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遞增數列 a2-a1=3 a3-a2=4 a4-a3=5 …… an-an-1=n+1 把上面的累加起來,可得到 an-a1=3+4+5+……+(n+1)=(n-1)(n+4)/2 所以此數列的運算式為an=[(n-1)(n+4)/2]+1
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