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There are 20 boys in class 6 (1). The ratio of boys to girls is 4:5. How many fewer boys are than girls, and what percentage of girls are in the class? 2. The product of a number multiplied by its reciprocal is 3, and its reciprocal is () 3, the subtracted is 360, the ratio of difference to subtraction is 2:3, the subtraction is (), and the difference is () 4. The perimeter of a square is 8 / 9 meters, and its area is () m2 5. If the number a is 1 and 1 / 4 times of the number B, and the number B is 3 / 5 of the number C, then the number a is ()
5/9
1/2
The subtraction is 216 and the difference is 144
4/9
3/4
I hope my answer can help you
Let a = √ 2 / 2 (sin17 degree + cos17 degree), B = 2cos ^ 13 degree - 1, C = √ 3 / 2, then
Compare a, B, C, size
A = √ 2 / 2 (sin17 ° + cos17 °) = sin17 ° cos45 ° + cos17 ° sin45 ° = sin (17 + 45) ° = sin62 ° B = 2 (cos13 °) ^ 2-1 = Cos2 * 13 ° = cos26 ° = cos (90 ° - 64 °) = sin64 ° C = √ 3 / 2 = sin60 ° because SiNx is an increasing function in the first quadrant
What's the percentage of boys in the class? What's the percentage of girls in the class? There are 25 boys and 20 girls in class 6
25÷（25＋20）＝55.6%
20÷（25＋20）＝44.4%
What is sin17 / 2 pie?
Sin17 / 2 faction = sin (8 faction + 1 / 2 faction) = sin (1 / 2 faction) = 1
One
There are 28 boys and 24 girls in class 2 of grade 5. What's the percentage of girls?
24 ÷ 28 = 67 A: the number of female students is 67
It is calculated that 2sin14 ° · cos31 ° + sin17 ° equals ()
A. 22B. -22C. 32D. -32
2sin14 °· cos31 ° + sin17 ° = 2sin14 °· cos31 ° + sin (31 ° - 14 °) = 2sin14 ° cos31 ° - cos31 ° sin14 ° = sin31 ° cos14 ° + cos31 ° sin14 ° = sin (31 ° + 14 °) = sin45 ° = 22
There are 24 boys and 22 girls in class 5 (2). What is the percentage of boys and girls in the class?
22/24=11/12
22/(24+22)=11/23
It is calculated that 2sin14 ° · cos31 ° + sin17 ° equals ()
A. 22B. -22C. 32D. -32
2sin14 °· cos31 ° + sin17 ° = 2sin14 °· cos31 ° + sin (31 ° - 14 °) = 2sin14 ° cos31 ° - cos31 ° sin14 ° = sin31 ° cos14 ° + cos31 ° sin14 ° = sin (31 ° + 14 °) = sin45 ° = 22
The number of boys in the school chorus is 3 / 5 less than that of girls. What's the number of boys? What's the number of girls?
What's the percentage of boys in the chorus?
Boys are two fifths of girls. Girls are two and a half times of boys
Simplification, evaluation: M2-1 / m2-2m + 1 △ (m-1-m + 1 / m-1), where M = √ 3
m2-1/m2-2m+1÷(m-1-m+1/m-1)
=(m-1)(m+1)/(m-1)² ÷[(m-1)²-(m+1)]/(m-1)
=(m+1)/(m²-2m+1-m-1)
=(m+1)/(m²-3m)
=(√3+1)/(3-3√3)
=-1/3×(√3+1)²/2
=-(4+2√3)/6
=-(2+√3)/3
m2-1/m2-2m+1÷(m-1-m+1/m-1)
=(m-1)(m+1)/(m-1)²÷((m-1)²-m-1)/(m-1)
=(m+1)/(m-1)×(m-1)/(m²-3m)
=(m+1)/(m²-3m)
=(√3+1)/(3-3√3)
=1/3 *(√3+1)/(1-√3)
=-1/3*(4+2√3)/2
=-(2+√3)/3
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