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15°∵AB=AE=BE∴AE=AD=BE=BC,三角形ADE和三角形BCE為等腰三角形在等邊三角形ABE中,角AEB=角EAB=角EBA=60°∵角EBC=90°-角EBA=30°同理可得角EAD=30°∴三角形ADE和三角形BCE為全等等腰三角形且角AED=角BEC=(180°-…
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