What is nine fourths plus one sixth?

What is nine fourths plus one sixth?

9/40+1/6= 27/120 + 20/120 = 47/120
=47/120
47/120？
forty-seven-120ths
47 out of 120
First simplify, then evaluate: m − 4m2 − 9 · (1 + 14m − 7m2 − 8m + 16) △ 1m − 3, where M = 5
The original formula = m − 4 (M + 3) (m − 3) · (M + 3) (m − 4) 2 △ 1m − 3 = m + 3 (m − 3) (m − 4) · m − 31 = m + 3M − 4; when m = 5, the original formula = 8
The ratio of boys to girls is 5; 4, boys are several times more than girls, and girls account for several times of the total number of students
The first question: it means that there are more boys than girls, which is a fraction of girls
What percentage of the total number of students are girls? The answer is four out of nine
First simplify, then evaluate: 4m − 3 − 2m − 6m2 − 6m + 9, where M = 7
4m − 3-2m − 6m2 − 6m + 9 = 4m − 3-2 (m − 3) (m − 3) 2 = 4m − 3-2m − 3 = 2m − 3; when m = 7, the original formula = 27 − 3 = 12
The number of boys is 8 / 7 of the number of girls, the number of boys is a fraction of the total number of students, and the number of girls is a fraction of the total number?
The number of boys is 8 / 15 of the total number of students, and the number of girls is 7 / 15 of the total number of students in the class
Simplification and evaluation: 5 (3a-b) - 4 (- A + 3b) = what
5（3a-b)-4(-a+3b)
=15a-5b+4a-12b
=19a-17b
Original formula = 15a-5b + 4a-12b
=19a-17b
5（3a-b)-4(-a+3b)=15a-5b+4a-12b=19a-17b
5（3a-b)-4(-a+3b)=15a-5b+4a-12b=19a-17b
5（3a-b)-4(-a+3b)
=15a-5b+4a-12b
=19a-17b
There are 630 students in the school, and girls account for 4 / 9 of the total number. How many boys are there in the school?
Girls account for 4 / 9 of the total, so boys should account for 5 / 9, so 630 * 5 / 9 = 350
If the result of (a + m) (a + 12) does not contain the linear term of a, then the value of M is ()
A. 2B. -2C. 12D. -12
∵ (a + m) (a + 12) = A2 + (M + 12) a + 12 · m, and ∵ does not contain a linear term about the letter A, ∵ m + 12 = 0, ∵ M = - 12
The number of male students in a school is one fifth more than that of female students
2:3
3/5
Given the quadratic power of (M-3) + N + 2 = 0, find - 3
The second power of (M-3) + N + 2 = 0
m-3=0,n+2=0
m=3,n=-2
Substituting - 3
The second power of (M-3) + N + 2 = 0
m-3=n+2=0
m=3,n=-2
So - 3