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①當2x-1≥0即x≥12時,不等式化為:x+3>2x-1,解得:x<4,此情况下的解集為:[-12,4);②當2x-1<0即x<12時,不等式化為:x+3>1-2x,解得:x>-23,此情况下的解集為:(-23,12).綜上,原不等式的解集為:[-12,4)∪(-23,12)=(-23,4).故答案為:(-23,4)
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