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2a+b>CD中線>b 設三角形第三遍為c,因為三角形兩邊之和大於第三邊,兩邊之差小於第三邊,所以a+b>c>a-b 因為a>b,設中線CD長為x 中點D有a+(a+b)/2>x>a-(a+b)/2和b+(a-b)/2>x>b-(a-b)/2 兩式聯立得 2a+b>CD中線>b
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