Five seventh of class 61 is equal to four seventh of class 62, and the number of class 61 is several percent less than that of class 62

Five seventh of class 61 is equal to four seventh of class 62, and the number of class 61 is several percent less than that of class 62

The number of class 61 is x, and the number of class 62 is y
Then 5 / 7 * x = 4 / 7 * y
So x / y = 4 / 5
X=4/5*Y
Therefore, the number of class 61 is 1 / 5 less than that of class 62, that is, 20%
[(5/7)*(7/4)-1]/[(5/7)*(7/5)]=20%
If the number of class 61 is x and the number of class 62 is y, then 5x = 4Y
We can get x = 4 / 5Y, that is, (Y-X) / y = 0.2
The number of class 61 is 20% less than that of class 62.
If AB > 0 and a (a, 0), B (0, b), C (- 2, - 2) are collinear, the minimum value of AB is obtained
∵ a, B and C are collinear, ∵ KAB = KAC, that is, B − 00 − a = − 2 − 0 − 2 − a, ∵ 1A + 1b = - 12, ∵ 12 = | 1A + 1b | = | 1a | + | 1b | ≥ 2Ab (take the equal sign when a = b), ∵ ab ≥ 4, ab ≥ 16ab minimum value is: 16
The number of class 61 is 11 / 10 of that of class 62. How much more is the number of class 61 than that of class 62?
In order to calculate the formula, it is better not to use the equation o (> ﹏)
（11-10）÷10=10%
10%
10% more
9%
① Tan (π / 4 + a) = 1 / 2 find the value of Tan a. ② (sin2a-2cos ＾ 2a) / 1 + Tan a?
tan(A+B)=(tan A+tan B)/(1-tan A* tan B)
So tan a = - 1 / 3
2cos ＾ 2A what is this?
The number of class 61 is 25% more than that of class 62. What percentage of the number of class 62 is that of class 61?
1÷（1+25%）=80%
1÷（1+25%）=80%
I really can't solve the problem of trigonometric number in senior one!
I seem to have forgotten this question. I seem to have said this. I told the three sides of the triangle a = what x, B = what x, C = what X. I asked if it is an obtuse triangle X's value range, if it is an acute triangle X's value range? I also forgot what the specific question is. I only listen to others once, If someone else has a question similar to this question or knows the original question of this question, I hope to provide the question and answer. I don't know how to thank you, so I have to send 50 points to show my gratitude
Let x.x + 1 and X + 2 be the lengths of the three sides of an obtuse triangle to find the value range of the real number X?
Because x.x + 1 and X + 2 are the three sides of an obtuse triangle, x + X + 1 is greater than x + 2, and X + 2 - (x + 1) is less than x. the solution is that x is greater than 1, which is right, but we also need to explain the square of the inequality x + (x + 1) of an obtuse triangle
There are 55 students in class 61 and 57 students in class 62
Now there are 49 people in class one: (55 + 57) / (7 + 9) × 7
So we need to drop: 55-49 = 6 people to class 2
If you don't understand, you can ask
If you have any help, please remember to adopt it. Thank you
Sin1 is sin1 degree or sin1 degree
You have made a conceptual mistake. π = 180 ° sin1 does not mean sin1, but sin (180 / π) °, sin1 ° is sin1
It should be one radian, which means 180 ° g π is about 56 degrees
This way of expression is expressed in radians, 1 radian is about 57 degrees, so you can know
The number of people in class 61 is one fifth more than that in class 62. Unit 1 here is (). What is the proportion of class 61 in class 62?
five-fourths
Sin1 and sin1? Which is bigger? Why?
Sin1 is expressed in radians
For example, sin Π = sin (3.1415926) = sin 180
sin1=sin57.3°＞sin1°
Sin1 is big, because the front is radian, you can know that radian 1 = 53 degrees, and sin is between 0 and 90 degrees. The bigger the degree is, the bigger it is. So the former is big
One degree corresponds to a radian of π / 180
Because 0