180=-1
tan45=1
cos(-330)=cos(360-330)=cos30=√3/2
sin(-210)=sin(360-210)sin150=1/2
So the original formula = 3 / 4-1 + 1-3 / 4 + 1 / 2 = 1 / 2
In Grade 6, boys are 15 / 14 of girls, and girls are a fraction of boys. Boys are a fraction of the class. Girls are a fraction of the class
emergency
The number of girls is higher than that of boys
1÷14\15
=1×15\14
=15\14
The number of boys is the same as that of the whole class
14\15÷（14\15+1)
=14\15÷29\15
=14\15×15\29
=14\29
The number of female students is the same as that of the whole class
1÷（14\15+1)
=1÷29\15
=1×15\29
=15\29
A: the number of girls is 15 out of 14 of boys, the number of boys is 29 out of 14 of the class, and the number of girls is 29 out of 15 of the class
I hope my answer can help you,
Given the vector a = (COS θ, sin (10 & ordm; - θ), the vector b = (cos10 & ordm;, cos50 & ordm;), if the vector a is perpendicular to the vector B, then Tan θ is
ab=(cosθ,sin(10º-θ))(cos10º,cos50º)=cosθcos10º+sin(10º-θ)cos50º=cosθcos10º+sin(10º-θ)sin40º=0cosθ+sin(10º-θ)sin40º/cos10º=0cosθ+(si...